OCR A LEVEL CHEMISTRY MODULE 4

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Last updated 9:22 AM on 2/5/26
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299 Terms

1
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What is meant by a homologous series?

A series of organic compounds with the same functional group and similar chemical properties, where each successive member differs by a CH₂ group.

2
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General formula for a carboxylic acid

CₙH₂ₙO₂ or CₙH₂ₙ₊₁COOH — both valid depending on how R is counted.

3
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Definition of structural isomers

Compounds with the same molecular formula but different structural formulae (different atom arrangements).

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Definition of stereoisomers

Compounds with the same structural formula but different spatial arrangements of atoms.

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Why do branched alkanes have lower boiling points than straight-chain isomers?

Branching reduces surface area contact between molecules → weaker London forces → lower boiling points.

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What are London forces (induced dipole-dipole interactions)?

Weak intermolecular forces caused by fluctuating dipoles; stronger with larger molecules or greater surface area.

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Conditions and reagent for hydration of an alkene

Steam (H₂O(g)) and an acid catalyst (e.g. H₃PO₄ or H₂SO₄).

8
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Why are alcohols more soluble in water than alkenes?

Alcohols form hydrogen bonds with water due to the OH group. Alkenes cannot form hydrogen bonds.

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What does a curly arrow represent in mechanisms?

Movement of an electron pair (from a lone pair or π-bond to an electrophile or atom).

10
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Definition of an electrophile

A species that accepts an electron pair — typically has a positive or δ⁺ charge (e.g. H⁺, NO₂⁺, I⁺).

11
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Definition of a nucleophile

A species that donates an electron pair to form a covalent bond (e.g. OH⁻, CN⁻, NH₃).

12
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Mechanism by which alkanes react with halogens under UV light

Free radical substitution.

13
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General formula of an alkyl group

CₙH₂ₙ₊₁ — derived by removing one H atom from an alkane.

14
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General formula for cycloalkanes

CₙH₂ₙ — same as alkenes, but only single bonds in a ring.

15
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Why do larger cycloalkanes have higher boiling points?

More contact area between molecules → stronger London forces → more energy needed to separate them.

16
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Reaction of bromine water with alkenes

Bromine water decolourises (orange to colourless) when it reacts with a C=C double bond.

17
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What is the role of IBr in reactions?

IBr undergoes heterolytic fission to form I⁺ (electrophile) and Br⁻.

18
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How many structural isomers of C₅H₁₂ exist?

3 — pentane, 2-methylbutane, and 2,2-dimethylpropane.

19
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Why do more branched isomers have lower boiling points?

More branching = less surface contact = weaker London forces = lower boiling points.

20
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Equation for full substitution of 3 Cl atoms in C₅H₁₂

C₅H₁₂ + 3Cl₂ → C₅H₉Cl₃ + 3HCl

21
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Systematic name for CH₃CH(CH₃)CH₂OH

2-methylpropan-1-ol

22
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Systematic name for allyl bromide

3-bromoprop-1-ene or 1-bromoprop-2-ene (both acceptable).

23
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General formula of homologous series for allyl bromide

CₙH₂ₙ₋₁Br — characteristic of substituted alkenes.

24
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Skeletal formula of pentane

Zigzag chain of five carbon atoms with no atom labels — shows backbone only.

25
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Why do some isomers exhibit stereoisomerism?

C=C double bond prevents rotation and different groups attached → E/Z (cis-trans) isomerism possible.

26
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Test for alkene presence

Add bromine water — decolourisation indicates presence of a double bond (electrophilic addition).

27
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What is an alicyclic compound?

An aliphatic (non-aromatic) compound with carbon atoms joined in a ring.

28
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Difference between aliphatic, alicyclic, and aromatic

Aliphatic = open chain; Alicyclic = ring, non-aromatic; Aromatic = contains benzene ring.

29
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Percent yield formula

% Yield = (actual moles ÷ theoretical moles) × 100

30
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Equation for elimination reaction: alcohol → alkene

C₆H₁₂O → C₆H₁₀ + H₂O (removal of water from alcohol).

31
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Why must carbon not have five bonds in structural formulas?

Carbon forms 4 covalent bonds. Drawing 5 is chemically invalid — check structures for correctness.

32
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Why are lowest locant numbers used in naming?

IUPAC rules favour lowest possible position numbers for functional groups and substituents.

33
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How to identify aliphatic, alicyclic, and aromatic compounds

Aliphatic: straight/branched chain; Alicyclic: non-aromatic ring; Aromatic: benzene or delocalised ring.

34
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Define radical substitution

A reaction involving free radicals where one atom (usually H) is replaced by another atom (usually halogen), initiated by UV light.

35
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Initiation step of radical substitution

Cl₂ → 2Cl· (requires UV light to break Cl-Cl bond homolytically).

36
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Propagation step 1 for butane and Cl·

C₄H₁₀ + Cl· → C₄H₉· + HCl

37
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Propagation step 2 for butyl radical and Cl₂

C₄H₉· + Cl₂ → C₄H₉Cl + Cl·

38
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Equation for full substitution of all H atoms in butane

C₄H₁₀ + 10Cl₂ → C₄Cl₁₀ + 10HCl

39
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How to determine molecular formula from gas data

Use: moles = volume / molar volume → molar mass = mass / moles → use Mr to find empirical/molecular formula.

40
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Definition of structural isomers

Compounds with the same molecular formula but different structural formulae.

41
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Why branched alkanes have lower boiling points

Branching reduces surface contact between molecules → weaker London forces → lower boiling point.

42
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Trend in boiling points across isomers

More branching = weaker London forces = lower boiling point.

