AP Biology - 2020 Practice Exam 1 MCQ

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Humans produce sweat as a cooling mechanism to maintain a stable internal temperature. Which of the following best explains how the properties of water contribute to this physiological process?

  • A: The high specific heat capacity of water allows the body to absorb a large amount of excess heat energy.

  • B: The high heat of vaporization of water allows the body to remove excess heat through a phase change of water from liquid to gas.

  • C: The high surface tension of water contributes to the physical process by which water leaves the body.

  • D: The high melting temperature of water allows the body to remove excess heat through a phase change of water from solid to liquid.

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1

Humans produce sweat as a cooling mechanism to maintain a stable internal temperature. Which of the following best explains how the properties of water contribute to this physiological process?

  • A: The high specific heat capacity of water allows the body to absorb a large amount of excess heat energy.

  • B: The high heat of vaporization of water allows the body to remove excess heat through a phase change of water from liquid to gas.

  • C: The high surface tension of water contributes to the physical process by which water leaves the body.

  • D: The high melting temperature of water allows the body to remove excess heat through a phase change of water from solid to liquid.

B: The high heat of vaporization of water allows the body to remove excess heat through a phase change of water from liquid to gas.

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2

A student placed a semipermeable membrane inside a U-shaped channel with two chambers, as shown. The membrane permits the movement of water but not salt. The student wants to vary the rate of osmosis that occurs across the membrane. Which of the following experimental designs will result in the fastest net rate of water movement into chamber A?

  • A: Placing salt water in chamber A and distilled water in chamber B

  • B: Placing distilled water in both chambers

  • C: Placing distilled water in chamber A and salt water in chamber B

  • D: Placing salt water in both chambers

A: Placing salt water in chamber A and distilled water in chamber B

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3

Which of the following best describes the role of water in photosynthesis?

  • A: Water is the only source of protons for the formation of a proton gradient.

  • B: Water molecules donate electrons to the electron transport chain.

  • C: Water molecules combine with stored carbon molecules to produce glucose.

  • D: Water is the terminal electron acceptor for electrons that pass through the electron transport chain.

B: Water molecules donate electrons to the electron transport chain.

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4

What evolutionary advantage does compartmentalization of core metabolic processes offer eukaryotes?

  • A: Evolution of the mitochondria allowed eukaryotes to perform respiration.

  • B: With the evolution of mitochondria in eukaryotes, the Krebs cycle and electron transport chain also evolved.

  • C: Evolution of a nucleus in eukaryotes separates the processes of transcription and translation and they can be regulated separately.

  • D: A nucleus in bacteria provides separation of respiration from transcription.

C: Evolution of a nucleus in eukaryotes separates the processes of transcription and translation and they can be regulated separately.

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<p><span>Pyruvate dehydrogenase is an enzyme that converts pyruvate to acetyl-CoA. Acetyl-CoA is further metabolized in the Krebs cycle. A researcher measured the accumulation of acetyl-CoA in a reaction containing pyruvate and pyruvate dehydrogenase under several different conditions (Figure 1).</span><br></p><p><span>Figure 1. Accumulation of acetyl-CoA under different conditions</span></p><p><strong><br><u><span>Which of the following best describes the cellular location where pyruvate dehydrogenase is most likely active?</span></u></strong></p><ul><li><p><strong>A: </strong>The Cytosol</p></li><li><p><strong>B: </strong>The lysosomes</p></li><li><p><strong>C: </strong>The nucleus</p></li><li><p><strong>D: </strong><span>The mitochondrial matrix</span></p></li></ul>

Pyruvate dehydrogenase is an enzyme that converts pyruvate to acetyl-CoA. Acetyl-CoA is further metabolized in the Krebs cycle. A researcher measured the accumulation of acetyl-CoA in a reaction containing pyruvate and pyruvate dehydrogenase under several different conditions (Figure 1).

Figure 1. Accumulation of acetyl-CoA under different conditions


Which of the following best describes the cellular location where pyruvate dehydrogenase is most likely active?

  • A: The Cytosol

  • B: The lysosomes

  • C: The nucleus

  • D: The mitochondrial matrix

  • D: The mitochondrial matrix

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<p>Pyruvate dehydrogenase is an enzyme that converts pyruvate to acetyl-CoA. Acetyl-CoA is further metabolized in the Krebs cycle. A researcher measured the accumulation of acetyl-CoA in a reaction containing pyruvate and pyruvate dehydrogenase under several different conditions (Figure 1).</p><p>Figure 1. Accumulation of acetyl-CoA under different conditions</p><p><strong><u><span>The maximum production rate of acetyl-CoA under condition 1 is closest to which of the following?</span></u></strong></p><ul><li><p><strong>A: </strong>1 micromole / sec</p></li><li><p><strong>B: </strong>24 micromole / sec</p></li><li><p><strong>C: </strong>35 micromole / sec</p></li><li><p><strong>D: </strong>65 micromole / sec</p></li></ul>

Pyruvate dehydrogenase is an enzyme that converts pyruvate to acetyl-CoA. Acetyl-CoA is further metabolized in the Krebs cycle. A researcher measured the accumulation of acetyl-CoA in a reaction containing pyruvate and pyruvate dehydrogenase under several different conditions (Figure 1).

Figure 1. Accumulation of acetyl-CoA under different conditions

The maximum production rate of acetyl-CoA under condition 1 is closest to which of the following?

  • A: 1 micromole / sec

  • B: 24 micromole / sec

  • C: 35 micromole / sec

  • D: 65 micromole / sec

A: 1 micromole / sec

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<p>Pyruvate dehydrogenase is an enzyme that converts pyruvate to acetyl-CoA. Acetyl-CoA is further metabolized in the Krebs cycle. A researcher measured the accumulation of acetyl-CoA in a reaction containing pyruvate and pyruvate dehydrogenase under several different conditions (Figure 1).</p><p>Figure 1. Accumulation of acetyl-CoA under different conditions</p><p><strong><u><span>Which of the following observations provides the best evidence that acetyl-CoA negatively regulates pyruvate dehydrogenase activity?</span></u></strong></p><ul><li><p><strong>A: </strong><span>The rate of the pyruvate dehydrogenase–catalyzed reaction is slower in the presence of a higher concentration of acetyl-CoA.</span></p><p></p></li><li><p><strong>B:</strong><span>The gene that encodes pyruvate dehydrogenase is transcribed when excess acetyl-CoA is detected.</span></p><p></p></li><li><p><strong>C: </strong><span>The accumulation of acetyl-CoA stops after 70 seconds, regardless of the reaction mixture.</span></p><p></p></li><li><p><strong>D: </strong>Acetyl-<span>CoA</span> is continuously broken down in the Krebs cycle.z</p></li></ul>

Pyruvate dehydrogenase is an enzyme that converts pyruvate to acetyl-CoA. Acetyl-CoA is further metabolized in the Krebs cycle. A researcher measured the accumulation of acetyl-CoA in a reaction containing pyruvate and pyruvate dehydrogenase under several different conditions (Figure 1).

Figure 1. Accumulation of acetyl-CoA under different conditions

Which of the following observations provides the best evidence that acetyl-CoA negatively regulates pyruvate dehydrogenase activity?

  • A: The rate of the pyruvate dehydrogenase–catalyzed reaction is slower in the presence of a higher concentration of acetyl-CoA.

  • B:The gene that encodes pyruvate dehydrogenase is transcribed when excess acetyl-CoA is detected.

  • C: The accumulation of acetyl-CoA stops after 70 seconds, regardless of the reaction mixture.

  • D: Acetyl-CoA is continuously broken down in the Krebs cycle.z

A: The rate of the pyruvate dehydrogenase–catalyzed reaction is slower in the presence of a higher concentration of acetyl-CoA.

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Pyruvate dehydrogenase is an enzyme that converts pyruvate to acetyl-CoA. Acetyl-CoA is further metabolized in the Krebs cycle. A researcher measured the accumulation of acetyl-CoA in a reaction containing pyruvate and pyruvate dehydrogenase under several different conditions (Figure 1).

Figure 1. Accumulation of acetyl-CoA under different conditions

Pyruvate dehydrogenase deficiency is a genetic disease most commonly linked to a mutation in the 𝛼-subunit of the mitochondrial enzyme that causes the enzyme to cease functioning. As a result of the mutation, affected individuals build up dangerous amounts of lactic acid. Which of the following best explains the buildup of lactic acid in individuals with the mutation?

  • A: Cells use lactic acid to shunt electrons from pyruvate to the electron transport chain in the mitochondria.

  • B: Cells undergo glycolysis because there is a buildup of pyruvate in affected individuals.

  • C: Cells cannot transport pyruvate to the mitochondria in the absence of pyruvate dehydrogenase activity, so the pyruvate is broken down to lactic acid and ethanol.

  • D: Cells undergo fermentation because pyruvate cannot be metabolized to proceed into the Krebs cycle.

D: Cells undergo fermentation because pyruvate cannot be metabolized to proceed into the Krebs cycle.

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<p>The diagram shows how water can adhere to the xylem in the stems of plants, which contributes to water movement in the plant. Which of the following best explains how water is able to move upward from the roots of a plant, through its xylem in the stem, and out to the leaves?</p><p></p><ul><li><p><strong>A: </strong><span>Water is polar, and the walls of the xylem are nonpolar. Water molecules have the ability to form hydrogen bonds with one another but not with the xylem walls.</span><br></p></li><li><p><strong>B: </strong><span>Water is nonpolar, and the walls of the xylem are polar. Water molecules are able to form hydrogen bonds with the xylem walls, and they are pulled up the xylem.</span><br></p></li><li><p><strong>C: </strong><span>Water and the xylem are both nonpolar. Water molecules have the ability to form hydrogen bonds with one another but not with the xylem walls.</span><br></p></li><li><p><strong>D: </strong><span>Water and the xylem are both polar. Water molecules have the ability to form hydrogen bonds with each other and with the walls of the xylem.</span></p></li></ul>

The diagram shows how water can adhere to the xylem in the stems of plants, which contributes to water movement in the plant. Which of the following best explains how water is able to move upward from the roots of a plant, through its xylem in the stem, and out to the leaves?

  • A: Water is polar, and the walls of the xylem are nonpolar. Water molecules have the ability to form hydrogen bonds with one another but not with the xylem walls.

  • B: Water is nonpolar, and the walls of the xylem are polar. Water molecules are able to form hydrogen bonds with the xylem walls, and they are pulled up the xylem.

  • C: Water and the xylem are both nonpolar. Water molecules have the ability to form hydrogen bonds with one another but not with the xylem walls.

  • D: Water and the xylem are both polar. Water molecules have the ability to form hydrogen bonds with each other and with the walls of the xylem.

D: Water and the xylem are both polar. Water molecules have the ability to form hydrogen bonds with each other and with the walls of the xylem.

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<p><span>Protein X activates gene expression only in cells exposed to a specific signaling molecule. In a study, researchers determined the intracellular location of Protein X in cultured cells both before and after exposing the cells to the signaling molecule. The results of the study are shown in the diagram.</span><br><br><strong><u><span>Based on the results, which of the following best describes what Protein X is?</span></u></strong></p><ul><li><p><strong>A: </strong>Protein <span>X</span> is an <span>RNA</span> splicing enzyme.</p><p></p></li><li><p><strong>B: </strong>Protein <span>X</span> is a cell membrane receptor protein.</p><p></p></li><li><p><strong>C: </strong>Protein <span>X</span> is a transcription factor.</p><p></p></li><li><p><strong>D: </strong>Protein X is a hormone.</p></li></ul>

Protein X activates gene expression only in cells exposed to a specific signaling molecule. In a study, researchers determined the intracellular location of Protein X in cultured cells both before and after exposing the cells to the signaling molecule. The results of the study are shown in the diagram.

Based on the results, which of the following best describes what Protein X is?

  • A: Protein X is an RNA splicing enzyme.

  • B: Protein X is a cell membrane receptor protein.

  • C: Protein X is a transcription factor.

  • D: Protein X is a hormone.

C: Protein X is a transcription factor.

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The hormone prolactin has varying effects in many different animal species. All vertebrates produce prolactin, which is involved in signal transduction pathways. In mammals, prolactin stimulates the production of milk in mammary glands. In fish, prolactin plays an important role in osmoregulation. In birds, prolactin is involved in lipid metabolism.

Which of the following best explains the presence of prolactin in various vertebrate species?

  • A: Though all vertebrates produce prolactin, its varied uses indicate it arose as a result of convergent evolution and not as a result of common ancestry.

  • B: Prolactin is a homologous hormone because it has a common origin but different functions in various species.

  • C: Prolactin will bind only to intracellular receptors in animal species with phospholipid bilayers, so its effects are varied in different species.

  • D: Because of different receptors activating different signal transduction pathways within the same species, it is likely that prolactin production is a trait with highly selective pressure.

B: Prolactin is a homologous hormone because it has a common origin but different functions in various species.

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Certain reef-building corals contain photosynthetic, symbiotic algae that have the ability to make dimethylsulphoniopropionate (DMSP), a chemical involved in the marine sulfur cycle. DMSP is released into the surrounding water, where it is converted to the gas dimethyl sulfide (DMS) by microorganisms and enters the atmosphere. Once in the atmosphere, it triggers the formation of sulfate aerosols, which induce cloud formation and block sunlight from heating up the water.

The symbiotic algae produce DMSP when they are stressed by a high water temperature. If water temperature is too high, corals will expel the symbiotic algae that produce DMSP. Researchers measured the amount of DMSP produced by juvenile and adult coral and their symbionts under normal and thermally stressed conditions. The data are shown in the graphs in Figure 1.

