SHM and uniform circular motion(ACCELERATION IN TERMS OF OMEGA)

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5 Terms

1
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acceleration of point P

As the point P is moving on the circle it has an acceleration

ap = x o omega2

always directed towards the center O.

At instant t, its direction will be along PO.

2
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acceleration of point N

The acceleration of point N will be the component of acceleration ap along the diameter DE on which N moves due to the motion of P

3
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value of component

the value of this component is

ap sin theta = x o omega2 sin theta

4
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(magnitude of)acceleration of N

a = x o omega2 sin theta

5
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final deri