SHM and uniform circular motion(ACCELERATION IN TERMS OF OMEGA)
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5 Terms
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acceleration of point P
As the point P is moving on the circle it has an acceleration
ap = x o omega2
always directed towards the center O.
At instant t, its direction will be along PO.
2
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acceleration of point N
The acceleration of point N will be the component of acceleration ap along the diameter DE on which N moves due to the motion of P
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value of component
the value of this component is
ap sin theta = x o omega2 sin theta
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(magnitude of)acceleration of N
a = x o omega2 sin theta
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final deri
Note 
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