IB Chem: Topic 3

studied byStudied by 4 people
0.0(0)
learn
LearnA personalized and smart learning plan
exam
Practice TestTake a test on your terms and definitions
spaced repetition
Spaced RepetitionScientifically backed study method
heart puzzle
Matching GameHow quick can you match all your cards?
flashcards
FlashcardsStudy terms and definitions

1 / 57

flashcard set

Earn XP

Description and Tags

58 Terms

1
Modern Periodic Law
When elements are arranged in order of increasing atomic number, their properties shoow a periodic recurrence and gradual change
New cards
2
Periodic Recurrence (Periodicity)
Elements in the same groups have similar properties
New cards
3
Gradual change
The properties of elements gradually change as you move down a group or across a period (trends)
New cards
4
Physical Properties
Description of a substance that does not involve changing its chemical composition
New cards
5
Chemical Properties
Description of how a substance behaves as its chemical composition is changed
New cards
6
Nuclear Charge
total positive charge in the nucleus (number of protons)
New cards
7
Shielding Effect, ShE
The interference between the attraction of the nucleus and valence electrons. It is provided by core electrons and the distance between the nucleus and Ve- (# E-levels)
New cards
8
Effective Nuclear Charge, Zeff
The net force of attraction experienced by Ve- of the nucleus (Z-Ce-)
New cards
9
Zeff _____ across a period because…
increases, the number of shielding electrons remain the same while the magnitude of positive charge in the nucleus increases
New cards
10
Zeff _____ down a group because…
remains constant, the magnitude of positive charge in the nucleus and the number of shielding electrons increase proportionally
New cards
11
ShE _____ across a period because…
remains relatively constant, the number of shielding electrons and energy levels do not change
New cards
12
ShE ______ down a group because…
increases, there is an increase in the # of shielding electrons
New cards
13
Atomic radius ______ across a period because…
decreases, Zeff increases due to additional p+, but the distance over which it has to act and the # of Ce- remains relatively constant. Therefore an increase in attraction b/n the nucleus and Ve- leads to a decrease in atomic radius.
New cards
14
Atomic radius _____ down a group because…
increases, # of E levels increase down a group resulting in an increase in the distance b/n nucleus and Ve-. Zeff remains constant, while ShE (Ce- + E levels) increases.
New cards
15
Cations have a _____ radius than their parent atom because…
smaller, the loss of an energy level decreases the number of shielding electrons therefore the positive charge of the nucleus has to act over a short distance to attract Ve-
New cards
16
Anions have a _____ radius than their parent atom because…
larger, the extra Ve- contribute to e-e repulsion, therefore taking up more space.
New cards
17

Atomic radius

half the distance between neighbouring atoms’ nuclei.

New cards
18
First Ionization Energy
the energy required to remove one mole of electrons from one mole of gaseous atoms
New cards
19
Electronegativity
The measure of the attraction of an atom for a pair of bonding electrons.
New cards
20
Electron Affinity
The energy change (+ or -) when one mole of electrons is added to one mole of gaseous atoms to form one mole of gaseous ions.
New cards
21
Ionization Energy _____ down a group because…
Decreases, Ve- are less attracted to the nucleus due to an increase in ShE; meaning there is a greater distance b/n the nucleus and the Ve’ while Zeff remains constant.
New cards
22
Ionization Energy _____ across a period because…
increases, the attraction to the nucleus increases across a period because zeff increases while ShE remains constant'; means there is a greater magnitude of positive charge in the nucleus acting over the same distance, making the attraction stronger therefore requiring more energy to remove Ve-
New cards
23
Ionization energy exceptions - Group 2 → Group 13
Removing the Ve- from group 13 elements requires less energy because it is in the p subshell, whereas group 2 element Ve- are in the s subshell (the p subshell is further from the nucleus).
New cards
24
Ionization energy exceptions - Group 15 → Group 16
It requires less E to remove a Ve- from a paired e- than a singly occupied orbital because of added e-e repulsion. Therefore it is easier to remove the first Ve- from group 16 than 15.
New cards
25

General EN trends on PT

Follows same trends as IE: decreases down a group due to increased ShE and constant Zeff, increases across a period due to increased Zeff and constant ShE

New cards
26
Ionization Energy vs Electronegativity
  • IE can be measured directly and is a property of only gaseous atoms.

  • EN is a property of an atom in a molecule or FU and its values are assigned/derived indirectly from experimental bond energy data.