The figure presents two line graphs, labeled Juveniles and Adults. Both graphs have two lines with three data points each; one line for an environmental temperature of 27 degrees Celsius and the other for an environmental temperature of 32 degrees Celsius. The graph titled Juveniles has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is labeled D M S P Concentration, in nanomoles per square millimeter, and the numbers 0 through 7, in increments of 1, are indicated. The data points for the line representing 27 degrees Celsius are located at the points 0 comma 2.5 with error bars extending from 2.3 to 2.7; 5 comma 3.0 with error bars extending from 2.8 to 3.2; 10 comma 3.1 with error bars extending from 2.9 to 3.3. The data points for the line representing 32 degrees Celsius are located at the points 0 comma 3.1 with error bars extending from 2.9 to 3.3; 5 comma 4.5 with error bars extending from 4.1 to 4.9; 10 comma 5.5 with error bars extending from 5.3 to 5.7. The graph titled Adults has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is titled D M S P Concentration, in nanomoles per square millimeter, and the numbers 0 through 25, in increments of 5, are indicated.  The data points for the line representing 27 degrees Celsius are located at the points 0 comma 10 with error bars extending from 9 to 11; 5 comma 11 with error bars extending from 10 to 12; 10 comma 12 with error bars extending from 11 to 13. The data points for the line representing 32 degrees Celsius are located at the points 0 comma 14 with error bars extending from 13 to 15; 5 comma 17 with error bars extending from 15 to 19; 10 comma 22 with error bars extending from 21 to 23.

Figure 1: DMSP concentration in juvenile and adult corals and their symbionts in normal and thermally-stressed conditions. Error bars represent ±2SE𝑥¯.

The researchers also measured the density of the symbiont as well as the photosynthetic yield in adult corals at the two temperatures. Photosynthetic yield is an index measure of energy output compared to sunlight energy input in which larger photosynthetic yield values represent photosynthetic organisms producing more energy.

The figure presents a bar graph and a line graph. The bar graph has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is labeled Symbiont Density, per square millimeter, and the numbers 0 through 8000, in increments of 1000, are indicated. Two bars of data each are located at 0 days, 5 days, and 10 days representing the data obtained at environmental temperatures 27 degrees Celsius and 32 degrees Celsius. Each bar contains error bars representing plus or minus 2 times the standard error of the mean. The data represented in the bar graph are as follows. Note that all values are approximate. Data for Time, 0 days. 27 degrees Celsius, 5100 per square millimeter with error bars extending from 4500 to 5500 per square millimeter; 32 degrees Celsius, 5000 per square millimeter with error bars extending from 4200 to 5800 per square millimeter. Data for Time, 5 days. 27 degrees Celsius, 5600 per square millimeter with error bars extending from 5100 to 6100 per square millimeter; 32 degrees Celsius, 4100 per square millimeter  with error bars extending from 3500 to 4700 per square millimeter. Data for Time, 10 days. 27 degrees Celsius, 6000 per square millimeter with error bars extending from 5500 to 6500 per square millimeter; 32 degrees Celsius, 900 per square millimeter with error bars extending from 800 to 1000 per square millimeter. The line graph has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is labeled Photosynthetic Yield, and no values are indicated along it. An arrow head is at the top of the axis. Two lines of data, each with 3 data points, are shown in the graph; one for an environmental temperature of 27 degrees Celsius and the other for an environmental temperature of 32 degrees Celsius. Each data point contains error bars representing plus or minus 2 standard error of the mean. The data represented in the line graph are as follows. The data points for 27 degrees Celsius are located at: 0 days and three quarters of the way up the vertical axis; 5 days and slightly below the height of the first data point; 10 days and slightly above the height of the first data point. The data points for 32 degrees Celsius are located at: 0 days and two thirds of the way up the vertical axis; 5 days and just above the midpoint of the vertical axis; 10 days and one sixth of the way up the vertical axis. None of the error bars around the data points overlap.

Figure 2: Variation in symbiont density and photosynthetic yield in adult corals grown in normal and thermally-stressed conditions. Error bars represent ±2SE𝑥¯.

Which of the following best describes the production of DMSP by coral and coral symbionts?

  • A: A negative feedback mechanism that increases the environmental change

  • B: A negative feedback mechanism that reverses the environmental change

  • C: A positive feedback mechanism that increases the environmental change

  • D: A positive feedback mechanism that reverses the environmental change

B: A negative feedback mechanism that reverses the environmental change

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Certain reef-building corals contain photosynthetic, symbiotic algae that have the ability to make dimethylsulphoniopropionate (DMSP), a chemical involved in the marine sulfur cycle. DMSP is released into the surrounding water, where it is converted to the gas dimethyl sulfide (DMS) by microorganisms and enters the atmosphere. Once in the atmosphere, it triggers the formation of sulfate aerosols, which induce cloud formation and block sunlight from heating up the water.

The symbiotic algae produce DMSP when they are stressed by a high water temperature. If water temperature is too high, corals will expel the symbiotic algae that produce DMSP. Researchers measured the amount of DMSP produced by juvenile and adult coral and their symbionts under normal and thermally stressed conditions. The data are shown in the graphs in Figure 1.

The figure presents two line graphs, labeled Juveniles and Adults. Both graphs have two lines with three data points each; one line for an environmental temperature of 27 degrees Celsius and the other for an environmental temperature of 32 degrees Celsius. The graph titled Juveniles has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is labeled D M S P Concentration, in nanomoles per square millimeter, and the numbers 0 through 7, in increments of 1, are indicated. The data points for the line representing 27 degrees Celsius are located at the points 0 comma 2.5 with error bars extending from 2.3 to 2.7; 5 comma 3.0 with error bars extending from 2.8 to 3.2; 10 comma 3.1 with error bars extending from 2.9 to 3.3. The data points for the line representing 32 degrees Celsius are located at the points 0 comma 3.1 with error bars extending from 2.9 to 3.3; 5 comma 4.5 with error bars extending from 4.1 to 4.9; 10 comma 5.5 with error bars extending from 5.3 to 5.7. The graph titled Adults has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is titled D M S P Concentration, in nanomoles per square millimeter, and the numbers 0 through 25, in increments of 5, are indicated.  The data points for the line representing 27 degrees Celsius are located at the points 0 comma 10 with error bars extending from 9 to 11; 5 comma 11 with error bars extending from 10 to 12; 10 comma 12 with error bars extending from 11 to 13. The data points for the line representing 32 degrees Celsius are located at the points 0 comma 14 with error bars extending from 13 to 15; 5 comma 17 with error bars extending from 15 to 19; 10 comma 22 with error bars extending from 21 to 23.

Figure 1: DMSP concentration in juvenile and adult corals and their symbionts in normal and thermally-stressed conditions. Error bars represent ±2SE𝑥¯.

The researchers also measured the density of the symbiont as well as the photosynthetic yield in adult corals at the two temperatures. Photosynthetic yield is an index measure of energy output compared to sunlight energy input in which larger photosynthetic yield values represent photosynthetic organisms producing more energy.

The figure presents a bar graph and a line graph. The bar graph has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is labeled Symbiont Density, per square millimeter, and the numbers 0 through 8000, in increments of 1000, are indicated. Two bars of data each are located at 0 days, 5 days, and 10 days representing the data obtained at environmental temperatures 27 degrees Celsius and 32 degrees Celsius. Each bar contains error bars representing plus or minus 2 times the standard error of the mean. The data represented in the bar graph are as follows. Note that all values are approximate. Data for Time, 0 days. 27 degrees Celsius, 5100 per square millimeter with error bars extending from 4500 to 5500 per square millimeter; 32 degrees Celsius, 5000 per square millimeter with error bars extending from 4200 to 5800 per square millimeter. Data for Time, 5 days. 27 degrees Celsius, 5600 per square millimeter with error bars extending from 5100 to 6100 per square millimeter; 32 degrees Celsius, 4100 per square millimeter  with error bars extending from 3500 to 4700 per square millimeter. Data for Time, 10 days. 27 degrees Celsius, 6000 per square millimeter with error bars extending from 5500 to 6500 per square millimeter; 32 degrees Celsius, 900 per square millimeter with error bars extending from 800 to 1000 per square millimeter. The line graph has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is labeled Photosynthetic Yield, and no values are indicated along it. An arrow head is at the top of the axis. Two lines of data, each with 3 data points, are shown in the graph; one for an environmental temperature of 27 degrees Celsius and the other for an environmental temperature of 32 degrees Celsius. Each data point contains error bars representing plus or minus 2 standard error of the mean. The data represented in the line graph are as follows. The data points for 27 degrees Celsius are located at: 0 days and three quarters of the way up the vertical axis; 5 days and slightly below the height of the first data point; 10 days and slightly above the height of the first data point. The data points for 32 degrees Celsius are located at: 0 days and two thirds of the way up the vertical axis; 5 days and just above the midpoint of the vertical axis; 10 days and one sixth of the way up the vertical axis. None of the error bars around the data points overlap.

Figure 2: Variation in symbiont density and photosynthetic yield in adult corals grown in normal and thermally-stressed conditions. Error bars represent ±2SE𝑥¯.

Which of the following best describes the effect of temperature on corals’ ability to produce DMSP as shown in Figure 1?

  • A: Both juvenile and adult corals produce less DMSP at 27°C than at 32°C.

  • B: Both juvenile and adult corals produce less DMSP at 32°C than at 27°C.

  • C: The amount of DMSP produced over time increases at 32°C in juveniles only.

  • D: The amount of DMSP produced over time increases at 32°C in adults only.

A: Both juvenile and adult corals produce less DMSP at 27°C than at 32°C.

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Certain reef-building corals contain photosynthetic, symbiotic algae that have the ability to make dimethylsulphoniopropionate (DMSP), a chemical involved in the marine sulfur cycle. DMSP is released into the surrounding water, where it is converted to the gas dimethyl sulfide (DMS) by microorganisms and enters the atmosphere. Once in the atmosphere, it triggers the formation of sulfate aerosols, which induce cloud formation and block sunlight from heating up the water.

The symbiotic algae produce DMSP when they are stressed by a high water temperature. If water temperature is too high, corals will expel the symbiotic algae that produce DMSP. Researchers measured the amount of DMSP produced by juvenile and adult coral and their symbionts under normal and thermally stressed conditions. The data are shown in the graphs in Figure 1.

The figure presents two line graphs, labeled Juveniles and Adults. Both graphs have two lines with three data points each; one line for an environmental temperature of 27 degrees Celsius and the other for an environmental temperature of 32 degrees Celsius. The graph titled Juveniles has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is labeled D M S P Concentration, in nanomoles per square millimeter, and the numbers 0 through 7, in increments of 1, are indicated. The data points for the line representing 27 degrees Celsius are located at the points 0 comma 2.5 with error bars extending from 2.3 to 2.7; 5 comma 3.0 with error bars extending from 2.8 to 3.2; 10 comma 3.1 with error bars extending from 2.9 to 3.3. The data points for the line representing 32 degrees Celsius are located at the points 0 comma 3.1 with error bars extending from 2.9 to 3.3; 5 comma 4.5 with error bars extending from 4.1 to 4.9; 10 comma 5.5 with error bars extending from 5.3 to 5.7. The graph titled Adults has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is titled D M S P Concentration, in nanomoles per square millimeter, and the numbers 0 through 25, in increments of 5, are indicated.  The data points for the line representing 27 degrees Celsius are located at the points 0 comma 10 with error bars extending from 9 to 11; 5 comma 11 with error bars extending from 10 to 12; 10 comma 12 with error bars extending from 11 to 13. The data points for the line representing 32 degrees Celsius are located at the points 0 comma 14 with error bars extending from 13 to 15; 5 comma 17 with error bars extending from 15 to 19; 10 comma 22 with error bars extending from 21 to 23.

Figure 1: DMSP concentration in juvenile and adult corals and their symbionts in normal and thermally-stressed conditions. Error bars represent ±2SE𝑥¯.

The researchers also measured the density of the symbiont as well as the photosynthetic yield in adult corals at the two temperatures. Photosynthetic yield is an index measure of energy output compared to sunlight energy input in which larger photosynthetic yield values represent photosynthetic organisms producing more energy.

The figure presents a bar graph and a line graph. The bar graph has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is labeled Symbiont Density, per square millimeter, and the numbers 0 through 8000, in increments of 1000, are indicated. Two bars of data each are located at 0 days, 5 days, and 10 days representing the data obtained at environmental temperatures 27 degrees Celsius and 32 degrees Celsius. Each bar contains error bars representing plus or minus 2 times the standard error of the mean. The data represented in the bar graph are as follows. Note that all values are approximate. Data for Time, 0 days. 27 degrees Celsius, 5100 per square millimeter with error bars extending from 4500 to 5500 per square millimeter; 32 degrees Celsius, 5000 per square millimeter with error bars extending from 4200 to 5800 per square millimeter. Data for Time, 5 days. 27 degrees Celsius, 5600 per square millimeter with error bars extending from 5100 to 6100 per square millimeter; 32 degrees Celsius, 4100 per square millimeter  with error bars extending from 3500 to 4700 per square millimeter. Data for Time, 10 days. 27 degrees Celsius, 6000 per square millimeter with error bars extending from 5500 to 6500 per square millimeter; 32 degrees Celsius, 900 per square millimeter with error bars extending from 800 to 1000 per square millimeter. The line graph has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is labeled Photosynthetic Yield, and no values are indicated along it. An arrow head is at the top of the axis. Two lines of data, each with 3 data points, are shown in the graph; one for an environmental temperature of 27 degrees Celsius and the other for an environmental temperature of 32 degrees Celsius. Each data point contains error bars representing plus or minus 2 standard error of the mean. The data represented in the line graph are as follows. The data points for 27 degrees Celsius are located at: 0 days and three quarters of the way up the vertical axis; 5 days and slightly below the height of the first data point; 10 days and slightly above the height of the first data point. The data points for 32 degrees Celsius are located at: 0 days and two thirds of the way up the vertical axis; 5 days and just above the midpoint of the vertical axis; 10 days and one sixth of the way up the vertical axis. None of the error bars around the data points overlap.

