IB Chem: Topic 3

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58 Terms

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Modern Periodic Law
When elements are arranged in order of increasing atomic number, their properties shoow a periodic recurrence and gradual change
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Periodic Recurrence (Periodicity)
Elements in the same groups have similar properties
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Gradual change
The properties of elements gradually change as you move down a group or across a period (trends)
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Physical Properties
Description of a substance that does not involve changing its chemical composition
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Chemical Properties
Description of how a substance behaves as its chemical composition is changed
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Nuclear Charge
total positive charge in the nucleus (number of protons)
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Shielding Effect, ShE
The interference between the attraction of the nucleus and valence electrons. It is provided by core electrons and the distance between the nucleus and Ve- (# E-levels)
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Effective Nuclear Charge, Zeff
The net force of attraction experienced by Ve- of the nucleus (Z-Ce-)
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Zeff _____ across a period because…
increases, the number of shielding electrons remain the same while the magnitude of positive charge in the nucleus increases
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Zeff _____ down a group because…
remains constant, the magnitude of positive charge in the nucleus and the number of shielding electrons increase proportionally
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ShE _____ across a period because…
remains relatively constant, the number of shielding electrons and energy levels do not change
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ShE ______ down a group because…
increases, there is an increase in the # of shielding electrons
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Atomic radius ______ across a period because…
decreases, Zeff increases due to additional p+, but the distance over which it has to act and the # of Ce- remains relatively constant. Therefore an increase in attraction b/n the nucleus and Ve- leads to a decrease in atomic radius.
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Atomic radius _____ down a group because…
increases, # of E levels increase down a group resulting in an increase in the distance b/n nucleus and Ve-. Zeff remains constant, while ShE (Ce- + E levels) increases.
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Cations have a _____ radius than their parent atom because…
smaller, the loss of an energy level decreases the number of shielding electrons therefore the positive charge of the nucleus has to act over a short distance to attract Ve-
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Anions have a _____ radius than their parent atom because…
larger, the extra Ve- contribute to e-e repulsion, therefore taking up more space.
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Atomic radius

half the distance between neighbouring atoms’ nuclei.

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First Ionization Energy
the energy required to remove one mole of electrons from one mole of gaseous atoms
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Electronegativity
The measure of the attraction of an atom for a pair of bonding electrons.
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Electron Affinity
The energy change (+ or -) when one mole of electrons is added to one mole of gaseous atoms to form one mole of gaseous ions.
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Ionization Energy _____ down a group because…
Decreases, Ve- are less attracted to the nucleus due to an increase in ShE; meaning there is a greater distance b/n the nucleus and the Ve’ while Zeff remains constant.
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Ionization Energy _____ across a period because…
increases, the attraction to the nucleus increases across a period because zeff increases while ShE remains constant'; means there is a greater magnitude of positive charge in the nucleus acting over the same distance, making the attraction stronger therefore requiring more energy to remove Ve-
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Ionization energy exceptions - Group 2 → Group 13
Removing the Ve- from group 13 elements requires less energy because it is in the p subshell, whereas group 2 element Ve- are in the s subshell (the p subshell is further from the nucleus).
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Ionization energy exceptions - Group 15 → Group 16
It requires less E to remove a Ve- from a paired e- than a singly occupied orbital because of added e-e repulsion. Therefore it is easier to remove the first Ve- from group 16 than 15.
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General EN trends on PT

Follows same trends as IE: decreases down a group due to increased ShE and constant Zeff, increases across a period due to increased Zeff and constant ShE

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Ionization Energy vs Electronegativity
* IE can be measured directly and is a property of only gaseous atoms.
* EN is a property of an atom in a molecule or FU and its values are assigned/derived indirectly from experimental bond energy data.
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General trends in mp across period 3

Metallic bonds increase in strength (increasing mp) → network covalent solids (highest mp) → molecular compounds decrease in size LDFs decrease in strength (decreasing mp)

