CHM 1046 TEST 2

what is R

6.31446

what is the concentration ? seckonds later given rate m.s M secs later

(rate later) x (sec later)= new m —> 1/conc + new m = m#2 —> 1/m#2 =M

what is the concentration x seckonds later given rate s M secs later

-(rate) x (sec later)= new m —> e^-(new)=b —>(M) x (b)= M

finding how long it takes for conc to be decreased by x % given s rate m and %

if original dont-10 (%-100(then un% it) ) x (M) = new m —> -1/rate ln(new m/m)= secs

how long it takes xM given M1, M2, rate constant s

-1/rate ln(M2/M1) = secs

finding how long it takes to decrease x% of inital value given rate m-1s-1 m %

(%(unpercent)) x (M)= m new —> 1/rate(1/new - 1/m)

graph thing w box and line

A) destroyed B) line/line secs in M/s C) original-box= m —> m/box secs in M/s

graph thing with just box

A) seconds B) in2/seconds = s^-1 C) given time/ seconds = A original M/2^A = M

equtn moves right

added: down, up removed down down

equtn moves left

added: up up removed: up down

Q>Kc

reactants made

Q<Kc

products made

Q=Kc

no change

K> 10

products dominate, little A/B

K<.01

reactants dominate, little C/D

K= 0.1-10

neither

endo

both up temp lowered left temp raised right

exo

both up temp lowered right temp raised left