Figure 2: Variation in symbiont density and photosynthetic yield in adult corals grown in normal and thermally-stressed conditions. Error bars represent ±2SE𝑥¯.

Which of the following best describes the difference between the total amount of DMSP produced by adults compared to juveniles at the start of the 32°C trial?

  • A: Adult corals produced 3 times more DMSP than juveniles produced.

  • B: Adult corals produced 3 times less DMSP than juveniles produced.

  • C: Adult corals produced 5 times more DMSP than juveniles produced.

  • D: Adult corals produced 5 times less DMSP than juveniles produced.

C: Adult corals produced 5 times more DMSP than juveniles produced.

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15

Certain reef-building corals contain photosynthetic, symbiotic algae that have the ability to make dimethylsulphoniopropionate (DMSP), a chemical involved in the marine sulfur cycle. DMSP is released into the surrounding water, where it is converted to the gas dimethyl sulfide (DMS) by microorganisms and enters the atmosphere. Once in the atmosphere, it triggers the formation of sulfate aerosols, which induce cloud formation and block sunlight from heating up the water.

The symbiotic algae produce DMSP when they are stressed by a high water temperature. If water temperature is too high, corals will expel the symbiotic algae that produce DMSP. Researchers measured the amount of DMSP produced by juvenile and adult coral and their symbionts under normal and thermally stressed conditions. The data are shown in the graphs in Figure 1.

The figure presents two line graphs, labeled Juveniles and Adults. Both graphs have two lines with three data points each; one line for an environmental temperature of 27 degrees Celsius and the other for an environmental temperature of 32 degrees Celsius. The graph titled Juveniles has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is labeled D M S P Concentration, in nanomoles per square millimeter, and the numbers 0 through 7, in increments of 1, are indicated. The data points for the line representing 27 degrees Celsius are located at the points 0 comma 2.5 with error bars extending from 2.3 to 2.7; 5 comma 3.0 with error bars extending from 2.8 to 3.2; 10 comma 3.1 with error bars extending from 2.9 to 3.3. The data points for the line representing 32 degrees Celsius are located at the points 0 comma 3.1 with error bars extending from 2.9 to 3.3; 5 comma 4.5 with error bars extending from 4.1 to 4.9; 10 comma 5.5 with error bars extending from 5.3 to 5.7. The graph titled Adults has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is titled D M S P Concentration, in nanomoles per square millimeter, and the numbers 0 through 25, in increments of 5, are indicated.  The data points for the line representing 27 degrees Celsius are located at the points 0 comma 10 with error bars extending from 9 to 11; 5 comma 11 with error bars extending from 10 to 12; 10 comma 12 with error bars extending from 11 to 13. The data points for the line representing 32 degrees Celsius are located at the points 0 comma 14 with error bars extending from 13 to 15; 5 comma 17 with error bars extending from 15 to 19; 10 comma 22 with error bars extending from 21 to 23.

Figure 1: DMSP concentration in juvenile and adult corals and their symbionts in normal and thermally-stressed conditions. Error bars represent ±2SE𝑥¯.

The researchers also measured the density of the symbiont as well as the photosynthetic yield in adult corals at the two temperatures. Photosynthetic yield is an index measure of energy output compared to sunlight energy input in which larger photosynthetic yield values represent photosynthetic organisms producing more energy.

The figure presents a bar graph and a line graph. The bar graph has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is labeled Symbiont Density, per square millimeter, and the numbers 0 through 8000, in increments of 1000, are indicated. Two bars of data each are located at 0 days, 5 days, and 10 days representing the data obtained at environmental temperatures 27 degrees Celsius and 32 degrees Celsius. Each bar contains error bars representing plus or minus 2 times the standard error of the mean. The data represented in the bar graph are as follows. Note that all values are approximate. Data for Time, 0 days. 27 degrees Celsius, 5100 per square millimeter with error bars extending from 4500 to 5500 per square millimeter; 32 degrees Celsius, 5000 per square millimeter with error bars extending from 4200 to 5800 per square millimeter. Data for Time, 5 days. 27 degrees Celsius, 5600 per square millimeter with error bars extending from 5100 to 6100 per square millimeter; 32 degrees Celsius, 4100 per square millimeter  with error bars extending from 3500 to 4700 per square millimeter. Data for Time, 10 days. 27 degrees Celsius, 6000 per square millimeter with error bars extending from 5500 to 6500 per square millimeter; 32 degrees Celsius, 900 per square millimeter with error bars extending from 800 to 1000 per square millimeter. The line graph has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is labeled Photosynthetic Yield, and no values are indicated along it. An arrow head is at the top of the axis. Two lines of data, each with 3 data points, are shown in the graph; one for an environmental temperature of 27 degrees Celsius and the other for an environmental temperature of 32 degrees Celsius. Each data point contains error bars representing plus or minus 2 standard error of the mean. The data represented in the line graph are as follows. The data points for 27 degrees Celsius are located at: 0 days and three quarters of the way up the vertical axis; 5 days and slightly below the height of the first data point; 10 days and slightly above the height of the first data point. The data points for 32 degrees Celsius are located at: 0 days and two thirds of the way up the vertical axis; 5 days and just above the midpoint of the vertical axis; 10 days and one sixth of the way up the vertical axis. None of the error bars around the data points overlap.

Figure 2: Variation in symbiont density and photosynthetic yield in adult corals grown in normal and thermally-stressed conditions. Error bars represent ±2SE𝑥¯.

In addition to the effect of temperature on DMSP produced by corals and their symbionts, which of the following relationships is also being considered in this experiment?

  • A: Effect of varying light levels and coral species

  • B: Effect of additional DMSP produced by symbionts and the corals' age

  • C: Effect of age and varying light levels

  • D: Effect of coral species and additional DMSP produced by symbionts

  • B: Effect of additional DMSP produced by symbionts and the corals' age

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Certain reef-building corals contain photosynthetic, symbiotic algae that have the ability to make dimethylsulphoniopropionate (DMSP), a chemical involved in the marine sulfur cycle. DMSP is released into the surrounding water, where it is converted to the gas dimethyl sulfide (DMS) by microorganisms and enters the atmosphere. Once in the atmosphere, it triggers the formation of sulfate aerosols, which induce cloud formation and block sunlight from heating up the water.

The symbiotic algae produce DMSP when they are stressed by a high water temperature. If water temperature is too high, corals will expel the symbiotic algae that produce DMSP. Researchers measured the amount of DMSP produced by juvenile and adult coral and their symbionts under normal and thermally stressed conditions. The data are shown in the graphs in Figure 1.

The figure presents two line graphs, labeled Juveniles and Adults. Both graphs have two lines with three data points each; one line for an environmental temperature of 27 degrees Celsius and the other for an environmental temperature of 32 degrees Celsius. The graph titled Juveniles has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is labeled D M S P Concentration, in nanomoles per square millimeter, and the numbers 0 through 7, in increments of 1, are indicated. The data points for the line representing 27 degrees Celsius are located at the points 0 comma 2.5 with error bars extending from 2.3 to 2.7; 5 comma 3.0 with error bars extending from 2.8 to 3.2; 10 comma 3.1 with error bars extending from 2.9 to 3.3. The data points for the line representing 32 degrees Celsius are located at the points 0 comma 3.1 with error bars extending from 2.9 to 3.3; 5 comma 4.5 with error bars extending from 4.1 to 4.9; 10 comma 5.5 with error bars extending from 5.3 to 5.7. The graph titled Adults has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is titled D M S P Concentration, in nanomoles per square millimeter, and the numbers 0 through 25, in increments of 5, are indicated.  The data points for the line representing 27 degrees Celsius are located at the points 0 comma 10 with error bars extending from 9 to 11; 5 comma 11 with error bars extending from 10 to 12; 10 comma 12 with error bars extending from 11 to 13. The data points for the line representing 32 degrees Celsius are located at the points 0 comma 14 with error bars extending from 13 to 15; 5 comma 17 with error bars extending from 15 to 19; 10 comma 22 with error bars extending from 21 to 23.

Figure 1: DMSP concentration in juvenile and adult corals and their symbionts in normal and thermally-stressed conditions. Error bars represent ±2SE𝑥¯.

The researchers also measured the density of the symbiont as well as the photosynthetic yield in adult corals at the two temperatures. Photosynthetic yield is an index measure of energy output compared to sunlight energy input in which larger photosynthetic yield values represent photosynthetic organisms producing more energy.

The figure presents a bar graph and a line graph. The bar graph has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is labeled Symbiont Density, per square millimeter, and the numbers 0 through 8000, in increments of 1000, are indicated. Two bars of data each are located at 0 days, 5 days, and 10 days representing the data obtained at environmental temperatures 27 degrees Celsius and 32 degrees Celsius. Each bar contains error bars representing plus or minus 2 times the standard error of the mean. The data represented in the bar graph are as follows. Note that all values are approximate. Data for Time, 0 days. 27 degrees Celsius, 5100 per square millimeter with error bars extending from 4500 to 5500 per square millimeter; 32 degrees Celsius, 5000 per square millimeter with error bars extending from 4200 to 5800 per square millimeter. Data for Time, 5 days. 27 degrees Celsius, 5600 per square millimeter with error bars extending from 5100 to 6100 per square millimeter; 32 degrees Celsius, 4100 per square millimeter  with error bars extending from 3500 to 4700 per square millimeter. Data for Time, 10 days. 27 degrees Celsius, 6000 per square millimeter with error bars extending from 5500 to 6500 per square millimeter; 32 degrees Celsius, 900 per square millimeter with error bars extending from 800 to 1000 per square millimeter. The line graph has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is labeled Photosynthetic Yield, and no values are indicated along it. An arrow head is at the top of the axis. Two lines of data, each with 3 data points, are shown in the graph; one for an environmental temperature of 27 degrees Celsius and the other for an environmental temperature of 32 degrees Celsius. Each data point contains error bars representing plus or minus 2 standard error of the mean. The data represented in the line graph are as follows. The data points for 27 degrees Celsius are located at: 0 days and three quarters of the way up the vertical axis; 5 days and slightly below the height of the first data point; 10 days and slightly above the height of the first data point. The data points for 32 degrees Celsius are located at: 0 days and two thirds of the way up the vertical axis; 5 days and just above the midpoint of the vertical axis; 10 days and one sixth of the way up the vertical axis. None of the error bars around the data points overlap.

Figure 2: Variation in symbiont density and photosynthetic yield in adult corals grown in normal and thermally-stressed conditions. Error bars represent ±2SE𝑥¯.

Which of the following best describes the scientists’ findings concerning the density of symbionts presented in Figure 2 ?

  • A: The symbiont density at 32°C on day 5 was less than the density on day 0 of the experiment.

  • B: The symbiont density at 27°C on day 0 was less than the density on day 5 of the experiment.

  • C: The symbiont density at 32°C was different from the density at 27°C on days 5 and 10 of the experiment.

  • D: The symbiont density at 27°C was higher than the density at 32°C for the entire length of the experiment.

C: The symbiont density at 32°C was different from the density at 27°C on days 5 and 10 of the experiment.

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Certain reef-building corals contain photosynthetic, symbiotic algae that have the ability to make dimethylsulphoniopropionate (DMSP), a chemical involved in the marine sulfur cycle. DMSP is released into the surrounding water, where it is converted to the gas dimethyl sulfide (DMS) by microorganisms and enters the atmosphere. Once in the atmosphere, it triggers the formation of sulfate aerosols, which induce cloud formation and block sunlight from heating up the water.

The symbiotic algae produce DMSP when they are stressed by a high water temperature. If water temperature is too high, corals will expel the symbiotic algae that produce DMSP. Researchers measured the amount of DMSP produced by juvenile and adult coral and their symbionts under normal and thermally stressed conditions. The data are shown in the graphs in Figure 1.

The figure presents two line graphs, labeled Juveniles and Adults. Both graphs have two lines with three data points each; one line for an environmental temperature of 27 degrees Celsius and the other for an environmental temperature of 32 degrees Celsius. The graph titled Juveniles has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is labeled D M S P Concentration, in nanomoles per square millimeter, and the numbers 0 through 7, in increments of 1, are indicated. The data points for the line representing 27 degrees Celsius are located at the points 0 comma 2.5 with error bars extending from 2.3 to 2.7; 5 comma 3.0 with error bars extending from 2.8 to 3.2; 10 comma 3.1 with error bars extending from 2.9 to 3.3. The data points for the line representing 32 degrees Celsius are located at the points 0 comma 3.1 with error bars extending from 2.9 to 3.3; 5 comma 4.5 with error bars extending from 4.1 to 4.9; 10 comma 5.5 with error bars extending from 5.3 to 5.7. The graph titled Adults has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is titled D M S P Concentration, in nanomoles per square millimeter, and the numbers 0 through 25, in increments of 5, are indicated.  The data points for the line representing 27 degrees Celsius are located at the points 0 comma 10 with error bars extending from 9 to 11; 5 comma 11 with error bars extending from 10 to 12; 10 comma 12 with error bars extending from 11 to 13. The data points for the line representing 32 degrees Celsius are located at the points 0 comma 14 with error bars extending from 13 to 15; 5 comma 17 with error bars extending from 15 to 19; 10 comma 22 with error bars extending from 21 to 23.

