Exam One

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30 Terms

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Alcohol/Carboxylic Acid

OH pka = 15

Carboxylic pka = 5

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Allylic

Radical on carbon next to carbon with double bond

  • resonance stabilizes and rxn proceeds easier

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Allyl cation, radical, and anion

2 pi e-, 3 pi e-, 4 pi e-

  • have same molecular orbital diagram but different homo and lumo

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Molecular Orbital Rules

  1. number of orbitals in = number of orbitals out

  2. adding nodes increases the amount of energy

  3. when reading L —> R the orbitals should be symmetrical

  4. when you have a weak nucleophile that would form no reaction, it can form a cation if it is allylic (good nucleophile will do sn2)

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Radical Halogenation

  • Low Concentrations X2 with RO-OR or Hv reacts at allylic spot → adds one X 

  • NBS/NCS with Peroxide adds TINY Br/Cl

Mechanism:

  1. Initiation: Br2 homolytically cleaves

  2.  homolytic cleavage of H at allylic spot (weakest bond) + bond formation with radical from initiation 

    1. Draw possible resonance structures

  3. Propagation two: homolytic cleavage of Br2 and bond formation with radical 

Product: starting material with a Cl/Br at allylic position and Cl/Br radical

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Possible Peroxides with NBS/NCS

(tBuO)2

(BzO)2

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Reactions of Allylic Systems

  1. Radical Halogenation: NBS/NCS w/ peroxide

  2. Nucleophilic Substitution: sn1 with poor nucleophiles

  3. Addition to electrophiles:

    1. addition of Mg and THF to form organometallic

    2. H attached to allylic carbon reacting with nBuLi and TMEDA to replace H with Li

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TMEDA

nBuLi deprotonates H at allylic position and replaces it with Li

  • nBuLi with TMEDA

  • TMEDA boosts the reaction by coordinating to Li⁺ through two nitrogen lone pairs, increasing the reactivity of n-BuLi

  • C-H bond is ~40 while C-Li bond is ~50 so reaction will still proceed, but slowly and less effectively without TMEDA

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Conjugation

  • 3 sp2 p orbitals in a row

  • lowers energy of molecule and stabilizes

  • single bond separates the double bond

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Diene

2 C=C bonds

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Triene

3 C=C bonds

Alternating single and double bonds

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Allene

Two adjacent double bonds

  • since adjacent, one orbital is up and down while the other is in and out

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E vs Z

E is when high priority groups are on opposite sides

Z is when high priority groups are on same sides

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Measuring stability + result of conjugated systems

△H°hydrogenation: energy released when pi bond breaks into sigma bond

  • One double bond reacting with H2/Pt = -30 kcal/mol

  • two double bonds reacting with H2/pt = -60 kcal/mol

  • Conjugated system reacting with H2/pt = -57 kcal/mol

Conjugation: Stabilizes starting material due to sp2 hybridization and p orbitals of adjacent bonds overlapping, allowing delocalization of pi electrons resulting in lower energy arrangement and increasing stability.

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Characterization of Conjugated systems

  • Single Bond Shortens: single bond between two double bonds has overlap of p orbitals allowing delocalization resulting in a partial double-bond character on the single bond

    • Makes bond strong and shorter than normal c-c bond

  • Barrier to Rotation: Rotation around central bond would break p-orbital overlap, disrupting conjugation

    • conjugations lowers energy, breaking this system requires more energy

    • inhibits rotation —> higher rotational energy barrier than normal single bond

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Bonding Orbitals

π3* = Antibonding - High energy

π2 = nonbonding - Neutral energy

π1 = bonding - Low energy

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3 carbon conjugated system - MOD

π3* = red/blue : blue/red : red/blue = 2 nodes = highest energy state

π2 = red/blue: blue/red = 1 node = neutral energy state

π1 = red/blue, red/blue, red/blue = 0 nodes = low energy state

MOD is same for 2,3,4 pi e- allylic systems - HOMO/LUMO changes

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4 carbon conjugated system MOD - Diene

2 double bonds = 4 pi bonds

no nonbonding orbitals in even number pi orbitals

π4* = red/blue : blue/red : red/blue : blue/red = 3 nodes = high energy

π3* = red/blue : blue/red : blue/red : red/blue = 2 nodes = high energy

π2 = red/blue : red/blue : blue/red : blue/red = 1 node = high energy

π1 = red/blue, red/blue, red/blue, red/blue = 0 nodes = lowest energy

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Thermodynamic Product

  • Most stable form (most substituted double bond)

    • compare all resonance forms

  • Higher Ea + low energy product

  • favored at high temperatures

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Kinetic Product

  • Fastest forming product

  • Lowest Ea

  • Favored at low temperatures

  • Can form at high temperatures

    • not favored due to ability to reverse reaction ability

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Impact of Increasing Conjugation

  • More double bonds = more resonance = more stable

    • due to increasing # of overlapping adjacent p orbitals

  • Lower Ea —> lots of possible products (more resonance intermediates)

  • Polymerization side rxn increases —> due to stable intermediate formation —> reacts with itself

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Benzene

  • Aromatic functional group

  • conjugated

  • not a triene

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Diels-Alder Reaction

4+2 Cycloaddition between diene (4πe-) and dienophile (2πe-) with heat

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Diene

Electron Rich —> Electron Donating Group (EDG)

  • R group

  • :O:R

  • :NR2

  • Me:O: (at position 3)

  • CH3 (at position one)

  • Hexane ring (connected at position 2/3) —> e- donating alkyl groups

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Dienophile

Electron Poor —> Electron Withdrawing Group (EWG)

  • CF3

  • NO2

  • C≡N

  • -CR=O

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Inductive Effect

Electronegativity acting at a distance

  • CH3 donates e- via hyperconjugation

    • 3- in C-H sigma bond overlap with pi system, pushing e- density into pi system

    • stabilizes positive charges —> carbocation has empty p orbital, CH3 sigma bonds overlap with empty p orbital, partially delocalizing positive charge, stabilizing it

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Resonance

Stronger effect than inductive effect

  • EDG: more e- density into π system

  • EWG: less e- density in π system

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How do you know if you are working with a diels-alder reaction?

If you see a cyclohexene with at least one π bond

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Diels-Alder Reaction Mechanism

Concerted Reaction!

  1. Arrow from C1-C2 Diene π bond to C2-C3 σ bond

  2. Arrow from C3-C4 Diene π bond to space between diene/dieneophile

  3. Arrow from C1-C2 π bond from Dieneophile to upper space between diene/dieneophile

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Diene Conformations - trans vs cis

s-trans: Thermodynamically favored and more stable

  • unreactive

s-cis: required for diels-alder reaction

  • Heat used to push this reaction

  • reactive