Motion

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12 Terms

1
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A tennis ball is hit horizontally and travels to a wall 10 metres away. Upon hitting the wall, the ball bounces back to its starting position. Calculate:

a) the horizontal distance travelled by the tennis ball
b) the horizontal displacement of the tennis ball

a.) Distance= 20m

b.) Displacement= 0m

2
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A formula one car travels a displacement of +500 metres on a test circuit. It then reverses in the opposite direction for 800 metres.

Calculate the displacement of the car from the start position to its end position.

-300m

Displacement is a vector and therefore direction matters.

The 800m should therefore be regarded as negative.

+500-800= - 300m

3
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Define the term speed

rate of change of distance per unit time.

4
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Define the term displacement

shortest straight line distance and direction from an object’s starting point to its ending point, ignoring the path taken.

5
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Define the term velocity

rate of change of displacement per unit time.

6
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How to calculate average speed and average velocity ?

Average speed = total distance travelled / total time taken

Average velocity = total displacement / total time taken

7
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Define the term acceleration

rate of change of velocity per unit time.

8
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Define rate of change

Change in a quantity relative to another quantity

9
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The gradient of a speed time graph =

The gradient of a velocity time graph =

The magnitude of acceleration (You’re not accounting for whether the object is speeding up in a forward or backward direction.)

The acceleration as a vector.

10
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Define the term Instantaneous Speed

rate of change of distance a given instant.

11
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Jack throws a ball upwards and catches it again. The acceleration is constant and (-), sketch the velocity time graph.

Velocity is (+) going up and (-) coming down.

<p><strong>Velocity </strong>is (<strong>+</strong>) going <strong>up </strong>and (<strong>-</strong>)  coming <strong>down.</strong></p>
12
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