IB Analysis Unit 6: Complex Numbers

studied byStudied by 0 people
0.0(0)
Get a hint
Hint

Complex numbers

1 / 16

flashcard set

Earn XP

17 Terms

1

Complex numbers

a number with both a real and imaginary part, often displayed in the form

a+bi

New cards
2

Complex conjugate

the conjugate of a complex number. Switch the sign in between a and b to it’s inverse.

New cards
3

equal

complex numbers are ______ if the real parts are equal and the imaginary parts are equal

New cards
4

argand diagram

diagrams drawn to represent complex number on a graph. One axis is for imaginary numbers, one is for real numbers. You can graph an a+bi imaginary number using this.

New cards
5

modulus

represented by r or |z|, represents the size of a complex number

√a2+b2

New cards
6

argument

represents the angle of a complex number (z), represented by θ

tan-1(b/a) when z is in quadrant 1

tan-1(b/a)+π when z is in quadrant 2, 3

tan-1(b/a)+2π when z is in quadrant 4

New cards
7

polar form

what form of a complex number is this?

z=r(cosθ+i sinθ)

New cards
8

muliply, add

when you multiply complex numbers, you ________ the moduli and ______ their arguments

New cards
9

DeMoivre’s Theorem

given z=r cisθ, the nth power of z=

zn=rn cis nθ

New cards
10

dilate

multiplying a complex number, z, by a positive real number, k, will ______ the vector z by a factor of k in the plane

New cards
11

180

multiplying a complex number, z, by -1 is equivalent to rotating z by _____ degrees in the complex plane

New cards
12

90

multiplying a complex number, z, by i, (an imaginary number) is equivalent to rotating z by ___ degrees counterclockwise in the complex plane.

New cards
13

rotate

multiplying z by k cis θ will _______ z by θ counterclockwise and scale the modulus of z by k in the plane

New cards
14

roots of unity

xn=1 where the equation has exactly n solutions on the unit circle that are equidistant from each other

New cards
15

generic complex roots

solutions to xn=z where z is a complex number. There will be n solutions.

New cards
16

complex conjugate theorem

a theorem that states that if a+bi is a root of a polynomial then a-bi is also a root. Corresponding factors would be (x-(a+bi)) and (x-(a-bi))

New cards
17

fundamental theorem of algebra

a polynomial of degree n has n complex factors and corresponding roots.

New cards

Explore top notes

note Note
studied byStudied by 18 people
... ago
5.0(1)
note Note
studied byStudied by 36 people
... ago
5.0(1)
note Note
studied byStudied by 9 people
... ago
5.0(1)
note Note
studied byStudied by 22 people
... ago
5.0(1)
note Note
studied byStudied by 6 people
... ago
5.0(1)
note Note
studied byStudied by 5 people
... ago
5.0(1)
note Note
studied byStudied by 12 people
... ago
5.0(1)
note Note
studied byStudied by 91 people
... ago
5.0(2)

Explore top flashcards

flashcards Flashcard (54)
studied byStudied by 33 people
... ago
5.0(1)
flashcards Flashcard (166)
studied byStudied by 76 people
... ago
5.0(2)
flashcards Flashcard (30)
studied byStudied by 1 person
... ago
5.0(1)
flashcards Flashcard (30)
studied byStudied by 5 people
... ago
5.0(1)
flashcards Flashcard (135)
studied byStudied by 2 people
... ago
5.0(1)
flashcards Flashcard (71)
studied byStudied by 3 people
... ago
5.0(1)
flashcards Flashcard (303)
studied byStudied by 15 people
... ago
5.0(1)
flashcards Flashcard (26)
studied byStudied by 20 people
... ago
5.0(2)
robot