Figure 1: DMSP concentration in juvenile and adult corals and their symbionts in normal and thermally-stressed conditions. Error bars represent ±2SE𝑥¯.

The researchers also measured the density of the symbiont as well as the photosynthetic yield in adult corals at the two temperatures. Photosynthetic yield is an index measure of energy output compared to sunlight energy input in which larger photosynthetic yield values represent photosynthetic organisms producing more energy.

The figure presents a bar graph and a line graph. The bar graph has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is labeled Symbiont Density, per square millimeter, and the numbers 0 through 8000, in increments of 1000, are indicated. Two bars of data each are located at 0 days, 5 days, and 10 days representing the data obtained at environmental temperatures 27 degrees Celsius and 32 degrees Celsius. Each bar contains error bars representing plus or minus 2 times the standard error of the mean. The data represented in the bar graph are as follows. Note that all values are approximate. Data for Time, 0 days. 27 degrees Celsius, 5100 per square millimeter with error bars extending from 4500 to 5500 per square millimeter; 32 degrees Celsius, 5000 per square millimeter with error bars extending from 4200 to 5800 per square millimeter. Data for Time, 5 days. 27 degrees Celsius, 5600 per square millimeter with error bars extending from 5100 to 6100 per square millimeter; 32 degrees Celsius, 4100 per square millimeter  with error bars extending from 3500 to 4700 per square millimeter. Data for Time, 10 days. 27 degrees Celsius, 6000 per square millimeter with error bars extending from 5500 to 6500 per square millimeter; 32 degrees Celsius, 900 per square millimeter with error bars extending from 800 to 1000 per square millimeter. The line graph has the horizontal axis labeled Time, in days, and the numbers 0 through 10, in increments of 5, are indicated. The vertical axis is labeled Photosynthetic Yield, and no values are indicated along it. An arrow head is at the top of the axis. Two lines of data, each with 3 data points, are shown in the graph; one for an environmental temperature of 27 degrees Celsius and the other for an environmental temperature of 32 degrees Celsius. Each data point contains error bars representing plus or minus 2 standard error of the mean. The data represented in the line graph are as follows. The data points for 27 degrees Celsius are located at: 0 days and three quarters of the way up the vertical axis; 5 days and slightly below the height of the first data point; 10 days and slightly above the height of the first data point. The data points for 32 degrees Celsius are located at: 0 days and two thirds of the way up the vertical axis; 5 days and just above the midpoint of the vertical axis; 10 days and one sixth of the way up the vertical axis. None of the error bars around the data points overlap.

Figure 2: Variation in symbiont density and photosynthetic yield in adult corals grown in normal and thermally-stressed conditions. Error bars represent ±2SE𝑥¯.

Which of the following best explains the result of adult corals being exposed to elevated temperatures for extended periods?

  • A: They are able to obtain more energy from their symbionts because the algae are receiving more light.

  • B: They are able to obtain more energy from their symbionts because the efficiency increases slightly over time.

  • C: They are able to obtain less energy from their symbionts because the algae have been expelled.

  • D: They are able to obtain less energy from their symbionts because more DMSP is being produced at lower temperatures

C: They are able to obtain less energy from their symbionts because the algae have been expelled.

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A particular gene has two alleles, a dominant allele 𝐴 and a recessive allele 𝑎. The frequency of allele 𝐴 is 0.55. If the population is in Hardy-Weinberg equilibrium with respect to the gene, then what is the expected frequency of genotype 𝐴𝑎?

  • A: 0.203

  • B: 0.303

  • C: 0.405

  • D: 0.495

  • D: 0.495

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A particular genetic disorder results from a single change in the amino acid sequence coded for in a gene. Parts of the sequence in normal and mutated genes are shown below.

Normal:

TAC CTC GTG GAC TGA GGT CTC

Mutated:

TAC CTC GTG GAC TGA GGT CAC

The figure presents a codon chart. The left side of the chart is labeled First Base. There are 4 boxes in a column that are labeled from top to bottom: U, C, A, and G. The top of the chart is labeled Second Base, and there are 4 boxes in a row labeled from left to right: U, C, A, and G. The right side of the chart is labeled Third Base, and there are 4 boxes in a column that are labeled from top to bottom U C A G, U C A G, U C A G, and U C A G. The chart contains 4 rows, with 4 boxes in each row. The data in the chart are as follows. Row 1, Box 1: Phe, Phe, Leu, Leu. Row 1, Box 2: Ser, Ser, Ser, Ser. Row 1, Box 3: Tyr, Tyr, Stop, Stop. Row 1, Box 4: Cys, Cys, Stop, Trp. Row 2, Box 1: Leu, Leu, Leu, Leu. Row 2, Box 2: Pro, Pro, Pro, Pro. Row 2, Box 3: His, His, Gln, Gln. Row 2, Box 4: Arg, Arg, Arg, Arg. Row 3, Box 1: Ile, Ile, Ile, Met. Row 3, Box 2: Thr, Thr, Thr, Thr. Row 3, Box 3: Asn, Asn, Lys, Lys. Row 3, Box 4: Ser, Ser, Arg, Arg. Row 4, Box 1: Val, Val, Val, Val. Row 4, Box 2: Ala, Ala, Ala, Ala. Row 4, Box 3: Asp, Asp, Glu, Glu. Row 4, Box 4: Gly, Gly, Gly, Gly.

Based on the codon chart above, which of the following amino acid changes is most likely found in the mutated protein?

Responses

  • A: Glu → Val

  • B: Val → Glu

  • C: Glu → Pro

  • D: Pro → Val

A: Glu → Val

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<p>Figure 1. A pedigree of three generations of a family that have a high frequency of a particular genetic condition</p><p style="text-align: start">Figure 1 shows the inheritance of a particular genetic condition in three generations of one family. Which of the following best explains the observed pattern of inheritance?</p><ul><li><p><strong>A: </strong><span>The condition is passed randomly because of the independent assortment of chromosomes.</span></p><p></p></li><li><p><strong>B: </strong><span>The condition is passed from fathers to sons via a Y-linked gene.</span></p><p></p></li><li><p><strong>C: </strong><span>The condition is passed from mothers to sons via an X-linked gene.</span></p><p></p></li><li><p><strong>D: </strong><span>The condition is passed from mothers to offspring via a mitochondrial gene.</span></p></li></ul>

Figure 1. A pedigree of three generations of a family that have a high frequency of a particular genetic condition

Figure 1 shows the inheritance of a particular genetic condition in three generations of one family. Which of the following best explains the observed pattern of inheritance?

  • A: The condition is passed randomly because of the independent assortment of chromosomes.

  • B: The condition is passed from fathers to sons via a Y-linked gene.

  • C: The condition is passed from mothers to sons via an X-linked gene.

  • D: The condition is passed from mothers to offspring via a mitochondrial gene.

D: The condition is passed from mothers to offspring via a mitochondrial gene.

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Oncogenes are genes that can cause tumor formation as a result of a particular mutation. Which of the following potential therapies would be most effective at preventing the expression of an oncogene?

  • A: Reducing the number of ribosomes in the cell to prevent the creation of the oncogene’s proteins

  • B: Blocking membrane-bound receptors of transcription factors

  • C: Introducing a chemical that binds to transcription factors associated with the oncogene’s promoter

  • D: Producing additional transcription factors for tumor suppressor genes in the cell

C: Introducing a chemical that binds to transcription factors associated with the oncogene’s promoter

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Ultraviolet (UV) radiation can damage DNA by breaking weak bonds. Which of the following best explains how this occurs?

  • (A) UV radiation disrupts the double helix structure by breaking the covalent bonds between the nitrogenous base pairs.

  • (B) UV radiation disrupts the double helix structure by breaking the hydrogen bonds between the nitrogenous base pairs.

  • (C) UV radiation is able to break DNA strands in two by breaking covalent bonds between the sugar-phosphate backbone molecules.

  • (D) UV radiation is able to break DNA strands in two by breaking hydrogen bonds between the sugar-phosphate backbone molecules.

(B) UV radiation disrupts the double helix structure by breaking the hydrogen bonds between the nitrogenous base pairs.

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Scientists are interested in determining the evolution of seven lizard species found on different islands of the Canary Island group. They isolated DNA from individuals of each species and sequenced the mitochondrial gene that encodes cytochrome 𝑏. The numbers of genetic differences between species are shown in the table below.

The figure presents a table with 7 columns and 7 rows. The row and columns are both labeled: Species A, Species B, Species C, Species D, Species E, Species F, and Species G. Note that not all cells within the table contain data. The data represented in the table are as follows. Species A, Species B: 34. Species A, Species C: 39. Species A, Species D, 38. Species A, Species E: 38. Species A, Species F: 43. Species A, Species G: 47. Species B, Species C: 23. Species B, Species D: 21. Species B, Species E: 17. Species B, Species F: 22. Species B, Species G: 26. Species C, Species D:  6. Species C, Species E: 8. Species C, Species F: 17. Species C, Species G: 17. Species D, Species E: 4. Species D, Species F: 17. Species D, Species G: 19. Species E, Species F: 13. Species E, Species G: 15. Species F, Species G: 2.

Based on the data in the table, which of the following lizard species are most closely related?

  • A: Species C and species B

  • B: Species E and species D

  • C: Species F and species B

  • D: Species G and species A

B: Species E and species D

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<p>Figure 1. A model of an endocrine signaling pathway showing involved body parts and hormones. GnRH = gonadotropin-releasing hormone, LH = luteinizing hormone, and FSH = follicle-stimulating hormone.</p><p style="text-align: start">Figure 1 shows a model of the endocrine signaling pathway that regulates ovulation. Which of the following observations would provide evidence of a positive feedback mechanism in this system?</p><ul><li><p style="text-align: start"><strong>A: </strong>Estrogen from the ovaries inhibits the release of GnRH from the hypothalamus.</p><p style="text-align: start"></p></li><li><p style="text-align: start"><strong>B: </strong>Progesterone from the ovaries stimulates the thickening of the uterine lining.</p><p style="text-align: start"></p></li><li><p style="text-align: start"><strong>C: </strong>Progesterone from the ovaries inhibits the release of LH and FSH from the anterior pituitary.</p><p style="text-align: start"></p></li><li><p style="text-align: start"><strong>D: </strong>Estrogen from the ovaries stimulates the hypothalamus and anterior pituitary to secrete more GnRH, LH, and FSH.</p></li></ul>

Figure 1. A model of an endocrine signaling pathway showing involved body parts and hormones. GnRH = gonadotropin-releasing hormone, LH = luteinizing hormone, and FSH = follicle-stimulating hormone.

Figure 1 shows a model of the endocrine signaling pathway that regulates ovulation. Which of the following observations would provide evidence of a positive feedback mechanism in this system?

  • A: Estrogen from the ovaries inhibits the release of GnRH from the hypothalamus.

  • B: Progesterone from the ovaries stimulates the thickening of the uterine lining.

  • C: Progesterone from the ovaries inhibits the release of LH and FSH from the anterior pituitary.

  • D: Estrogen from the ovaries stimulates the hypothalamus and anterior pituitary to secrete more GnRH, LH, and FSH.

  • D: Estrogen from the ovaries stimulates the hypothalamus and anterior pituitary to secrete more GnRH, LH, and FSH.

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Dichlorophenolindophenol (DCPIP) is a chemical dye. When DCPIP is chemically reduced, it changes color from blue to clear. DCPIP can be used as an electron acceptor in experiments that measure the rate of electron transport through the electron transport chain. A student performed an experiment to study the effects of a chemical, DCMU, on photosynthesis.

The student prepared four tubes with a liquid buffer and chloroplasts that had been extracted from spinach leaves. The student then added DCPIP to three of the tubes and added DCMU to one of them. Additionally, tube 3 was wrapped in tin foil. The contents of each tube are shown in the table. The student then incubated each tube for 60 minutes and measured the absorbance (A600) of each solution at five-minute intervals. The absorbance readings of each solution are shown in Figure 1.

Tube 1:

Buffer and water

Tube 2:

DCPIP, buffer, and water

Tube 3:

DCPIP, buffer, and water (wrapped in foil)

Tube 4:

DCPIP, buffer, and 1.0mMDCMU

The figure presents a graph with the horizontal axis labeled Time, in minutes, and the numbers 0 through 60, in increments of 20, are indicated. The vertical axis is labeled A sub 600, and the numbers 0 through 1.0, in increments of 0.1, are indicated. Four lines of data are shown on the graph, labeled Tube 1, Tube 2, Tube 3, and Tube 4. The data represented in the graph are as follows. Note that all values are approximate. The line labeled Tube 1 begins at the origin and moves to the right, fluctuating slightly above the horizontal axis, and ending at the point 60 minutes comma 0.01 A sub 600. The line labeled Tube 2 begins at the point 0 minutes comma 0.9 A sub 600 and moves downwards and to the right at a constant rate, ending at the point 60 minutes comma 0.12 A sub 600. The line labeled Tube 3 begins at the point 0 minutes comma 0.9 A sub 600 and moves nearly horizontally to the right, fluctuating slightly, and ending at the point 60 minutes comma 0.9 A sub 600. The line labeled Tube 4 begins at the point 0 minutes comma 0.9 A sub 600 and moves nearly horizontally to the right, fluctuates upward slightly, and ends at the point 60 minutes comma 0.91 A sub 600.

