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Aluminum a
24J/mol K x 1 mol x 635 K = 15kJ
15kJ + 10.7 kJ = 25.7 kJ
Aluminum b
1675kJ/mol x 1 mol/2 mol Al = 837.5 kJ
Recycling takes less energy
Beaker of sand a
241 kJ
Beaker of sand b
Subtract masses and get 7.06g
7.06 g x 1 mol/58.12 g = 0.121 mol
Beaker of sand c
0.121 mols x -2659 kJ/1 mol = -322 kJ released
Beaker of sand d
Yes the my answers support the students claim because the theortical yield from part c should be equal to the actual yield from a, however the yield of part a was less than the yield of part c
Combustion of c2h4 a
-1412kJ/mol
Energy diagram
Products lower than and delta h is the distance between reactants and products
C2h5oh + 3o2
42 kJ/mol
Bond enthalpies table with missing value d
358 kJ/mol
Predict sign for delta s
Negative bc more moles of gas on reactants which means higher entropy within reactants.