Chapter 21: Alpha Carbon Chemistry

0.0(0)
studied byStudied by 0 people
GameKnowt Play
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/17

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

18 Terms

1
New cards

Enol & Enolate Intermediates

reactions occur either through enol or enolate intermediates

*must have ⍺ carbon

enolates are more reactive than enols b/c the ⊖ charge on O

<p>reactions occur either through enol or enolate intermediates</p><p>*must have ⍺ carbon</p><p>enolates are more reactive than enols b/c the ⊖ charge on O</p>
2
New cards

Enol Intermediates

in presence of catalytic base or acid

→ ketone exists in equilibrium w/ enol

ketone & enol are tautomers

(not resonance structures)

equilibrium favors ketone (99%) unless:

1) conjugated system → favors enol

2) intramolecular H-bond (like in diketone) → favors enol

enol is very reactive b/c its ⍺ carbon is very nucleophilic

(OH activates carbon)

<p>in presence of catalytic base or acid</p><p>→ ketone exists in equilibrium w/ enol</p><p>ketone &amp; enol are tautomers </p><p>(not resonance structures)</p><p>equilibrium favors ketone (99%) unless:</p><p>1) conjugated system → favors enol</p><p>2) intramolecular H-bond (like in diketone) → favors enol</p><p>enol is very reactive b/c its ⍺ carbon is very nucleophilic</p><p>(OH activates carbon)</p>
3
New cards

Acid-Catalyzed Tautomerization

Starting Material: Ketone

Acidic Tautomerization → Enol

Reagents: H3O+

*assume tautomerization will occur if possible

<p>Starting Material: Ketone</p><p>Acidic Tautomerization → Enol</p><p>Reagents: H3O+</p><p>*assume tautomerization will occur if possible</p>
4
New cards

Base-Catalyzed Tautomerization

Starting Material: Ketone

Basic Tautomerization → Enol

Reagents: OH-

*assume tautomerization will occur if possible

<p>Starting Material: Ketone</p><p>Basic Tautomerization → Enol</p><p>Reagents: OH-</p><p>*assume tautomerization will occur if possible</p>
5
New cards

Enolate Intermediates

⍺ carbon of ketone treated w/ strong base → enolate intermediate

enolates have 2 nucleophilic sites: O & C

(C attacks are more common)

<p>⍺ carbon of ketone treated w/ strong base → enolate intermediate</p><p>enolates have 2 nucleophilic sites: O &amp; C</p><p>(C attacks are more common)</p>
6
New cards

pKa Values Predicting Equilibrium Shift

similar pKa values (milder base)

→ both reactants & enolate present

strong base like NaH/LDA used

→ only enolate present (irreversible)

diketone reactant → mild base is sufficient to ensure irreversible enolate

<p>similar pKa values (milder base) </p><p>→ both reactants &amp; enolate present</p><p>strong base like NaH/LDA used </p><p>→ only enolate present (irreversible)</p><p>diketone reactant → mild base is sufficient to ensure irreversible enolate </p>
7
New cards

Alpha Halogenation in Basic Conditions

Starting Material: Aldehyde/Ketone

Basic Alpha Halogenation → all ⍺ protons replaced w/ Br

Reagents: NaOH, Br2

Intermediate: Enolate

*if unsymmetrical, Br added to more substituted side

<p>Starting Material: Aldehyde/Ketone</p><p>Basic Alpha Halogenation → all ⍺ protons replaced w/ Br</p><p>Reagents: NaOH, Br2</p><p>Intermediate: Enolate</p><p>*if unsymmetrical, Br added to more substituted side</p>
8
New cards

Haloform Reaction

Starting Material: Tribromomethyl

Haloform Reaction → Carboxylic Acid

Reagents: 1) NaOH, Br2 / 2) H3O+

Intermediate: -CBr3 (good LG)

<p>Starting Material: Tribromomethyl</p><p>Haloform Reaction → Carboxylic Acid</p><p>Reagents: 1) NaOH, Br2 / 2) H3O+</p><p>Intermediate: -CBr3 (good LG)</p>
9
New cards

Alpha Halogenation in Acidic Conditions

Starting Material: Aldehyde/Ketone

Acidic Alpha Halogenation → 1 ⍺ proton replaced w/ Br

Reagents: H3O+, Br2

Intermediate: Enol

*if unsymmetrical, Br added to more substituted side

<p>Starting Material: Aldehyde/Ketone</p><p>Acidic Alpha Halogenation → 1 ⍺ proton replaced w/ Br</p><p>Reagents: H3O+, Br2</p><p>Intermediate: Enol</p><p>*if unsymmetrical, Br added to more substituted side</p>
10
New cards

Aldol Addition Reaction

Starting Material: Aldehyde

Aldol Addition → ꞵ-Hydroxy Aldehyde/Ketone (OH at ꞵ)

Reagents: H3O+, Br2

Intermediate: Enolate

*reversible → retro-aldol reaction

<p>Starting Material: Aldehyde</p><p>Aldol Addition → ꞵ-Hydroxy Aldehyde/Ketone (OH at ꞵ)</p><p>Reagents: H3O+, Br2</p><p>Intermediate: Enolate</p><p>*reversible → retro-aldol reaction</p>
11
New cards

