Directional Fields, Euler's Methods, Applications of Diff Eqns

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21 Terms

1
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for every differential eqn, there is a

infinite amount of “solns” to the differential eqn

  • therefore, there is generally a FAMILY of solns that have a general form

  • ex: f’(x) = 2*f(x) or y’ = 2y, the soln can be any soln of the form y = ce^(2x) for every c that’s a real num

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directional field for the differential eqn y’ = 2*y (example)

  • two solns of a diff eqn NEVER INTERSECT

  • observe that the lim of y(x) as x → infy = infy IF y(0) > 0 (all the solns above the x-axis)

  • and the lim of y(x) as x → infy = -infy IF y(0) < 0 (all the solns below the x-axis)

  • each soln has their own unique initial condition of y(0)

<ul><li><p>two solns of a diff eqn NEVER INTERSECT</p></li><li><p>observe that the lim of y(x) as x → infy = infy IF y(0) &gt; 0 (all the solns above the x-axis)</p></li><li><p>and the lim of y(x) as x → infy = -infy IF y(0) &lt; 0 (all the solns below the x-axis)</p></li><li><p>each soln has their own unique initial condition of y(0)</p></li></ul><p></p>
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directional field

a graph of some solutions of the given diff eqn

  • using arrows, draw the soln curves that start from their own unique initial condition y(0) (x = 0, y(0))

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equilibrium soln

in the example in the image (y’ = 2y), the soln y(x) = 0 because the fn is a constant value (yields a horizontal line)

<p>in the example in the image (y’ = 2y), the soln y(x) = 0 because the fn is a constant value (yields a horizontal line)</p>
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procedure of drawing a directional field

<p></p>
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euler’s method concept

  • a numerical method for finding explicit/implicit solns that works for almost all diff eqns

  • uses the tangent at certain pts and you keep shifting the x-val until you find the estimated path of the soln/you can approximate the output value from the soln fn at some given x-pt

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formulas for euler’s method

x0 = “prev” x-val or start x-val

y0 = “prev” y-val or start y-val

x1 = “next/current” x-val

y1 = “next/current” y-val

h = the “small step”, constant val, usually given to you, the amount the x-val is “shifted” each step

f(x0, y0) = the tangent/slope at the “prev” coord (x0, y0)

**f(x,y) = dy/dx

<p>x0 = “prev” x-val or start x-val</p><p>y0 = “prev” y-val or start y-val</p><p>x1 = “next/current” x-val</p><p>y1 = “next/current” y-val</p><p>h = the “small step”, constant val, usually given to you, the amount the x-val is “shifted” each step</p><p>f(x0, y0) = the tangent/slope at the “prev” coord (x0, y0)</p><p>**f(x,y) = dy/dx </p>
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method for euler’s method

  • the goal is that when you are given a diff eqn (y’), you must approximate y(x) for some given x pt

<ul><li><p>the goal is that when you are given a diff eqn (y’), you must approximate y(x) for some given x pt</p></li></ul><p></p>
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exponential growth basics

  • a fn that maps out how quantities grow or decay at a rate proportional to their size

  • a quantity y that grows/decays at a rate proportional to its size fits w the eqn of the form:

  • dy/dx = ky (the RATE = constant * quantity, where quantity abides by its own growth/decay eqn)

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exponential growth: dy/dx = ky, if k < 0:

  • eqn is called the LAW OF NATURAL DECAY

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exponential growth: dy/dx = ky, if k > 0:

  • the eqn is called the LAW OF NATURAL GROWTH

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exponential growth: dy/dx = ky, general form of the solution:

y = ce^(kx) for some c that’s a real num

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exponential growth: population growth eqn model

dP/dt = kP and P(t) = P(0)*e^(kt) where P(0) is some initial population at some initial time

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exponential growth: radioactive decay model

m(t) = m(0)*e^(k*t)

  • m(t) = mass of the substance at time t

  • m(0) = mass at t = 0

  • k = rate of decay

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half life of a substance

the amount of time required for HALF of the mass of the quantity to decay

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newton’s cooling law

rate of cooking of an obj is proportional to the temp diff between the OBJ and its SURROUNDINGS provided the temperature diff isn’t super significant

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newton’s cooling law: formulas

dT/dt = k(T - Ts)

dT/dt = ky for y = T - Ts

  • T = temp of object

  • Ts = temp of surroundings

  • t = time

  • k = rate of cooling

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newton’s cooling law: formulas cont’d

T(t) = temp of the obj after t minutes

y = T - Ts

y(0) = T(0) - Ts (Ts is a constant val)

and y(t) = y(0)*e^(kt) = k(T(0) - Ts)

y(t) = T(t) - Ts

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continuously compounded interest: formulas

A = A(0)*(1 + r/n)^(nt)

A(0) = initial amount of money invested

r = interest rate

t = number of years

n = the amount of times the interest rate is compounded per year

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continuously compounded interest: formulas 2

A = A(0)*(1 + r/n)^(nt)

r/n = in each compounding period, the rate is r/n

nt = compounding periods in t years

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continuously compounded interest: formulas 3 (the most important)

A(t) = A(0)*e^(rt)

therefore, dA/dt = rA(0)e^(rt) = r*A(t) (which is the above line)