Figure 1. Absorbance readings of four prepared tubes with various solutions over a 60-minute period.

In which of the following tubes did the greatest reduction of DCPIP occur after 60 minutes?

  • A: Tube 1

  • B: Tube 2

  • C: Tube 3

  • D: Tube 4

  • B: Tube 2

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Dichlorophenolindophenol (DCPIP) is a chemical dye. When DCPIP is chemically reduced, it changes color from blue to clear. DCPIP can be used as an electron acceptor in experiments that measure the rate of electron transport through the electron transport chain. A student performed an experiment to study the effects of a chemical, DCMU, on photosynthesis.

The student prepared four tubes with a liquid buffer and chloroplasts that had been extracted from spinach leaves. The student then added DCPIP to three of the tubes and added DCMU to one of them. Additionally, tube 3 was wrapped in tin foil. The contents of each tube are shown in the table. The student then incubated each tube for 60 minutes and measured the absorbance (A600) of each solution at five-minute intervals. The absorbance readings of each solution are shown in Figure 1.

Tube 1:

Buffer and water

Tube 2:

DCPIP, buffer, and water

Tube 3:

DCPIP, buffer, and water (wrapped in foil)

Tube 4:

DCPIP, buffer, and 1.0mMDCMU

The figure presents a graph with the horizontal axis labeled Time, in minutes, and the numbers 0 through 60, in increments of 20, are indicated. The vertical axis is labeled A sub 600, and the numbers 0 through 1.0, in increments of 0.1, are indicated. Four lines of data are shown on the graph, labeled Tube 1, Tube 2, Tube 3, and Tube 4. The data represented in the graph are as follows. Note that all values are approximate. The line labeled Tube 1 begins at the origin and moves to the right, fluctuating slightly above the horizontal axis, and ending at the point 60 minutes comma 0.01 A sub 600. The line labeled Tube 2 begins at the point 0 minutes comma 0.9 A sub 600 and moves downwards and to the right at a constant rate, ending at the point 60 minutes comma 0.12 A sub 600. The line labeled Tube 3 begins at the point 0 minutes comma 0.9 A sub 600 and moves nearly horizontally to the right, fluctuating slightly, and ending at the point 60 minutes comma 0.9 A sub 600. The line labeled Tube 4 begins at the point 0 minutes comma 0.9 A sub 600 and moves nearly horizontally to the right, fluctuates upward slightly, and ends at the point 60 minutes comma 0.91 A sub 600.

Figure 1. Absorbance readings of four prepared tubes with various solutions over a 60-minute period.

Which of the following claims is best supported by the experimental results?

  • A: Light is required for the electron transport chain to transfer electrons.

  • B: Water, not carbon dioxide, is the source of electrons used in the light-dependent reaction of photosynthesis.

  • C: Carbon dioxide is the source of carbon used by green plants to build carbohydrates.

  • D: DCPIP provides a significant source of electrons to the electron transport chain of the light reaction in the absence of light.

A: Light is required for the electron transport chain to transfer electrons.

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Dichlorophenolindophenol (DCPIP) is a chemical dye. When DCPIP is chemically reduced, it changes color from blue to clear. DCPIP can be used as an electron acceptor in experiments that measure the rate of electron transport through the electron transport chain. A student performed an experiment to study the effects of a chemical, DCMU, on photosynthesis.

The student prepared four tubes with a liquid buffer and chloroplasts that had been extracted from spinach leaves. The student then added DCPIP to three of the tubes and added DCMU to one of them. Additionally, tube 3 was wrapped in tin foil. The contents of each tube are shown in the table. The student then incubated each tube for 60 minutes and measured the absorbance (A600) of each solution at five-minute intervals. The absorbance readings of each solution are shown in Figure 1.

Tube 1:

Buffer and water

Tube 2:

DCPIP, buffer, and water

Tube 3:

DCPIP, buffer, and water (wrapped in foil)

Tube 4:

DCPIP, buffer, and 1.0mMDCMU

The figure presents a graph with the horizontal axis labeled Time, in minutes, and the numbers 0 through 60, in increments of 20, are indicated. The vertical axis is labeled A sub 600, and the numbers 0 through 1.0, in increments of 0.1, are indicated. Four lines of data are shown on the graph, labeled Tube 1, Tube 2, Tube 3, and Tube 4. The data represented in the graph are as follows. Note that all values are approximate. The line labeled Tube 1 begins at the origin and moves to the right, fluctuating slightly above the horizontal axis, and ending at the point 60 minutes comma 0.01 A sub 600. The line labeled Tube 2 begins at the point 0 minutes comma 0.9 A sub 600 and moves downwards and to the right at a constant rate, ending at the point 60 minutes comma 0.12 A sub 600. The line labeled Tube 3 begins at the point 0 minutes comma 0.9 A sub 600 and moves nearly horizontally to the right, fluctuating slightly, and ending at the point 60 minutes comma 0.9 A sub 600. The line labeled Tube 4 begins at the point 0 minutes comma 0.9 A sub 600 and moves nearly horizontally to the right, fluctuates upward slightly, and ends at the point 60 minutes comma 0.91 A sub 600.

Figure 1. Absorbance readings of four prepared tubes with various solutions over a 60-minute period.

Which of the following best explains how DCMU affected the reaction?

  • A: DCMU acts as a second buffer in the reaction.

  • B: DCMU acts as an additional carrier of electrons from photosystem II to DCPIP.

  • C: DCMU acts as an additional source of electrons to the light reaction of photosynthesis.

  • D: DCMU acts as an inhibitor to the movement of electrons within the light reaction of photosynthesis.

D: DCMU acts as an inhibitor to the movement of electrons within the light reaction of photosynthesis.

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Dichlorophenolindophenol (DCPIP) is a chemical dye. When DCPIP is chemically reduced, it changes color from blue to clear. DCPIP can be used as an electron acceptor in experiments that measure the rate of electron transport through the electron transport chain. A student performed an experiment to study the effects of a chemical, DCMU, on photosynthesis.

The student prepared four tubes with a liquid buffer and chloroplasts that had been extracted from spinach leaves. The student then added DCPIP to three of the tubes and added DCMU to one of them. Additionally, tube 3 was wrapped in tin foil. The contents of each tube are shown in the table. The student then incubated each tube for 60 minutes and measured the absorbance (A600) of each solution at five-minute intervals. The absorbance readings of each solution are shown in Figure 1.

Tube 1:

Buffer and water

Tube 2:

DCPIP, buffer, and water

Tube 3:

DCPIP, buffer, and water (wrapped in foil)

Tube 4:

DCPIP, buffer, and 1.0mMDCMU

The figure presents a graph with the horizontal axis labeled Time, in minutes, and the numbers 0 through 60, in increments of 20, are indicated. The vertical axis is labeled A sub 600, and the numbers 0 through 1.0, in increments of 0.1, are indicated. Four lines of data are shown on the graph, labeled Tube 1, Tube 2, Tube 3, and Tube 4. The data represented in the graph are as follows. Note that all values are approximate. The line labeled Tube 1 begins at the origin and moves to the right, fluctuating slightly above the horizontal axis, and ending at the point 60 minutes comma 0.01 A sub 600. The line labeled Tube 2 begins at the point 0 minutes comma 0.9 A sub 600 and moves downwards and to the right at a constant rate, ending at the point 60 minutes comma 0.12 A sub 600. The line labeled Tube 3 begins at the point 0 minutes comma 0.9 A sub 600 and moves nearly horizontally to the right, fluctuating slightly, and ending at the point 60 minutes comma 0.9 A sub 600. The line labeled Tube 4 begins at the point 0 minutes comma 0.9 A sub 600 and moves nearly horizontally to the right, fluctuates upward slightly, and ends at the point 60 minutes comma 0.91 A sub 600.

Figure 1. Absorbance readings of four prepared tubes with various solutions over a 60-minute period.

Which of the following best justifies the use of tube 2 as a control treatment?

  • A: It was a negative control for the accuracy of the spectrophotometer, ensuring that an accurate reading for treatment cuvette 2 would be made.

  • B: It was a negative control for the chemical stability of the chlorophyll suspension, ensuring that changes in absorbance could only be attributed to changes in chlorophyll content.

  • C: It was a positive control for the change in DCPIP color associated with changes in light intensity.

  • D: It was a positive control for measuring the effect of DCMU on the reaction.

D: It was a positive control for measuring the effect of DCMU on the reaction.

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29

A scientist designed an experiment to test an artificial membrane that mimics the phospholipid bilayer of a cell.

The scientist built a tube that was divided by an artificial membrane and filled with distilled water. The scientist put a known amount of a protein into the water on one side of the membrane. After some time, the scientist measured the concentration of the protein on either side of the membrane but found that there had been no change.

Which of the following experimental changes would allow the scientist to observe transport of a solute across the artificial membrane?

  • A: Increase the solute concentration in the solution

  • B: Use a small, nonpolar solute instead of a protein

  • C: Increase the temperature of the solution

  • D: Add artificial aquaporins to the membrane

B: Use a small, nonpolar solute instead of a protein

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Which of the following best illustrates the flow of information required for the synthesis of proteins encoded in the genome of a retrovirus?

  • A: DNA → RNA → PROTEIN

  • B: RNA → DNA → PROTEIN

  • C: RNA → DNA → RNA → PROTEIN

  • D: DNA → RNA → DNA → PROTEIN

C: RNA → DNA → RNA → PROTEIN

<p><strong>C: </strong>RNA → DNA → RNA → PROTEIN</p>
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Which of the following best describes the process by which gas from the atmosphere is obtained by plants and used to build lipids?

  • A: Gas is fixed by plants as part of the sulfur cycle.

  • B: Gas is fixed by plants as part of the nitrogen cycle.

  • C: Gas is directly obtained by plants as part of the carbon cycle.

  • D: Gas is directly obtained by plants as part of the magnesium cycle.

C: Gas is directly obtained by plants as part of the carbon cycle.

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Which of the following best explains how the phospholipid bilayer of a transport vesicle contributes to cellular functions?

  • A: The phospholipid bilayer allows the vesicle to fuse with the Golgi apparatus and the plasma membrane, allowing the exocytosis of proteins.

  • B: The phospholipid bilayer physically connects the nuclear envelope to the rough endoplasmic reticulum, thus increasing the rate of transcription and translation.

  • C: The phospholipid bilayer of a transport vesicle contains chemicals that digest the proteins made in the rough endoplasmic reticulum.

  • D: The phospholipid bilayer contains enzymes that catalyze the conversion of hydrogen peroxide to water and oxygen.

A: The phospholipid bilayer allows the vesicle to fuse with the Golgi apparatus and the plasma membrane, allowing the exocytosis of proteins.

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<p>The diploid number of chromosomes in the cell of a domesticated dog is <span>78</span>. Which of the following options includes the correct number of chromosomes in a cell after each cellular process (<span>G2</span> checkpoint, meiosis, and fertilization, respectively)?</p><p>(ignore the that i accidentally selected A)</p>

The diploid number of chromosomes in the cell of a domesticated dog is 78. Which of the following options includes the correct number of chromosomes in a cell after each cellular process (G2 checkpoint, meiosis, and fertilization, respectively)?

(ignore the that i accidentally selected A)

knowt flashcard image
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<p></p><ul><li><p><strong>A: </strong><span>Rotenone acts as an inhibitor of the enzymes in the Krebs cycle.</span></p><p></p></li><li><p><strong>B: </strong>NADH, p<span>roduced during glycolysis, is not able to enter the mitochondria because transport proteins are blocked from entering.</span></p><p></p></li><li><p><strong>C: </strong><span>Treated cells are not able to break down NADH because certain enzymes of the electron transport chain are inhibited.</span></p><p></p></li><li><p><strong>D: </strong><span>Rotenone acts as an allosteric inhibitor of glycolytic enzymes, thus inhibiting cellular respiration.</span></p></li></ul>

  • A: Rotenone acts as an inhibitor of the enzymes in the Krebs cycle.

  • B: NADH, produced during glycolysis, is not able to enter the mitochondria because transport proteins are blocked from entering.

  • C: Treated cells are not able to break down NADH because certain enzymes of the electron transport chain are inhibited.

  • D: Rotenone acts as an allosteric inhibitor of glycolytic enzymes, thus inhibiting cellular respiration.

C: Treated cells are not able to break down NADH because certain enzymes of the electron transport chain are inhibited.

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Which of the following best explains why triploid bananas do not produce seeds?

  • A: The cells of the banana plant are unable to replicate DNA, thus preventing cell division and limiting growth.

  • B: The banana plants lack enough genetic diversity to properly hybridize.

  • C: The production of gametes is disrupted because of unequal pairing of homologous chromosomes during meiosis.

  • D: The production of seeds is not required because triploid plants produce gametes without fertilization.

C: The production of gametes is disrupted because of unequal pairing of homologous chromosomes during meiosis.

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<ul><li><p><strong>A: </strong><em><span>T. aquaticus</span></em><span> polymerase has an optimal temperature of 68°C.</span></p><p></p></li><li><p><strong>B: </strong><em><span>T. aquaticus</span></em><span> polymerase does not denature at high temperatures.</span></p><p></p></li><li><p><strong>C: </strong><em><span>T. aquaticus</span></em><span> polymerase can be used more than once without degrading.</span></p><p></p></li><li><p><strong>D: </strong><em><span>T. aquaticus</span></em><span> polymerase adds nucleotides to both the 3′ and 5′ ends of DNA.</span></p></li></ul>
  • A: T. aquaticus polymerase has an optimal temperature of 68°C.

