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location of DNA replication in eukaryotic organism
both strands at each end of a replication bubble
origin of DNA replication in eukaryotic organism
many origins of replication within each replicon
how does replication proceed in a eukaryotic genome
DNA unwinds at each origin, producing a replication bubble
DNA synthesis occurs on both strands at each end of the bubble + the 2 replication forks spread outward
forks of adjacent bubbles run into each other + segments of DNA fuse, which produces 2 identical linear synthesized DNA molecules
bidirectional
no breakage of nucleotide strand
replication fork
point where the 2 strands separate from the double-stranded DNA helix
aka, point of unwinding
replication bubble
loop generated by unwinding of double helix
why are nucleotides brought into the growing strand as triphosphates?
to provide the energy needed for DNA polymerization
what is a primer + why is it necessary in DNA replication?
primer = RNA nucleotides
provide 3’-OH group to which DNA polymerase can attach DNA nucleotides
leading strand only needs primers at 5’ end of new strand
lagging strand needs new primer at beginning of each Okazaki fragment
DNA helicase function
unwinds DNA at replication fork
DNA primase function
synthesizes a short RNA primer to provide a 3’-OH group for the attachment of DNA nucleotides
single-strand binding proteins (SSBs) function
attach to exposed single-stranded DNA that has been unwound by helicase
protect single-stranded nucleotide chains
prevent formation of secondary structures that would interfere w/replication
DNA polymerase III function
elongates a new nucleotide strand from the 3’-OH group provided by the primer
5’ → 3’ polymerase activity = adds new nucleotides in 5’ → 3’ direction
3’ → 5’ exonuclease activity = removes nucleotides in 3’ → 5’ direction (used to correct errors →accurate + efficient DNA synthesis)
topoisomerase function
relaxes supercoiled DNA ahead of the replication fork so replication can proceed
DNA polymerase I function
has 5’ → 3’ polymerase + 3’ →5’ exonuclease activities
also has 5’ → 3’ exonuclease activity
removes RNA primers + replaces them w/DNA nucleotides
DNA ligase function
joins Okazaki fragments by sealing breaks in the sugar-phospahte backbone of newly synthesized DNA
5’ vs 3’ ends of a molecule
DNA synthesis is always 5’ → 3’
new nucleotides are always added to the 3’ end of the growing nucleotide strand
leading strand in replication fork
runs in 5’ → 3’ direction in the the replication fork
grows in direction of replication fork
undergoes continuous replication
no fragments formed
requires one primer
doesn’t require DNA ligase
lagging strand in replication fork
opens in 3’ → 5’ direction towards the replication fork
grows away from replication fork
undergoes discontinuous replication (forms Okasaki fragments)
each fragment requires its own primers
requires DNA ligase
Okasaki fragment
short lengths/fragments of DNA produced by discontinous replication of lagging strand