The Rest of the Course (after Midterm 2)

0.0(0)
studied byStudied by 0 people
0.0(0)
full-widthCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/26

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

27 Terms

1
New cards

cross product formula using cofactor row expansion

  • don’t forget the minus sign written before the j (vertical component of the vector)

  • rmbr: ai + bj + ck = (a, b, c)

<ul><li><p>don’t forget the minus sign written before the j (vertical component of the vector)</p></li><li><p>rmbr: ai + bj + ck = (a, b, c) </p></li></ul><p></p>
2
New cards

formula for the curl of a vector field

  • remember: ∇ × F (order is important)

  • expand the top row via cofactor determinant expansion

<ul><li><p>remember: <span>∇ × F (order is important) </span></p></li><li><p>expand the top row via cofactor determinant expansion</p></li></ul><p></p>
3
New cards

curl of a vector field F = (P, Q, R): input and output

  • computing the curl gives you another vector field

  • the input of a curl = any point in space

  • the output of a curl = a vector where the direction is the axis that the point is “spinning around” and the magnitude is how fast it is spinning

4
New cards

curl of a vector field: defn

  • curl measures the infinitesimal circulation per unit area at a point

  • imagine a tiny closed loop around a point in a vector field, computer the circulation (line integral of the vector field around that loop), divide by the area of the loop, and shrink the loop to size → 0, and the vector that you get is the curl at that point

<ul><li><p>curl measures the infinitesimal circulation per unit area at a point</p></li><li><p>imagine a tiny closed loop around a point in a vector field, computer the circulation (line integral of the vector field around that loop), divide by the area of the loop, and shrink the loop to size → 0, and <strong>the vector that you get is the curl at that point </strong></p></li></ul><p></p>
5
New cards

right hand rule for curl

knowt flashcard image
6
New cards

right hand rule for stokes theorem

knowt flashcard image
7
New cards

the curl of a gradient, which is a type of vector field, is equal to ___

zero.

  • gives criterion for determining whether a vector field is the gradient of some function

  • so if you are given some vector field F, and you compute the curl with ∇ × F and it eqiuals to 0, then F = the gradient of some function and you can use the

<p><strong>zero.</strong></p><ul><li><p>gives criterion for determining whether a vector field is the gradient of some function</p></li><li><p>so if you are given some vector field F, and you compute the curl with <span>∇ × F and it eqiuals to 0, then F = the gradient of some function and you can use the </span></p></li></ul><p></p>
8
New cards

formula for the divergence of a vector field (in 2D)

just remember this dot product: DIV(F) = ∇ ⋅ F

<p><span>just remember this dot product: </span>DIV(F) = <span>∇ ⋅ F</span></p>
9
New cards

formula for the divergence of a vector field (in 3D)

or just remember: DIV(F) = ∇ ⋅ F

<p>or just remember: DIV(F) = <span>∇ ⋅ F</span></p>
10
New cards

divergence of a vector field: defn

  • the computation of the divergence gives you a real number, not a vector

  • if you imagine the vector field as a pool of water, divergence at a point tells you whether water is spreading out (called a source) or converging in (sink)

    • if divergence result at some point = positive → source

    • negative → sink

    • zero → neither source or sink

11
New cards

what is the computation of the divergence of a curl of a vector field equal to?

ZERO.

∇⋅ (∇ × F) = 0, because the dot product between perpen vecs = 0, and ∇ is perpen to (∇ × F) by defn of cross product

12
New cards

formula for green’s flux theorem

so instead of computing the left hand side, you can compute the right hand side IF green’s flux theorem applies, and the equation just becomes a normal double integral

  • this theorem is only for 2D

  • R = D = domain

  • (∇ ⋅ F) = DIV(F)