  • B: T. aquaticus polymerase does not denature at high temperatures.

  • C: T. aquaticus polymerase can be used more than once without degrading.

  • D: T. aquaticus polymerase adds nucleotides to both the 3′ and 5′ ends of DNA.

  • B: T. aquaticus polymerase does not denature at high temperatures.

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<p>(accidentally clicked on an answer again)</p>

(accidentally clicked on an answer again)

knowt flashcard image
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<ul><li><p><strong>A: </strong><span>Xylem only</span></p><p></p></li><li><p><strong>B: </strong><span>Seeds and wood only</span></p><p></p></li><li><p><strong>C: </strong><span>Embryo and xylem only</span></p><p></p></li><li><p><strong>D: </strong><span>Embryo, xylem, wood, and seeds only</span></p></li></ul><p></p>
  • A: Xylem only

  • B: Seeds and wood only

  • C: Embryo and xylem only

  • D: Embryo, xylem, wood, and seeds only

C: Embryo and xylem only

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<ul><li><p><strong>A: </strong>3.84</p><p></p></li><li><p><strong>B: </strong>5.99</p><p></p></li><li><p><strong>C: </strong>7.82</p><p></p></li><li><p><strong>D: </strong>9.49</p></li></ul><p></p>
  • A: 3.84

  • B: 5.99

  • C: 7.82

  • D: 9.49

A: 3.84

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40

Sea otters are native to the western coast of North America. Between 1750 and 1850, hunting had reduced the population from hundreds of thousands to only one thousand individuals. In the early 1900s, a small population of sea otters was discovered in Elkhorn Slough, an estuary in central California near a large human population center. The otters were then protected by the international fur seal treaty, which banned sea otter hunting. The sea otter population has rebounded to nearly three thousand individuals today.

Otters live in kelp forests and eelgrass beds and feed on crabs and shellfish (Figure 1). Most herbivores in the habitat eat algae that grows on the eelgrass and not the eelgrass itself. If there is too much algae, the eelgrass does not receive enough light for photosynthesis. As the otter population has increased, the eelgrass habitat has increased.

The figure shows a vertically oriented food chain with 5 organisms depicted and arrows indicating the direction of flow. Flowing from bottom to top, the organisms are Eelgrass with a magnified view of algae growing on the Eelgrass, a Sea Slug, a Crab, and a Sea Otter.

Figure 1. Partial food chain in eelgrass habitats

Recently, however, scientists have noticed the presence of two nonnative, predatory invertebrate species that may be colonizing the Elkhorn Slough, which would have been too cold for them three decades ago. Scientists have also observed that otters in the area are experiencing increased mortality because of an increase in harmful algal blooms, which occur as a result of nutrient pollution. The harmful algae are ingested by shellfish, which the otters eat.

Which of the following best describes what happened to the otter population between 1750 and 1850 ?

  • A: The population decreased in size as a result of a loss of genetic diversity.

  • B: The population decreased in size as a result of habitat loss.

  • C: The population lost genetic diversity as a result of a bottleneck effect.

  • D: The population lost genetic diversity as a result of the founder effect.

C: The population lost genetic diversity as a result of a bottleneck effect.

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41

Sea otters are native to the western coast of North America. Between 1750 and 1850, hunting had reduced the population from hundreds of thousands to only one thousand individuals. In the early 1900s, a small population of sea otters was discovered in Elkhorn Slough, an estuary in central California near a large human population center. The otters were then protected by the international fur seal treaty, which banned sea otter hunting. The sea otter population has rebounded to nearly three thousand individuals today.

Otters live in kelp forests and eelgrass beds and feed on crabs and shellfish (Figure 1). Most herbivores in the habitat eat algae that grows on the eelgrass and not the eelgrass itself. If there is too much algae, the eelgrass does not receive enough light for photosynthesis. As the otter population has increased, the eelgrass habitat has increased.

The figure shows a vertically oriented food chain with 5 organisms depicted and arrows indicating the direction of flow. Flowing from bottom to top, the organisms are Eelgrass with a magnified view of algae growing on the Eelgrass, a Sea Slug, a Crab, and a Sea Otter.

Figure 1. Partial food chain in eelgrass habitats

Recently, however, scientists have noticed the presence of two nonnative, predatory invertebrate species that may be colonizing the Elkhorn Slough, which would have been too cold for them three decades ago. Scientists have also observed that otters in the area are experiencing increased mortality because of an increase in harmful algal blooms, which occur as a result of nutrient pollution. The harmful algae are ingested by shellfish, which the otters eat.

Based on the information provided in the passage, which of the following best describes the effect of harmful algal blooms on otter populations

  • A: They are a density-dependent factor that increases otter mortality in larger populations.

  • B: hey are a density-dependent factor that reduces otter numbers at lower population sizes

  • C: They are a density-independent factor that negatively affects the otter population regardless of its size.

  • D: They are a density-independent factor that increases otter mortality in only larger populations.

C: They are a density-independent factor that negatively affects the otter population regardless of its size.

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42

Sea otters are native to the western coast of North America. Between 1750 and 1850, hunting had reduced the population from hundreds of thousands to only one thousand individuals. In the early 1900s, a small population of sea otters was discovered in Elkhorn Slough, an estuary in central California near a large human population center. The otters were then protected by the international fur seal treaty, which banned sea otter hunting. The sea otter population has rebounded to nearly three thousand individuals today.

Otters live in kelp forests and eelgrass beds and feed on crabs and shellfish (Figure 1). Most herbivores in the habitat eat algae that grows on the eelgrass and not the eelgrass itself. If there is too much algae, the eelgrass does not receive enough light for photosynthesis. As the otter population has increased, the eelgrass habitat has increased.

The figure shows a vertically oriented food chain with 5 organisms depicted and arrows indicating the direction of flow. Flowing from bottom to top, the organisms are Eelgrass with a magnified view of algae growing on the Eelgrass, a Sea Slug, a Crab, and a Sea Otter.

Figure 1. Partial food chain in eelgrass habitats

Recently, however, scientists have noticed the presence of two nonnative, predatory invertebrate species that may be colonizing the Elkhorn Slough, which would have been too cold for them three decades ago. Scientists have also observed that otters in the area are experiencing increased mortality because of an increase in harmful algal blooms, which occur as a result of nutrient pollution. The harmful algae are ingested by shellfish, which the otters eat.

As otters were removed during the hunting years, there was a large decrease in the catches of fish species from the eelgrass habitats. Which of the following best explains why this decrease happened?

  • A: Otters are a keystone species, so their disappearance from the area affected the population size of one other species.

  • B: Otters are a keystone species, so their disappearance from the area resulted in the collapse of an entire community.

  • C: Otters have mutualistic relationships with many other species, so their disappearance from the area affected the population size of another species.

  • D: Otters have mutualistic relationships with many other species, so their disappearance from the area resulted in the collapse of an entire ecosystem.

B: Otters are a keystone species, so their disappearance from the area resulted in the collapse of an entire community.

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Sea otters are native to the western coast of North America. Between 1750 and 1850, hunting had reduced the population from hundreds of thousands to only one thousand individuals. In the early 1900s, a small population of sea otters was discovered in Elkhorn Slough, an estuary in central California near a large human population center. The otters were then protected by the international fur seal treaty, which banned sea otter hunting. The sea otter population has rebounded to nearly three thousand individuals today.

Otters live in kelp forests and eelgrass beds and feed on crabs and shellfish (Figure 1). Most herbivores in the habitat eat algae that grows on the eelgrass and not the eelgrass itself. If there is too much algae, the eelgrass does not receive enough light for photosynthesis. As the otter population has increased, the eelgrass habitat has increased.

The figure shows a vertically oriented food chain with 5 organisms depicted and arrows indicating the direction of flow. Flowing from bottom to top, the organisms are Eelgrass with a magnified view of algae growing on the Eelgrass, a Sea Slug, a Crab, and a Sea Otter.

Figure 1. Partial food chain in eelgrass habitats

Recently, however, scientists have noticed the presence of two nonnative, predatory invertebrate species that may be colonizing the Elkhorn Slough, which would have been too cold for them three decades ago. Scientists have also observed that otters in the area are experiencing increased mortality because of an increase in harmful algal blooms, which occur as a result of nutrient pollution. The harmful algae are ingested by shellfish, which the otters eat.

Climate change could affect the ecosystem of the Elkhorn Slough in many ways. From the information provided, which of the following predictions about the direct, local effects of climate change is most likely?

  • A: Ocean warming will favor population growth of nonnative species as their habitats shift northward.

  • B: Ocean warming will decrease eelgrass habitat area as a result of increased herbivory by nonnative species.

  • C: Harmful algal blooms will decrease otter populations as a result of increased mortality of otter prey species.

  • D: Harmful algal blooms will decrease the availability of nutrients for eelgrass and other algae species.

A: Ocean warming will favor population growth of nonnative species as their habitats shift northward.

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44

Sea otters are native to the western coast of North America. Between 1750 and 1850, hunting had reduced the population from hundreds of thousands to only one thousand individuals. In the early 1900s, a small population of sea otters was discovered in Elkhorn Slough, an estuary in central California near a large human population center. The otters were then protected by the international fur seal treaty, which banned sea otter hunting. The sea otter population has rebounded to nearly three thousand individuals today.

Otters live in kelp forests and eelgrass beds and feed on crabs and shellfish (Figure 1). Most herbivores in the habitat eat algae that grows on the eelgrass and not the eelgrass itself. If there is too much algae, the eelgrass does not receive enough light for photosynthesis. As the otter population has increased, the eelgrass habitat has increased.

The figure shows a vertically oriented food chain with 5 organisms depicted and arrows indicating the direction of flow. Flowing from bottom to top, the organisms are Eelgrass with a magnified view of algae growing on the Eelgrass, a Sea Slug, a Crab, and a Sea Otter.

Figure 1. Partial food chain in eelgrass habitats

Recently, however, scientists have noticed the presence of two nonnative, predatory invertebrate species that may be colonizing the Elkhorn Slough, which would have been too cold for them three decades ago. Scientists have also observed that otters in the area are experiencing increased mortality because of an increase in harmful algal blooms, which occur as a result of nutrient pollution. The harmful algae are ingested by shellfish, which the otters eat.

Based on the information, an increase in the sea slug population would most likely be directly related to which of the following?

  • A: An increase in the eelgrass population

  • B: The introduction of nonnative invertebrates

  • C: A decrease in algae availability

  • D: A decrease in the crab population

D: A decrease in the crab population

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Many fish species, such as fathead minnows, release a pheromone when their skin cells are damaged. Researchers placed pike, a predator of fathead minnows, in a choice chamber and released the minnow pheromone at one end of the chamber. The researchers observed that the pike oriented themselves toward the end of the chamber where the pheromone was released.

Which of the following questions will best guide a follow-up investigation about the role of pheromones in locating prey?

  • A: How do pike determine that the fathead minnow pheromone is present in the water?

  • B: Why do pike prey on fathead minnows?

  • C: Do pike have natural predators in the environment?

  • D: Do pike release pheromones that are detected by fathead minnows?

A: How do pike determine that the fathead minnow pheromone is present in the water?

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Which of the following best explains why a cell’s plasma membrane is composed of two layers of phospholipids rather than just a single layer?

  • A: Having two oppositely oriented layers of phospholipids allows only the hydrophilic heads to interact with water inside and outside of the cell.

  • B: Having two oppositely oriented layers of phospholipids allows the hydrophilic heads to repel water both inside and outside of the cells.

  • C: Having two identically oriented layers of phospholipids gives cells more protection from the exterior environment than just a single layer would.

  • D: Having two identically oriented layers of phospholipids allows for the production of vacuoles while still maintaining a protective barrier.

A: Having two oppositely oriented layers of phospholipids allows only the hydrophilic heads to interact with water inside and outside of the cell.

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<ul><li><p><strong>A: </strong><span>Simple squamous cells</span></p><p></p></li><li><p><strong>B: </strong><span>Simple cuboidal cells</span></p><p></p></li><li><p><strong>C: </strong><span>Simple columnar cells</span></p><p></p></li><li><p><strong>D: </strong><span>Simple spherical cells</span></p></li></ul><p></p>
  • A: Simple squamous cells

  • B: Simple cuboidal cells

  • C: Simple columnar cells

  • D: Simple spherical cells

A: Simple squamous cells

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48

Which of the following best explains how the extensive folding of the inner mitochondrial membrane benefits a eukaryotic cell?

  • A: It enlarges the volume of the matrix, which allows for more enzymatic reactions.

  • B: It increases the area available for proteins involved in energy transfer.

  • C: It allows for greater area for the diffusion of water into and out of the mitochondria.

  • D: It provides better insulation for reactions in the matrix from conditions outside the mitochondria.

B: It increases the area available for proteins involved in energy transfer.

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<ul><li><p><strong>A: </strong><span>The percentage of hatchlings that survive to adulthood is directly proportional to average nest temperature.</span></p><p></p></li><li><p><strong>B: </strong><span>Female sea turtles search for cooler beaches in order to have more male offspring.</span></p><p></p></li><li><p><strong>C: </strong>W<span>armer nests produce more female sea turtles than do cooler nests.</span></p><p></p></li><li><p><strong>D: </strong><span>The sex ratio of sea turtles is genetically determined.</span></p></li></ul><p></p>
  • A: The percentage of hatchlings that survive to adulthood is directly proportional to average nest temperature.

