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Learning Objectives
Articulate how information flows in biology through nucleic acids and proteins
Use a baking analogy to represent the central dogma of biology
Compare where the central dogma occurs in eukaryotes and prokaryotes
Distinguish between the primary structures of DNA and RNA
Explain how the structures of DNA and RNA influence their functions in information flow
phosphate group
part of the nucleotide
negatively charged
sugar
nitrogenous base
nucleotide
monomer that composes nucleic acids, consists of 3 parts
5 carbon sugar
phosphate group
nitrogenous base
nucleic acid
a polymer of nucleotide monomers
contain the information that encodes life
RNA
ribo-nucleic acid
nucleic acid that serves as a messenger, transferring genetic instructions from DNA to the cell's protein-making machinery
=RIBOSE has a hydroxy on the 2’ carbon
DNA
complex molecule that carries the genetic instructions for the development, functioning, growth, and reproduction of all known living organisms
Stable
• Able to be copied - heritable
• Able to encode information
=DEOXYRIBOSE has a hydrogen on the 2’ carbon
phosphodiester bonds
the stable covalent bonds in between nucleotides in nucleic acid
sugar phosphate backbone
Phosphodiester linkages form the sugar–phosphate backbone= the negatively charged phospho group links to the 3’ carbon on the sugar
3’ 5’
complementary base pairing
specific pairing between nucleotide bases in DNA and RNA —>held together by hydrogen bonds
important for forming the double helix and encoding complex genetic information.
run anti parallel
central dogma
genetic information flows from DNA—>RNA—>Proteins
Learning Objectives
List the steps needed to make RNA from a DNA template (transcription)
Relate the structures of nucleotides to the directionality of transcription
Explain the function of RNA polymerase and how it reads the DNA template to synthesize the complementary RNA transcript
Identify key features of a gene and how they relate to the process of transcription
5’ end
unlinked phosphate
3’ end
unlinked hydroxyl group
new nucleotides are ALWAYS added to this end.
transcription
the synthesis of RNA from a DNA template
—>determines how dna is used in the cell
initiation
elongation
termination
rna polymerase
an enzyme that binds to DNA, reads it (3’—>5’), and synthesizes complementary RNA (5’—>3’)
template strand
the strand of DNA that serves as the blueprint for the synthesis of a complementary RNA molecule during transcription
initiation of transcription
rna polymerase binds to DNA
promoter
stretches of DNA that allow RNA polymerases to “know” where to start transcribing= recruit DNA and serve as a binding site
sigma factor
recognizes and binds to the promoter DNA to help position the RNA polymerase in prokaryotes
general transcription factors
use _______ to recognize promoter regions and position RNA polymerase on the DNA— eukaryotes
transcription elongation
RNA polymerase “reads” the DNA template
to synthesize the complementary RNA
transcription termination
termination site allows RNA polymerase to “know” where to stop transcribing
prokaryotes: RNA polymerase transcribes a DNA sequence known as the “termination site”
“termination sequence” of
DNA is transcribed into RNA, it
recruits an enzyme to subsequently
cut the RNA
Then, the RNA falls off the DNA
RNA polymerase stops transcription shortly after
gene
a segment of DNA that is necessary for the synthesis of a product
(typically a protein, but sometimes a functional RNA)
genetic code
The code is (nearly) universal!
• The code is degenerate or
redundant
• Some codons indicate the same
amino acid
• The code is unambiguous
• One codon never codes for more
than one amino acid
• The code is conservative
• When several codons specify the
same amino acid, the first two
bases are typically identical
tRNA
non-coding RNA molecules that function as adaptors, translating the genetic code from messenger RNA (mRNA) into proteins by delivering specific amino acids to the ribosome during translation.
codon
anticodon
charged states
uncharged states