<p>so instead of computing the left hand side, you can compute the right hand side IF green’s flux theorem applies, and the equation just becomes a normal double integral</p><ul><li><p>this theorem is only for 2D</p></li><li><p>R = D = domain</p></li><li><p><span>(∇ ⋅ F) = DIV(F)</span></p></li></ul><p></p>
13
New cards

criterion for the green’s flux theorem

  1. the curve C that bounds the domain D just be a simple closed curve (it doesn’t cross itself)

  2. C must be positively oriented (when traversed counterclockwise, D is always on your left)

  3. D should be simply connected. if there are holes, it must be computed separately

14
New cards

what is the formula for flux of a parametric surface

<p></p>
15
New cards

flux of a surface: defn

knowt flashcard image
16
New cards

formula for the normal vector in the flux formula

knowt flashcard image
17
New cards

if you have a tangent vector <a,b>, what would the normal vector be?

n = <b, -a>

  • only works for vectors that only have two components

18
New cards

if a curve is negatively oriented, what should you do?

include a minus sign in the formula

19
New cards

formula to find the unit normal

knowt flashcard image
20
New cards

formula to finding the area of a surface

knowt flashcard image
21
New cards

formula for integrating a function over a surface

knowt flashcard image
22
New cards

if you were given the parametrization of a cylinder → (Rcosθ, Rsinθ, z), how do you make it a surface

make one of the variables a fixed number

  • the most common is to make R into a fixed number → if R = 2, then you’d get the surface parametrization of r(u,v) = (2cos(u), 2sin(u), v) where u = θ and v = z….

23
New cards

formula for integrating a vector field over a surface

<p></p>
24
New cards

a shortcut when computing the integral of a vector field over a surface

  • for when u = F (vector field)

  • and v and w are the partial derivs of the parametrization of the surface

<ul><li><p>for when u = F (vector field)</p></li><li><p>and v and w are the partial derivs of the parametrization of the surface</p></li></ul><p></p>
25
New cards

formula for stokes theorem

turns a complicated line integral into a simpler to compute surface integral

<p>turns a complicated line integral into a simpler to compute surface integral</p>
26
New cards

criterion for applying stokes theorem

when you look from the direction of the normal vector, you must walk around the boundary counterclockwise

<p>when you look from the direction of the normal vector, you must walk around the boundary <strong>counterclockwise</strong></p><p></p>
27
New cards

formula for divergence theorem

this theorem makes it so you don’t have to compute a complicated surface integral, and you just have to compute a regular triple integral by treating the surface as the boundary of some volume

  • best for surfaces with hard corners, like a cube

  • the surface must be a CLOSED SMOOTH surface

  • the normal vec (n) must be pointing outwards out of the surface. if it’s pointing inwards, you have to apply -1 to the integral

<p>this theorem makes it so you don’t have to compute a complicated surface integral, and you just have to compute a regular triple integral by treating the surface as the boundary of some volume</p><ul><li><p>best for surfaces with hard corners, like a cube</p></li><li><p>the surface must be a CLOSED SMOOTH surface</p></li><li><p>the normal vec (n) must be pointing outwards out of the surface. if it’s pointing inwards, you have to apply -1 to the integral </p></li></ul><p></p>

Explore top flashcards

AMSCO: Quiz 3
Updated 244d ago
flashcards Flashcards (246)
Germany
Updated 917d ago
flashcards Flashcards (222)
Vivaldi
Updated 1041d ago
flashcards Flashcards (182)
English vocab
Updated 218d ago
flashcards Flashcards (40)
Stages 20-22 vocab
Updated 377d ago
flashcards Flashcards (78)
Circuits
Updated 590d ago
flashcards Flashcards (84)
AMSCO: Quiz 3
Updated 244d ago
flashcards Flashcards (246)
Germany
Updated 917d ago
flashcards Flashcards (222)
Vivaldi
Updated 1041d ago
flashcards Flashcards (182)
English vocab
Updated 218d ago
flashcards Flashcards (40)
Stages 20-22 vocab
Updated 377d ago
flashcards Flashcards (78)
Circuits
Updated 590d ago
flashcards Flashcards (84)