Aldol Condensation Reaction

aldol condensation = aldol addition + elimination

Starting Material: Aldehyde/Ketone

Aldol Condensation → ⍺,ꞵ-Unsaturated Aldehyde/Ketone

Reagents: NaOH, H2O, heat

*driving force → increased conjugation

<p>aldol condensation = aldol addition + elimination</p><p>Starting Material: Aldehyde/Ketone</p><p>Aldol Condensation → ⍺,ꞵ-Unsaturated Aldehyde/Ketone</p><p>Reagents: NaOH, H2O, heat</p><p>*driving force → increased conjugation</p>
12
New cards

Crossed Aldol Reaction

getting 1 product btwn different aldehydes/ketones

1) 1 Aldehyde/Ketone Lacks ⍺ Proton → Not Enolizable

Reagents: NaOH, H2O

2) Strong Base (NaH or LDA) → 3 Steps

Reagents: 1) NaH (or LDA) / 2) Aldehyde/Ketone / 3) H2O

<p>getting 1 product btwn different aldehydes/ketones</p><p>1) 1 Aldehyde/Ketone Lacks ⍺ Proton → Not Enolizable</p><p>Reagents: NaOH, H2O</p><p>2) Strong Base (NaH or LDA) → 3 Steps </p><p>Reagents: 1) NaH (or LDA) / 2) Aldehyde/Ketone / 3) H2O</p>
13
New cards

Claisen Condensation Reaction

Starting Material: Ester

Claisen Condensation → ꞵ-Keto Estr

Reagents: 1) NaOEt / 2) H3O+

Intermediate: Ester Enolate

*RO groups must be the same

<p>Starting Material: Ester</p><p>Claisen Condensation → ꞵ-Keto Estr</p><p>Reagents: 1) NaOEt / 2) H3O+</p><p>Intermediate: Ester Enolate</p><p>*RO groups must be the same </p>
14
New cards

Crossed Claisen Condensation Reaction

getting 1 product btwn different esters

1) 1 Ester Lacks ⍺ Proton → Not Enolizable

Reagents: 1) NaOMe / 2) H3O+

2) Strong Base (NaH or LDA) → 3 Steps

Reagents: 1) NaH (or LDA) / 2) Ester / 3) H3O+

<p>getting 1 product btwn different esters</p><p>1) 1 Ester Lacks ⍺ Proton → Not Enolizable</p><p>Reagents: 1) NaOMe / 2) H3O+</p><p>2) Strong Base (NaH or LDA) → 3 Steps </p><p>Reagents: 1) NaH (or LDA) / 2) Ester / 3) H3O+</p>
15
New cards

Alkylation of ⍺ Position

Starting Material: Ketone

1) Small Base (NaH) → R Added at More Substituted

Reagents: 1) NaH / 2) RX

2) Bulky Base (LDA) → R Added at Least Substituted

Reagents: 1) LDA / 2) RX

<p>Starting Material: Ketone</p><p>1) Small Base (NaH) → R Added at More Substituted </p><p>Reagents: 1) NaH / 2) RX</p><p>2) Bulky Base (LDA) → R Added at Least Substituted</p><p>Reagents: 1) LDA / 2) RX</p>
16
New cards

Malonic Ester Synthesis

Starting Material: Large Ester Compound

Malonic Ester Synthesis → Basic Carboxylic Acid

Reagents: 1) NaOMe, MeOH / 2) MeBr / 3) NaOMe, MeOH / 4) EtBr / 5) H3O+, heat

*forms CO2 by-product

<p>Starting Material: Large Ester Compound</p><p>Malonic Ester Synthesis → Basic Carboxylic Acid</p><p>Reagents: 1) NaOMe, MeOH / 2) MeBr / 3) NaOMe, MeOH / 4) EtBr / 5) H3O+, heat</p><p>*forms CO2 by-product</p>
17
New cards

Michael Acceptors vs Donors

Michael Acceptor (E+) → ⍺,ꞵ-Unsaturated Compound

*unique reactivity: 2 E+ positions

Michael Donor (Nuc-) → Enolate Ion

*large & weak compound (favors attack at ꞵ carbon)

<p>Michael Acceptor (E+) → ⍺,ꞵ-Unsaturated Compound</p><p>*unique reactivity: 2 E+ positions</p><p>Michael Donor (Nuc-) → Enolate Ion</p><p>*large &amp; weak compound (favors attack at ꞵ carbon)</p>
18
New cards

Michael Synthesis

Starting Material: Michael Donor (Nuc-)

Michael Synthesis → Combines Donor + Acceptor

Reagents: 1) KOH / 2) Michael Acceptor (E+) / 3) H3O+

*keto-enol tautomerization occurs after product is formed

<p>Starting Material: Michael Donor (Nuc-)</p><p>Michael Synthesis → Combines Donor + Acceptor</p><p>Reagents: 1) KOH / 2) Michael Acceptor (E+) / 3) H3O+</p><p>*keto-enol tautomerization occurs after product is formed</p>