inverse trig derivatives

d/dx sin^-1u =

1/(1 - u^2)^1/2 du/dx

d/dx cos^-1u =

-1/(1 - u^2)^1/2 du/dx

d/dx tan^-1u =

1/(1 + u^2) du/dx

d/dx cot^-1u =

-1/(1 + u^2) du/dx

d/dx sec^-1u =

1/(|u| (u^2 - 1)^1/2) du/dx

d/dx csc^-1u =

1/(|u| (u^2 - 1)^1/2) du/dx