inverse trig derivatives

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d/dx sin^-1u =

1/(1 - u^2)^1/2 du/dx

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d/dx cos^-1u =

-1/(1 - u^2)^1/2 du/dx

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d/dx tan^-1u =

1/(1 + u^2) du/dx

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d/dx cot^-1u =

-1/(1 + u^2) du/dx

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d/dx sec^-1u =

1/(|u| (u^2 - 1)^1/2) du/dx

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d/dx csc^-1u =

1/(|u| (u^2 - 1)^1/2) du/dx

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