  • B: Female sea turtles search for cooler beaches in order to have more male offspring.

  • C: Warmer nests produce more female sea turtles than do cooler nests.

  • D: The sex ratio of sea turtles is genetically determined.

C: Warmer nests produce more female sea turtles than do cooler nests.

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<ul><li><p><strong>A: </strong><span>A fish that has mouth parts adapted to eat moderately sized prey is introduced into a lake in which there are only large and small prey.</span></p><p></p></li><li><p><strong>B: </strong><span>A population of mice live on the ground and in short trees. An invasive, tree-dwelling snake that preys on the mice is introduced into the area.</span></p><p></p></li><li><p><strong>C: </strong><span>Climate change-induced warming of arctic tundra reduces average snow cover that lighter-colored arctic foxes rely on for camouflage. Darker-colored arctic foxes are better suited to the exposed moss and grass habitat.</span></p><p></p></li><li><p><strong>D: </strong><span>House sparrows that lay smaller-than-average clutches of eggs produce fewer viable offspring, while larger-than-average clutches of eggs result in malnourished chicks that have a higher mortality rate.</span></p></li></ul><p></p>
  • A: A fish that has mouth parts adapted to eat moderately sized prey is introduced into a lake in which there are only large and small prey.

  • B: A population of mice live on the ground and in short trees. An invasive, tree-dwelling snake that preys on the mice is introduced into the area.

  • C: Climate change-induced warming of arctic tundra reduces average snow cover that lighter-colored arctic foxes rely on for camouflage. Darker-colored arctic foxes are better suited to the exposed moss and grass habitat.

  • D: House sparrows that lay smaller-than-average clutches of eggs produce fewer viable offspring, while larger-than-average clutches of eggs result in malnourished chicks that have a higher mortality rate.

D: House sparrows that lay smaller-than-average clutches of eggs produce fewer viable offspring, while larger-than-average clutches of eggs result in malnourished chicks that have a higher mortality rate.

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<ul><li><p><strong>A: </strong><span>Trabectedin increases the production of cyclin proteins that signal the cancer cells to enter prophase.</span></p><p></p></li><li><p><strong>B: </strong><span>Trabectedin interferes with the plasma membrane, causing it to break down and expose the DNA to damage.</span></p><p></p></li><li><p><strong>C: </strong><span>Trabectedin interferes with the duplication of DNA during interphase and thus prevents cancer cells from passing the G2 checkpoint.</span></p><p></p></li><li><p><strong>D: </strong><span>Trabectedin interferes with the regulations of cyclin proteins, causing their levels to increase and creating errors in DNA.</span></p></li></ul><p></p>
  • A: Trabectedin increases the production of cyclin proteins that signal the cancer cells to enter prophase.

  • B: Trabectedin interferes with the plasma membrane, causing it to break down and expose the DNA to damage.

  • C: Trabectedin interferes with the duplication of DNA during interphase and thus prevents cancer cells from passing the G2 checkpoint.

  • D: Trabectedin interferes with the regulations of cyclin proteins, causing their levels to increase and creating errors in DNA.

C: Trabectedin interferes with the duplication of DNA during interphase and thus prevents cancer cells from passing the G2 checkpoint.

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Friedreich’s ataxia is an inherited disorder. Friedreich’s ataxia is caused by an insertion mutation in a noncoding portion of the 𝐹𝑋𝑁 gene where a GAA triplet is repeated hundreds of times. The 𝐹𝑋𝑁 gene encodes the protein frataxin. A pedigree of a family with members affected by this disorder is shown in Figure 1.

The figure presents a pedigree of four generations, with each individual assigned a number in his or her generation. Generation 1 includes two sets of parents who are unaffected by Friedreich’s ataxia. They include female 1-1 who has a child with male 1-2 and female 1-3 who has children with male 1-4. In generation 2, the child born to female 1-1 and male 1-2 is an unaffected male, 2-1. Male 2-1 has two generation 3 children with an unaffected female, 2-2. Their generation 3 children are unaffected females, 3-1 and 3-2. Female 1-3 and male 1-4 have four generation 2 children, an unaffected female, 2-4, an affected female, 2-5, another unaffected female, 2-6, and an unaffected male, 2-7. Unaffected female 2-4 has four generation 3 children with an unaffected male, 2-3. Their four generation 3 children are an unaffected male, 3-3, an unaffected female, 3-4, a female, 3-5, who status is unknown and whose symbol is marked with a question mark, and an affected male, 3-6. The unaffected male, 3-3, has one generation 4 child with unaffected female 3-2. The child, 4-1, is an affected female.

Figure 1. A pedigree of a family affected by Friedreich’s ataxia

A researcher collected DNA from several members of the family and used PCR to amplify the FXN genes from each individual’s DNA. The researcher then used DNA gel electrophoresis to separate the DNA. The results are shown in Figure 2.

The figure presents a rectangle representing a gel. The first lane of the gel is labeled Known D N A Fragments. The next four lanes contain D N A from family members and are labeled 3-2, 3-3, 3-4, and 4-1. The left side of the rectangle is labeled Sizes of Known Fragments, in base pairs, and the following numbers are present, from top to bottom along the side: 3000, 1500, 500. Black rectangles in each lane represent the D N A fragments in the samples and have different thicknesses. The data are as follows. In the Known D N A Fragments lane, there is a thin black rectangle at 3000, a thick black rectangle at 1500, and a thick black rectangle at 500. In the 3 – 2 lane, there is a thin black rectangle between 3000 and 1500, and a thin black rectangle just above 500. In the 3 – 3 lane, there is a thin black rectangle between 3000 and 1500, and a thin black rectangle just above 500. In the 3 – 4 lane, there is a thick black rectangle just above 500. In the 4 – 1 lane, there is a thick black rectangle between 3000 and 1500.

Figure 2. 𝐹𝑋𝑁 gene fragment sizes for several family members. A sample of DNA with fragments of known lengths was used for comparison.

The researcher also used a computer to model the structure of the mutant 𝐹𝑋𝑁 allele. The model suggests that the repeated GAA triplets in the mutant 𝐹𝑋𝑁 gene may lead to the formation of an unusual triple-stranded configuration of DNA (Figure 3).

The figure presents a model of a D N A triple helix structure with a sequence that has multiple G A A and T T C triplets. One strand of DNA contains repeats of the sequence  T T C . The complementary strand contains repeats of the sequence A A G . The D N A forms a hairpin loop and folds back on itself so that there are four parallel strands of nucleotides. In the model, the top strand is unpaired and the three lower strands in the loop interact to form a triple helix structure. The second and third strands contain many repeats of the triplet A A G. The fourth strand contains many repeats of the sequence T T C. Dots between nucleotides on all three strands represent bonds holding the three strands together in the triple helix structure.

Figure 3. The modeled DNA triple-helix structure that can form in areas with multiple GAA triplets

Based on the data in Figure 1, which of the following best describes the inheritance pattern of Friedreich’s ataxia?

  • A: Autosomal recessive

  • B: Autosomal dominant

  • C: Sex-linked recessive

  • D: Sex-linked dominant

A: Autosomal recessive

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Friedreich’s ataxia is an inherited disorder. Friedreich’s ataxia is caused by an insertion mutation in a noncoding portion of the 𝐹𝑋𝑁 gene where a GAA triplet is repeated hundreds of times. The 𝐹𝑋𝑁 gene encodes the protein frataxin. A pedigree of a family with members affected by this disorder is shown in Figure 1.

The figure presents a pedigree of four generations, with each individual assigned a number in his or her generation. Generation 1 includes two sets of parents who are unaffected by Friedreich’s ataxia. They include female 1-1 who has a child with male 1-2 and female 1-3 who has children with male 1-4. In generation 2, the child born to female 1-1 and male 1-2 is an unaffected male, 2-1. Male 2-1 has two generation 3 children with an unaffected female, 2-2. Their generation 3 children are unaffected females, 3-1 and 3-2. Female 1-3 and male 1-4 have four generation 2 children, an unaffected female, 2-4, an affected female, 2-5, another unaffected female, 2-6, and an unaffected male, 2-7. Unaffected female 2-4 has four generation 3 children with an unaffected male, 2-3. Their four generation 3 children are an unaffected male, 3-3, an unaffected female, 3-4, a female, 3-5, who status is unknown and whose symbol is marked with a question mark, and an affected male, 3-6. The unaffected male, 3-3, has one generation 4 child with unaffected female 3-2. The child, 4-1, is an affected female.

Figure 1. A pedigree of a family affected by Friedreich’s ataxia

A researcher collected DNA from several members of the family and used PCR to amplify the FXN genes from each individual’s DNA. The researcher then used DNA gel electrophoresis to separate the DNA. The results are shown in Figure 2.

The figure presents a rectangle representing a gel. The first lane of the gel is labeled Known D N A Fragments. The next four lanes contain D N A from family members and are labeled 3-2, 3-3, 3-4, and 4-1. The left side of the rectangle is labeled Sizes of Known Fragments, in base pairs, and the following numbers are present, from top to bottom along the side: 3000, 1500, 500. Black rectangles in each lane represent the D N A fragments in the samples and have different thicknesses. The data are as follows. In the Known D N A Fragments lane, there is a thin black rectangle at 3000, a thick black rectangle at 1500, and a thick black rectangle at 500. In the 3 – 2 lane, there is a thin black rectangle between 3000 and 1500, and a thin black rectangle just above 500. In the 3 – 3 lane, there is a thin black rectangle between 3000 and 1500, and a thin black rectangle just above 500. In the 3 – 4 lane, there is a thick black rectangle just above 500. In the 4 – 1 lane, there is a thick black rectangle between 3000 and 1500.

Figure 2. 𝐹𝑋𝑁 gene fragment sizes for several family members. A sample of DNA with fragments of known lengths was used for comparison.

The researcher also used a computer to model the structure of the mutant 𝐹𝑋𝑁 allele. The model suggests that the repeated GAA triplets in the mutant 𝐹𝑋𝑁 gene may lead to the formation of an unusual triple-stranded configuration of DNA (Figure 3).

The figure presents a model of a D N A triple helix structure with a sequence that has multiple G A A and T T C triplets. One strand of DNA contains repeats of the sequence  T T C . The complementary strand contains repeats of the sequence A A G . The D N A forms a hairpin loop and folds back on itself so that there are four parallel strands of nucleotides. In the model, the top strand is unpaired and the three lower strands in the loop interact to form a triple helix structure. The second and third strands contain many repeats of the triplet A A G. The fourth strand contains many repeats of the sequence T T C. Dots between nucleotides on all three strands represent bonds holding the three strands together in the triple helix structure.

Figure 3. The modeled DNA triple-helix structure that can form in areas with multiple GAA triplets

The probability that individual III-5 will develop Friedreich’s ataxia is closest to which of the following?

  • A: 0%

  • B: 25%

  • C: 50%

  • D: 75%

B: 25%

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54

Friedreich’s ataxia is an inherited disorder. Friedreich’s ataxia is caused by an insertion mutation in a noncoding portion of the 𝐹𝑋𝑁 gene where a GAA triplet is repeated hundreds of times. The 𝐹𝑋𝑁 gene encodes the protein frataxin. A pedigree of a family with members affected by this disorder is shown in Figure 1.

The figure presents a pedigree of four generations, with each individual assigned a number in his or her generation. Generation 1 includes two sets of parents who are unaffected by Friedreich’s ataxia. They include female 1-1 who has a child with male 1-2 and female 1-3 who has children with male 1-4. In generation 2, the child born to female 1-1 and male 1-2 is an unaffected male, 2-1. Male 2-1 has two generation 3 children with an unaffected female, 2-2. Their generation 3 children are unaffected females, 3-1 and 3-2. Female 1-3 and male 1-4 have four generation 2 children, an unaffected female, 2-4, an affected female, 2-5, another unaffected female, 2-6, and an unaffected male, 2-7. Unaffected female 2-4 has four generation 3 children with an unaffected male, 2-3. Their four generation 3 children are an unaffected male, 3-3, an unaffected female, 3-4, a female, 3-5, who status is unknown and whose symbol is marked with a question mark, and an affected male, 3-6. The unaffected male, 3-3, has one generation 4 child with unaffected female 3-2. The child, 4-1, is an affected female.

Figure 1. A pedigree of a family affected by Friedreich’s ataxia

A researcher collected DNA from several members of the family and used PCR to amplify the FXN genes from each individual’s DNA. The researcher then used DNA gel electrophoresis to separate the DNA. The results are shown in Figure 2.

The figure presents a rectangle representing a gel. The first lane of the gel is labeled Known D N A Fragments. The next four lanes contain D N A from family members and are labeled 3-2, 3-3, 3-4, and 4-1. The left side of the rectangle is labeled Sizes of Known Fragments, in base pairs, and the following numbers are present, from top to bottom along the side: 3000, 1500, 500. Black rectangles in each lane represent the D N A fragments in the samples and have different thicknesses. The data are as follows. In the Known D N A Fragments lane, there is a thin black rectangle at 3000, a thick black rectangle at 1500, and a thick black rectangle at 500. In the 3 – 2 lane, there is a thin black rectangle between 3000 and 1500, and a thin black rectangle just above 500. In the 3 – 3 lane, there is a thin black rectangle between 3000 and 1500, and a thin black rectangle just above 500. In the 3 – 4 lane, there is a thick black rectangle just above 500. In the 4 – 1 lane, there is a thick black rectangle between 3000 and 1500.

