Lab 1- Titration using a buret

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8 Terms

1
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Glassware and Chemicals used

  • 25mL buret stand

  • 125mL Erlemeyer flask ( 4 of them for the tirals)

  • 5.00mL graduated cylinder or pipet

  • 0.100 M NaOH solution (goes in the burret)

  • Unknown HCl solution - 5mL for each trial

  • 3 drops of phenolphthalein indicator

2
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Lab Procedure

  • Rinse the buret with 5mL of the 0.100 M NaOH and discard it into the beaker (put it in waste when finished)

  • Fill the burret to the 0.00 mL with NaOH (meniscus bottom on the line)

  • Measure out 5.00mL of acid and put into the 125mL flask

  • Add 3 drops of phenolphthalein to that and swirl

  • Record the initial buret reading

  • Titrate the NaOH slowly while watching the volume

  • Stop once you have reached a light pink color

  • Record the final buret reading (volume of NaOH = Final - Initial)

  • Repeat for trials 1-3

3
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What type of chemical reaction is this?

Neutralization (Acid Base)

4
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how do you read a buret?

top of the meniscus at eye level to bottom

5
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How do you calculate the avarage of the 3 trials?

  • Add the three trial volumes together

  • Divide by the amount of trials (in this case 3)

6
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How do you calculate the standard deviation of the 3 trials?

  • Find the average of the 3 trials

  • then do (volume of HaOH added - the average) make sure to do this for each trial individually

  • once you find that difference square each of those values

  • add those squared numbers up and the divide by 2

  • take that result and square root that to get your final answer

  • Formula (Volume of NaOH added for trial 1 - Average of trial 1) ² + (Volume of NaOH added for trial 2 - Average of trial 2) ² + ((Volume of NaOH added for trial 3 - Average of trial 3)² /2 square root that number

7
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How do you find the volume of NaOH added

(final - inital)

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How to find percent error

%error = experimental  - true value/ true value * 100

  • in context of this expirement you would use this formula- (Avg. volume of NaOH added for the three trials- Actual volume of NaOH) / Actual volume of NaOH *100