moving up, +a
moving down, -a
Fa = mg + ma
moving up, -a
moving down, +a
Fa = mg - ma
distance
how far something moves (path it takes)
displacement
change in distance (straight line)
acceleration along a frictionless slope
ax = ±g*sinθ
direction of frictional force
opposite of the way the object would move w/o friction
harder to make an object move
higher value of µ
magnitude of kinetic friction
independent of object's speed
static friction (fs)
magnitude ≤ fsmax = µsn, direction as necessary to prevent motion
kinetic friction (fk)
= µkn, direction opposite motion
rolling friction (fr)
= µrn, direction opposite motion
terminal speed
speed at which the exact balance between the upward drag force & the downward weight force causes an object to fall w/o acceleration
acceleration for uniform circular motion
a = v²r
decreases with increased distance from center of circle
centrifugal force (away from center)
F = mv²/r
apparent weight @ bottom of circle
wapp = n = w + (mv²)/r
apparent weight @ top of circle
wapp = n = (mv²)/r - w
more inertial mass
less rotational acceleration (α)
less inertial mass
more rotational acceleration (α)
pulling an object at an angle is...
EASIER because there is less normal force -> less friction
equation for torque
t = r⊥F = r*Fsinθ
generally, every point on a rotating rigid body has the same ANGULAR velo
however, a point farther from an object's axis of rotation will have a higher TANGENTIAL speed than one closer to the aor
maximum shm velocity occurs at...
minimum displacement
maximum shm acceleration occurs at...
-maximum displacement
a higher spring constant means...
a stiffer spring
closed system
allows energy (but not matter) to enter/leave
isolated system
doesn't allow energy or matter to enter/leave
atwood machine equation
a = g(m₁ - m₂)/(m₁ + m₂) where m₂ is the driver
modified atwood equation
a = g(m₂)/(m₁ + m₂) where m₂ is the driver
universal gravitational constant (G)
6.67 * 10⁻¹¹ Nm²/kg²
with equations like mv²/r the exponent is...
distributed only to the variable right next to it (if no parentheses)
minimum velo needed to "hill hop" (slowest possible speed at which an object can complete a circle)
v = √gr
acceleration due to gravity on a distance-time² graph
twice the slope → s = (1/2)at²