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A negative e-A value means…
the change in energy is exothermic and the atom has a HIGH e-A
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A positive e-A value means…
the change in energy is endothermic and the atom has a LOW e-A
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Units of e-A
kJmol^-1
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e-A _____ across a period because…
increases, higher Zeff and a constant ShE result in a greater attraction for an additional e-
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e-A ______ down a group because…
decreases, Zeff remains constant while ShE increases resulting in a decreased attraction for Ve-. Therefore energy is required (endothermic) to add additional e-.
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e-A trend exceptions: Group 15
The group 15 elements have a half-full p-subshell, which has more stability than the e- configurations of group 14 and 16 elements. Therefore its e-A is decreased
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e-A trend exceptions: Group 2
The group 2 elements have a full s subshell, which is more energetically favourable than adding an electron to the unoccupied p subshell.
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The strength of metallic bonds is influenced by

the magnitude of positive charge in the central ions (Zeff vs ShE) and the number of delocalized e- surrounding them. Also the ionic radius of the positive ions (kernels)

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Theory of reactivity
Atoms will lose, gain or share valence e- to become isoelectronic with the nearest noble gas (ie. obtain a stable octet/full s and p subshells)
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Monatomic molecules

molecules formed form one atom, formed by unreactive elements

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Reactivity of Alkali Metals ______ down a group because…
increases, the attraction of group 1 atoms to their Ve- decreases dramatically down a group due to unchanging Zeff and increasing ShE
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Reactivity of Halogens ________ down a group because…
decreases, halogens form anions in ionic bonds, so as the hold on e- decreases down a group due to increased ShE and constant Zeff, the reactivity decreases as well
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Alkali metal + H2O reaction
2M(s) + 2H2O(l) → H2(g) + 2MOH(aq)

alkali metal + water → hydrogen gas + alkali metal hydroxide
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Silver Halide Reaction
2Ag(s) + X2 (g/l/s) → 2AgX(s)

silver + halogen → silver halide precipitate
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Metal Halide Reaction
2M(s) + X2(s/l/g) → 2MX

alkali metal + halogen → alkali metal halide
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Halogen displacement reaction
a MORE REACTIVE halogen (X) will displace a LESS REACTIVE halide ion (x) in a single displacement reaction

X2(s/l/g) + 2Mx(aq) → 2MX(aq) + x2(s/l/g)
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Colour change when Br2 is replaced by Cl2 in a halide displacement reaction
CLEAR → ORANGE
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Colour change when I2 is replaced by Br2 in a halide displacement reaction
COLOUR DARKENS, Turns purple when mixed with a hydrocarbon
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Metallic character _____ across a period because…
decreases, metallic properties can be explained by loosely held Ve- and the underlying d-subshell e-
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Metallic character _____ down a group because…
increases, metallic properties can be explained by loosely held Ve- and the underlying d-subshell e-
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Period 3 Oxides trend in pH
basic (metals) → amphoteric (Al2O3) → acidic (non-metals)
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Period 3 Oxides trend in ionic character
decreases across, difference in EN decreases
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Example of a measure of ionic character
electrical conductivity
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Amphoteric
can behave as an acid or base depending on what it is reacting with
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Rxn of Basic Oxides and Water
Na2O(s) + H2O(l) → 2NaOH (aq)

basic oxide + water → metal hydroxide
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Rxn of Basic Oxides and an Acid
Na2O(s) + 2HCl(aq) → H20(l) + 2NaCl(aq)

basic oxide + acid → water + salt

double displacement neutralization
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Amphoteric Oxides Rxn /w H2O
DOES NOT REACT
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Rxn of Amphoteric Oxides and an Acid
Al2O3(s) + 6HCl(aq) → 3H2O(l) + 2AlCl3(aq)

amphoteric oxide + acid → water + salt
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Rxn of Amphoteric Oxides and a Base
Al2O3(s) + 2NaOH(aq) + 3H2O(l) → 2NaAl(OH)4(aq)

amphoteric oxide + base + water → sodium tetrahydroxoaluminate
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Rxn of an Acidic Oxide with H2O
P4O10(g) + 6H20(l) → 4H3PO4

acidic oxide + water → acidic solution
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Rxn of an Acidic Oxide with a Base
P4H10(g) + 12NaOH(aq) → 6H2O(l) + 4Na3PO4(aq)

acidic oxide + base → water + salt

Double displacement neutralization