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inverse trig derivatives
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1
d/dx sin^-1u =
1/(1 - u^2)^1/2 du/dx
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2
d/dx cos^-1u =
-1/(1 - u^2)^1/2 du/dx
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3
d/dx tan^-1u =
1/(1 + u^2) du/dx
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4
d/dx cot^-1u =
-1/(1 + u^2) du/dx
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5
d/dx sec^-1u =
1/(|u| (u^2 - 1)^1/2) du/dx
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6
d/dx csc^-1u =
1/(|u| (u^2 - 1)^1/2) du/dx
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