Figure 2. 𝐹𝑋𝑁 gene fragment sizes for several family members. A sample of DNA with fragments of known lengths was used for comparison.

The researcher also used a computer to model the structure of the mutant 𝐹𝑋𝑁 allele. The model suggests that the repeated GAA triplets in the mutant 𝐹𝑋𝑁 gene may lead to the formation of an unusual triple-stranded configuration of DNA (Figure 3).

The figure presents a model of a D N A triple helix structure with a sequence that has multiple G A A and T T C triplets. One strand of DNA contains repeats of the sequence  T T C . The complementary strand contains repeats of the sequence A A G . The D N A forms a hairpin loop and folds back on itself so that there are four parallel strands of nucleotides. In the model, the top strand is unpaired and the three lower strands in the loop interact to form a triple helix structure. The second and third strands contain many repeats of the triplet A A G. The fourth strand contains many repeats of the sequence T T C. Dots between nucleotides on all three strands represent bonds holding the three strands together in the triple helix structure.

Figure 3. The modeled DNA triple-helix structure that can form in areas with multiple GAA triplets

Which of the following statements best describes the results seen in Figure 2

  • A: Individuals III-2 and III-3 carry two different alleles of the 𝐹𝑋𝑁 gene, a mutant allele and a wild-type allele. Individual IV-1 inherited two copies of the mutant allele.

  • B: Individuals III-2 and III-3 carry two different alleles of the 𝐹𝑋𝑁 gene, a mutant allele and a wild-type allele. Individual IV-1 inherited two copies of the wild-type allele.

  • C: Individuals III-2 and III-3 both carry two wild-type alleles. Individual IV-1 inherited two copies of the wild-type allele.

  • D: Individuals III-2 and III-3 both carry two wild-type alleles, but individual IV-1 inherited one copy of the wild-type allele and one copy of the mutant allele.

A: Individuals III-2 and III-3 carry two different alleles of the 𝐹𝑋𝑁 gene, a mutant allele and a wild-type allele. Individual IV-1 inherited two copies of the mutant allele.

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55

Friedreich’s ataxia is an inherited disorder. Friedreich’s ataxia is caused by an insertion mutation in a noncoding portion of the 𝐹𝑋𝑁 gene where a GAA triplet is repeated hundreds of times. The 𝐹𝑋𝑁 gene encodes the protein frataxin. A pedigree of a family with members affected by this disorder is shown in Figure 1.

The figure presents a pedigree of four generations, with each individual assigned a number in his or her generation. Generation 1 includes two sets of parents who are unaffected by Friedreich’s ataxia. They include female 1-1 who has a child with male 1-2 and female 1-3 who has children with male 1-4. In generation 2, the child born to female 1-1 and male 1-2 is an unaffected male, 2-1. Male 2-1 has two generation 3 children with an unaffected female, 2-2. Their generation 3 children are unaffected females, 3-1 and 3-2. Female 1-3 and male 1-4 have four generation 2 children, an unaffected female, 2-4, an affected female, 2-5, another unaffected female, 2-6, and an unaffected male, 2-7. Unaffected female 2-4 has four generation 3 children with an unaffected male, 2-3. Their four generation 3 children are an unaffected male, 3-3, an unaffected female, 3-4, a female, 3-5, who status is unknown and whose symbol is marked with a question mark, and an affected male, 3-6. The unaffected male, 3-3, has one generation 4 child with unaffected female 3-2. The child, 4-1, is an affected female.

Figure 1. A pedigree of a family affected by Friedreich’s ataxia

A researcher collected DNA from several members of the family and used PCR to amplify the FXN genes from each individual’s DNA. The researcher then used DNA gel electrophoresis to separate the DNA. The results are shown in Figure 2.

The figure presents a rectangle representing a gel. The first lane of the gel is labeled Known D N A Fragments. The next four lanes contain D N A from family members and are labeled 3-2, 3-3, 3-4, and 4-1. The left side of the rectangle is labeled Sizes of Known Fragments, in base pairs, and the following numbers are present, from top to bottom along the side: 3000, 1500, 500. Black rectangles in each lane represent the D N A fragments in the samples and have different thicknesses. The data are as follows. In the Known D N A Fragments lane, there is a thin black rectangle at 3000, a thick black rectangle at 1500, and a thick black rectangle at 500. In the 3 – 2 lane, there is a thin black rectangle between 3000 and 1500, and a thin black rectangle just above 500. In the 3 – 3 lane, there is a thin black rectangle between 3000 and 1500, and a thin black rectangle just above 500. In the 3 – 4 lane, there is a thick black rectangle just above 500. In the 4 – 1 lane, there is a thick black rectangle between 3000 and 1500.

Figure 2. 𝐹𝑋𝑁 gene fragment sizes for several family members. A sample of DNA with fragments of known lengths was used for comparison.

The researcher also used a computer to model the structure of the mutant 𝐹𝑋𝑁 allele. The model suggests that the repeated GAA triplets in the mutant 𝐹𝑋𝑁 gene may lead to the formation of an unusual triple-stranded configuration of DNA (Figure 3).

The figure presents a model of a D N A triple helix structure with a sequence that has multiple G A A and T T C triplets. One strand of DNA contains repeats of the sequence  T T C . The complementary strand contains repeats of the sequence A A G . The D N A forms a hairpin loop and folds back on itself so that there are four parallel strands of nucleotides. In the model, the top strand is unpaired and the three lower strands in the loop interact to form a triple helix structure. The second and third strands contain many repeats of the triplet A A G. The fourth strand contains many repeats of the sequence T T C. Dots between nucleotides on all three strands represent bonds holding the three strands together in the triple helix structure.

Figure 3. The modeled DNA triple-helix structure that can form in areas with multiple GAA triplets

Which of the following best describes the most likely effect of the formation of a triplex DNA structure (Figure 3) on the synthesis of the frataxin protein?

  • A: The binding of the ribosome to the mRNA is prevented, resulting in a decrease in frataxin translation.

  • B: The DNA will not degrade in the cytoplasm, leading to an increase in frataxin translation.

  • C: RNA polymerase is prevented from binding to the DNA, resulting in a decrease in frataxin mRNA transcription.

  • D: The protein will include extra amino acids, resulting in a protein with an altered secondary structure.

C: RNA polymerase is prevented from binding to the DNA, resulting in a decrease in frataxin mRNA transcription.

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56

Friedreich’s ataxia is an inherited disorder. Friedreich’s ataxia is caused by an insertion mutation in a noncoding portion of the 𝐹𝑋𝑁 gene where a GAA triplet is repeated hundreds of times. The 𝐹𝑋𝑁 gene encodes the protein frataxin. A pedigree of a family with members affected by this disorder is shown in Figure 1.

The figure presents a pedigree of four generations, with each individual assigned a number in his or her generation. Generation 1 includes two sets of parents who are unaffected by Friedreich’s ataxia. They include female 1-1 who has a child with male 1-2 and female 1-3 who has children with male 1-4. In generation 2, the child born to female 1-1 and male 1-2 is an unaffected male, 2-1. Male 2-1 has two generation 3 children with an unaffected female, 2-2. Their generation 3 children are unaffected females, 3-1 and 3-2. Female 1-3 and male 1-4 have four generation 2 children, an unaffected female, 2-4, an affected female, 2-5, another unaffected female, 2-6, and an unaffected male, 2-7. Unaffected female 2-4 has four generation 3 children with an unaffected male, 2-3. Their four generation 3 children are an unaffected male, 3-3, an unaffected female, 3-4, a female, 3-5, who status is unknown and whose symbol is marked with a question mark, and an affected male, 3-6. The unaffected male, 3-3, has one generation 4 child with unaffected female 3-2. The child, 4-1, is an affected female.

Figure 1. A pedigree of a family affected by Friedreich’s ataxia

A researcher collected DNA from several members of the family and used PCR to amplify the FXN genes from each individual’s DNA. The researcher then used DNA gel electrophoresis to separate the DNA. The results are shown in Figure 2.

The figure presents a rectangle representing a gel. The first lane of the gel is labeled Known D N A Fragments. The next four lanes contain D N A from family members and are labeled 3-2, 3-3, 3-4, and 4-1. The left side of the rectangle is labeled Sizes of Known Fragments, in base pairs, and the following numbers are present, from top to bottom along the side: 3000, 1500, 500. Black rectangles in each lane represent the D N A fragments in the samples and have different thicknesses. The data are as follows. In the Known D N A Fragments lane, there is a thin black rectangle at 3000, a thick black rectangle at 1500, and a thick black rectangle at 500. In the 3 – 2 lane, there is a thin black rectangle between 3000 and 1500, and a thin black rectangle just above 500. In the 3 – 3 lane, there is a thin black rectangle between 3000 and 1500, and a thin black rectangle just above 500. In the 3 – 4 lane, there is a thick black rectangle just above 500. In the 4 – 1 lane, there is a thick black rectangle between 3000 and 1500.

Figure 2. 𝐹𝑋𝑁 gene fragment sizes for several family members. A sample of DNA with fragments of known lengths was used for comparison.

The researcher also used a computer to model the structure of the mutant 𝐹𝑋𝑁 allele. The model suggests that the repeated GAA triplets in the mutant 𝐹𝑋𝑁 gene may lead to the formation of an unusual triple-stranded configuration of DNA (Figure 3).

The figure presents a model of a D N A triple helix structure with a sequence that has multiple G A A and T T C triplets. One strand of DNA contains repeats of the sequence  T T C . The complementary strand contains repeats of the sequence A A G . The D N A forms a hairpin loop and folds back on itself so that there are four parallel strands of nucleotides. In the model, the top strand is unpaired and the three lower strands in the loop interact to form a triple helix structure. The second and third strands contain many repeats of the triplet A A G. The fourth strand contains many repeats of the sequence T T C. Dots between nucleotides on all three strands represent bonds holding the three strands together in the triple helix structure.

Figure 3. The modeled DNA triple-helix structure that can form in areas with multiple GAA triplets

Which of the following types of bonds is most likely responsible for the unusual base pairing shown in Figure 3 that results in the formation of a triplex DNA structure?

  • A: Hydrogen

  • B: Polar covalent

  • C: Ionic

  • D: Nonpolar covalent

A: Hydrogen

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57
<ul><li><p><strong>A: </strong>0.1</p><p></p></li><li><p><strong>B: </strong>1.9</p><p></p></li><li><p><strong>C: </strong>18.3</p><p></p></li><li><p><strong>D: </strong>23.1</p></li></ul><p></p>
  • A: 0.1

  • B: 1.9

  • C: 18.3

  • D: 23.1

D: 23.1

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58

Scientists compared the chemical structure of several molecules that various bacterial species use for quorum sensing. Quorum sensing is an ability some bacteria have to detect the number of related cells nearby. The chemical structure of some of these molecules found in certain species of bacteria are shown in Figure 1.

The figure presents the chemical structure of three molecules. From top to bottom the molecules are labeled with the species of bacteria that produce them: Vibrio fischeri, Vibrio harveyi, and Pseudomonas aeruginosa. Each molecule is composed of an identical five-sided ring structure. The ring contains an oxygen atom, and another oxygen atom is double bonded to a carbon in the top of the ring. Each of the three molecules has a different hydrocarbon chain coming off the same position of the ring. The hydrocarbon chain of the Vibrio fischeri molecule is seven atoms long. The first atom is a nitrogen, and it is followed by six carbons. Oxygen atoms are double-bonded to the second and fourth carbons. The hydrocarbon chain of the Vibrio harveyi molecule is five atoms long. The first atom is a nitrogen, and it is followed by four carbons. An oxygen atom is double-bonded to the second carbon, and a hydroxyl group is attached to the fourth carbon. The hydrocarbon chain of Pseudomonas aeruginosa molecule is five atoms long. The first atom is a nitrogen, and it is followed by four carbons. An oxygen atom is double-bonded to the second carbon.

Figure 1. The chemical structure of several molecules used for quorum sensing in three species of bacteria

Which of the following research questions would best guide an investigation of the link between the structure of the signaling molecules and the evolution of quorum sensing?

  • A: Do these molecules require the same receptors in each bacteria species to generate a response?

  • B: Did these species evolve from a common ancestor that used a similar signaling molecule?

  • C: Do these species all perform the same action when the concentration of the signaling molecules is high enough?

  • D: Did these species evolve from the same common ancestor that is still living today and uses the same receptors?

  • B: Did these species evolve from a common ancestor that used a similar signaling molecule?

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59

Carbon dioxide most likely enters a cell through which of the following processes?

  • A: Simple diffusion through the membrane

  • B: Facilitated diffusion through membrane proteins

  • C: Active transport through membrane proteins

  • D: Active transport through aquaporins

A: Simple diffusion through the membrane

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60

In pea seeds, yellow color (𝑌) is dominant to green color (𝑦), and a round shape (𝑅) is dominant to a wrinkled shape (𝑟). A dihybrid cross between a true-breeding plant with yellow, round seeds (𝑌𝑌𝑅𝑅) and a true-breeding plant with green, wrinkled seeds (𝑦𝑦𝑟𝑟) results in an F1 generation of plants with yellow, round seeds. Crossing two F1 plants produces an F2 generation with approximately nine times as many plants with yellow, round seeds as plants with green, wrinkled seeds.

Which of the following best explains these results?

  • A: The allele pairs of each parent stay together, resulting in gametes that are identical to the parents.

  • B: Gene segments on sister chromatids cross over.

  • C: Alleles that are on nonhomologous chromosomes recombine.

  • D: The genes for seed color and seed shape assort independently.

  • D: The genes for seed color and seed shape assort independently.

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