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Grignard Trend (strongest to weakest)
I > Br > Cl > > > F
Carboxylation of Grignard Reagent
Mg
CO2
H3O+
Acetal Formation
start with an aldehyde or a ketone. NO CARBOX ACID
react with 2 equivalents of alcohol (R-OH)
the alcohol is the nucleophile
the order is acid nuc nuc acid nuc nuc
the acids only protonate, the nucs either add on or deprotonate
Reagents that Oxidize to Carboxylic Acids/Make them
Na2Cr2O7/H2SO4/H2O/heat
KMNO4/OH-/heat
ozonolysis of an alkene
carboxylation of grignard (the thing with CO2)
LiAlH4
reduces a carboxylic acid to a primary alcohol. ALWAYS a PRIMARY alcohol. reduces basically everything except alkenes and alkynes
the carbonyl carbon takes an H from the Li thing but the arrow is coming from the bond of H to Al (idk why?)
the oxide? that was the carbonyl oxygen then attacks the Al of the AlH3 situation and Li is just floating around
the Al stuff can still react so basically acid workup happens where the bond of the now FOUR Al things takes an H from an acid and the Al thing just comes off
you should end up with FOUR PRIMARY ALCOHOLS and some like water and Li and Al
Imine Formation
start with ONLY KETONE or ALDEHYDE, not carboxylic acid
needs primary AMINE
the amine adds SN2-like at first
there is a “leave as water” step
in the end there is a C to N DOUBLE BOND
Enamine formation
the same as imine formation
SECONDARY AMINE USED
in the end there is a C to C DOUBLE BOND bc u take a beta hydrogen
Wittig Reaction
KETONE/ALDEHYDE to ALKENE
use the PPh3 ylid thing
forms a box at some point
u should end up with at least O double bond PPh3
unstable ylid=CIS
stable ylid=adjacent EWG and resonance stablized=TRANS
Least Stable to Most Stable, Most Reactive to Least Reactive
acid chloride
anhydride
imide
aldehyde
ketone
lactone
ester
lactom
amide
nitrile
imine
carboxylate
Carboxylic Acid Reactions that are Acidic Conditions
esterification
acetal formation
imine formation
PROTONATE THE CARBONYL OXYGEN
Carboxylic Acid Reactions that are Basic Conditions
Saponification
Grignard
Reduction
Amidation?
DEPROTONATE
Acidity
alkyl groups=negliglable effect
halogens=higher EN means higher acidity
the closer halogens are to the carbonyl, the more acidic they are
double and triple bond=more acidic
Acid Catalyzed Esterification
need an alcohol and some acid
carbonyl oxygen deprotonates the acid (except sometimes the alc takes an H from the acid?? idk bro)
shuffle stuff around until water leaves
you should end up with carbonyl bound to an oxygen thats bound to an R group
the O next to R in the product is always from the nucleophile/alcohol
Making Acid Chlorides
Use Thionyl Chloride
the carbonyl O is NOT getting protonated here, it really doesnt do anything
the OH oxygen on carbox acid attacks the sulfur bc the sulfur really wants electrons
one of the chlorides leaves but it comes back later and adds onto the carbonyl carbon
that rlly big thing with the O connected to the sulfur leaves at some point
Base Reaction
base will deprotonate that OH
then u can do like SN2 with the resulting carboxylate
Synthesis of Symmetrical Anhydride
use a catalyst like P2O5, POCl3, or P4H10
its that thing with the like 2 carbonyls and O in the middle connecting them
Synthesis of Asymmetrical Anhydrides
use a base like NEt3, ofc that deprotonates to make ur carboxylate
do some SN2 type stuff on a carbonyl with a LG
the leaving group leaves duh
boom anhydride
Decarboxylation
simple carbox acids dont do allat
u need alpha-beta-keto carbox acid
malonic acid and its relatives like to decarboxylate tho
u need heat
its kind of like a cyclic mechanism, basically a CO2 should be leaving or else yikes
the carbonyl with the R group on it takes the H from OH, then u should see that CO2 should leave idk
should be forming a ketone
Saponification
“base” attaches to carbonyl
that O-R thing gets kicked off
the kicked off O-R deprotonates the base that got added, forms that ion thing
the ion thing gets protonated by acid, done
Acid Cat. Hydrolysis: Amide to Carboxylic Acid
acidic conditions, so acid protonates O of carbonyl first
then the water/base/nucleophile? attacks the carbonyl carbon
then water deprotonates the water that just got added, that new water turns into H3O+
the nitrogen takes an H from h3o+ (becomes water), the whole nitrogen group thing leaves and the carbonyl oxygen slams down its lone pair
then the water deprotonates the carbonyl oxygen, becomes H3O+, that H3O+ protonates the nitrogen thing that came off
then done 2 products
NaBH4 in Alcohol Solution
some type of cyclic situation is happening first, so the carbonyl oxygen takes an H from the alcohol solvent. then the bond between a H and the like OCH3 part of the alcohol attacks the B. then the bond between BH3 and H attacks the carbonyl carbon
thats it
reduces aldehydes and ketones, nothing else really
Acid Catalyzed Hydrolysis of Nitriles in Acid
use H2SO4 in water and heat
the water takes an H from the H2SO4. VERY IMPORTANT. becomes H3O+
then the nitrogen takes an H from. H3O+
do the resonance structure where a lone pair ends up on nitrogen and there is a double bond instead of triple
water attacks the carbon of that double bond
another water deprotonates the attached water
the lone pairs on nitrogen take an H from the new H3O+
tautomerization-aka the lone pair on oxygen slams down to form carbonyl, the double bond with nitrogen is kicked out and turns into lone pair on N
then you deprotonate the carbonyl oxygen with water
boom done, but the product is lowkey still prone to hydrolysis