AP Calculus AB Formulas

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33 Terms

1
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What is the limit?

y’ = m = lim h→ 0 [f(a+h) - f(a)]/ h

2
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What is the limit 2?

y’ = m = lim x → a [f(x) - f(a)]/x-a

3
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y’ = m = lim h → 0 [f(a+h) - f(a-h)]/2h

4
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f’© = f(b) - f(a)/ b-a

5
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What is the equation for l’Hopital?

L’H → lim x→ 0 f(x)/g(x) = lim x→ a f’(x)/g’(x)

6
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What are critical points?

f’(x) = 0, f’(x) = DNE

7
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How to find increasing/decreasing?

f’(x) > 0 → inc, f’(x) < 0 → dec

8
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Concavity?

f”(x) > 0 → conc. up (min), f”(x) < 0 → conc. down (max)

9
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Local Extrema?

f’(x) = 0 and f”(x) > 0 → min

f’(x) = 0 and f”(x) < 0 → max

10
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Point of inflection?

a. f”(x) = 0

b. f”(x) = DNE

c. where f’(x) changes sign (means… changes concavity)

11
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Linearization?

L(x) = f(a) + f’(a)(x-a)

12
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Newton’s method?

Xn + t = Xn - f(Xn)/f’(Xn)

13
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Approximating binomials

(t + X)^k = x + Kx

14
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y’ of ln(u)

1/u

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y’ of loga u

1/ulna

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y’ of e^x

e^x

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y’ of lnx

1/x

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y’ of a^x

a^x lna

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y’ of x^n

nX^(n-1)

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y’ of cu

c(du/dx)

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y’ of sinx

cosx

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y’ of cosx

-sinx

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y’ of tanx

sec²x

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y’ of cscx

-cscxcotx

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y’ of secx

secxtanx

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y’ of cotx

-csc²x

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y’ of inverse sin

1/sqrt(1-u²)

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y’ of inverse cos

-1/sqrt(1-u²)

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y’ of inverse tan

1/(1+u²)

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y’ of inverse csc

-1/u sqrt(u²-1)

31
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y’ of inverse sec

1/u sqrt(u²-1)

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y’ of inverse cot

-1/1+u²

33
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