New cards
27

General trends in mp across period 3

Metallic bonds increase in strength (increasing mp) → network covalent solids (highest mp) → molecular compounds decrease in size LDFs decrease in strength (decreasing mp)

New cards
28
A negative e-A value means…
the change in energy is exothermic and the atom has a HIGH e-A
New cards
29
A positive e-A value means…
the change in energy is endothermic and the atom has a LOW e-A
New cards
30
Units of e-A
kJmol^-1
New cards
31
e-A _____ across a period because…
increases, higher Zeff and a constant ShE result in a greater attraction for an additional e-
New cards
32
e-A ______ down a group because…
decreases, Zeff remains constant while ShE increases resulting in a decreased attraction for Ve-. Therefore energy is required (endothermic) to add additional e-.
New cards
33
e-A trend exceptions: Group 15
The group 15 elements have a half-full p-subshell, which has more stability than the e- configurations of group 14 and 16 elements. Therefore its e-A is decreased
New cards
34
e-A trend exceptions: Group 2
The group 2 elements have a full s subshell, which is more energetically favourable than adding an electron to the unoccupied p subshell.
New cards
35

The strength of metallic bonds is influenced by

the magnitude of positive charge in the central ions (Zeff vs ShE) and the number of delocalized e- surrounding them. Also the ionic radius of the positive ions (kernels)

New cards
36
Theory of reactivity
Atoms will lose, gain or share valence e- to become isoelectronic with the nearest noble gas (ie. obtain a stable octet/full s and p subshells)
New cards
37

Monatomic molecules

molecules formed form one atom, formed by unreactive elements

New cards
38
Reactivity of Alkali Metals ______ down a group because…
increases, the attraction of group 1 atoms to their Ve- decreases dramatically down a group due to unchanging Zeff and increasing ShE
New cards
39
Reactivity of Halogens ________ down a group because…
decreases, halogens form anions in ionic bonds, so as the hold on e- decreases down a group due to increased ShE and constant Zeff, the reactivity decreases as well
New cards
40
Alkali metal + H2O reaction
2M(s) + 2H2O(l) → H2(g) + 2MOH(aq)

alkali metal + water → hydrogen gas + alkali metal hydroxide
New cards
41
Silver Halide Reaction
2Ag(s) + X2 (g/l/s) → 2AgX(s)

silver + halogen → silver halide precipitate
New cards
42
Metal Halide Reaction
2M(s) + X2(s/l/g) → 2MX

alkali metal + halogen → alkali metal halide
New cards
43
Halogen displacement reaction
a MORE REACTIVE halogen (X) will displace a LESS REACTIVE halide ion (x) in a single displacement reaction

X2(s/l/g) + 2Mx(aq) → 2MX(aq) + x2(s/l/g)
New cards
44
Colour change when Br2 is replaced by Cl2 in a halide displacement reaction
CLEAR → ORANGE
New cards
45
Colour change when I2 is replaced by Br2 in a halide displacement reaction
COLOUR DARKENS, Turns purple when mixed with a hydrocarbon
New cards
46
Metallic character _____ across a period because…
decreases, metallic properties can be explained by loosely held Ve- and the underlying d-subshell e-
New cards
47
Metallic character _____ down a group because…
increases, metallic properties can be explained by loosely held Ve- and the underlying d-subshell e-
New cards
48
Period 3 Oxides trend in pH
basic (metals) → amphoteric (Al2O3) → acidic (non-metals)
New cards
49
Period 3 Oxides trend in ionic character
decreases across, difference in EN decreases
New cards
50
Example of a measure of ionic character
electrical conductivity
New cards
51
Amphoteric
can behave as an acid or base depending on what it is reacting with
New cards
52
Rxn of Basic Oxides and Water
Na2O(s) + H2O(l) → 2NaOH (aq)

basic oxide + water → metal hydroxide
New cards
53
Rxn of Basic Oxides and an Acid
Na2O(s) + 2HCl(aq) → H20(l) + 2NaCl(aq)

basic oxide + acid → water + salt

double displacement neutralization
New cards
54
Amphoteric Oxides Rxn /w H2O
DOES NOT REACT
New cards
55
Rxn of Amphoteric Oxides and an Acid
Al2O3(s) + 6HCl(aq) → 3H2O(l) + 2AlCl3(aq)

amphoteric oxide + acid → water + salt
New cards
56
Rxn of Amphoteric Oxides and a Base
Al2O3(s) + 2NaOH(aq) + 3H2O(l) → 2NaAl(OH)4(aq)

amphoteric oxide + base + water → sodium tetrahydroxoaluminate
New cards
57
Rxn of an Acidic Oxide with H2O
P4O10(g) + 6H20(l) → 4H3PO4

acidic oxide + water → acidic solution
New cards
58
Rxn of an Acidic Oxide with a Base
P4H10(g) + 12NaOH(aq) → 6H2O(l) + 4Na3PO4(aq)

acidic oxide + base → water + salt

Double displacement neutralization
New cards
robot