43
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Definition of London forces

Weak intermolecular forces caused by temporary dipoles between molecules.

44
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Why less energy is needed to separate branched molecules

Fewer/weaker London forces → less energy required to overcome IMFs.

45
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Mechanism name for alkane + Cl₂ under UV

Free radical substitution.

46
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Why radical substitution forms many isomers

Any H atom can be substituted → multiple mono- and polysubstituted products form.

47
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Equation for formation of trichloro derivative of C₅H₁₂

C₅H₁₂ + 3Cl₂ → C₅H₉Cl₃ + 3HCl

48
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Condition for radical substitution

UV light (or sunlight) — initiates homolytic fission.

49
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Definition of homolytic fission

Covalent bond breaks evenly so each atom takes one electron → forms two radicals.

50
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Propagation step example: CH₃CH₂COOH and Cl·

Cl· + CH₃CH₂COOH → CH₃CHCOOH· + HCl

51
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Displayed formula of CH₃CHCOOH·

Radical has unpaired electron on central carbon (C₂).

52
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Further substitution product example from CH₃CHClCOOH

Structure with additional Cl on carbon chain, e.g. CH₃CCl₂COOH.

53
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Why alcohols have higher boiling points than alkanes

Alcohols have hydrogen bonds (strong) vs alkanes' London forces (weak).

54
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Equation for complete combustion of octane

C₈H₁₈ + 12.5O₂ → 8CO₂ + 9H₂O

55
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How to check if combustion was incomplete

Compare moles of CO₂ actually produced with moles expected from complete combustion — if less, it's incomplete.

56
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Definition of homologous series

Series of compounds with the same functional group, similar reactions, each member differing by CH₂.

57
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General formula for cycloalkanes

CₙH₂ₙ

58
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Why boiling points increase across cycloalkanes

More carbons = more contact = stronger London forces = higher boiling point.

59
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Shape and bonding around C in cycloalkanes

Tetrahedral shape; four bonding pairs repel equally.

60
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Initiation step with bromine in cyclohexane

Br₂ → 2Br·

61
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Propagation steps with bromine and cyclohexane

C₆H₁₂ + Br· → C₆H₁₁· + HBr; C₆H₁₁· + Br₂ → C₆H₁₁Br + Br·

62
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Termination step examples in free radical reactions

Br· + Br· → Br₂; C₆H₁₁· + Br· → C₆H₁₁Br; C₆H₁₁· + C₆H₁₁· → C₁₂H₂₂

63
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Name a structural isomer of C₆H₁₀Br₂

e.g. 1,2-dibromocyclohexane or 1,4-dibromocyclohexane

64
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Skeletal formula of product from hexane + Cl₂

Line structure of hexane with a Cl replacing one H.

65
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Why radical substitution gives a mixture of products

Multiple H atoms can be substituted randomly → mono- and polysubstitutions at different positions.

66
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Why CO is dangerous in incomplete combustion

CO is toxic — binds to haemoglobin and prevents oxygen transport.

67
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How to assess safety in combustion based on oxygen

Compare oxygen consumed with oxygen required for complete combustion — if less, it's unsafe/incomplete.

68
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How a sigma (σ) bond forms

Direct overlap of orbitals between bonding atoms.

69
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Bond angle and shape around C=C in alkenes

120°, trigonal planar.

70
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Definition of termination step in radical substitution

Two radicals combine to form a stable molecule, ending the chain reaction.

71
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Definition of an electrophile

A species that accepts a pair of electrons — typically positively charged or δ+ (e.g. H⁺, Br⁺, I⁺).

72
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What happens when Br₂ reacts with an alkene?

Bromine adds across the double bond; bromine water decolourises (orange → colourless).

73
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What is the mechanism for alkene + Br₂?

Electrophilic addition: π electrons attack Br, Br-Br bond breaks heterolytically, Br⁻ adds to carbocation.

74
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Conditions for hydrogenation of an alkene

H₂ gas and a nickel (Ni) catalyst; Pt, Pd or Rh also accepted.

75
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Conditions for hydration of an alkene

Steam (H₂O(g)) and an acid catalyst (e.g. H₃PO₄ or H₂SO₄).

76
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Why are alkenes more reactive than alkanes?

They contain a C=C double bond which is electron-rich and can be attacked by electrophiles.

77
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What type of reaction occurs between alkenes and halogens?

Electrophilic addition.

78
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Why does poly(propene) not have E/Z isomers?

Poly(propene) is saturated — it contains only single (σ) bonds, so there's free rotation.

79
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Why do alkenes show E/Z stereoisomerism?

C=C bond has restricted rotation; each carbon in the double bond must have 2 different groups.

80
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Definition of electrophilic addition

Reaction where an electrophile is attracted to a region of high electron density and adds to it.

81
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What is the bond angle around each carbon in an alkene?

120°, trigonal planar.

82
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Why can't pent-1-ene exhibit E/Z isomerism?

One carbon in the C=C bond has two identical groups (hydrogens), so stereoisomerism isn't possible.

83
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What is Markovnikov's rule?

In HX addition, the H attaches to the carbon with more Hs already (major product comes from more stable carbocation).

84
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How does carbocation stability affect product formation?

Tertiary carbocations are more stable than secondary/primary → major product forms via more stable intermediate.

85
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Name the mechanism: alkene + HCl

Electrophilic addition.

86
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Why is π bond weaker than σ bond?

π bond forms from sideways p-orbital overlap — electron density is above and below nuclei → more exposed and weaker.

87
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How is a π bond formed?

By sideways overlap of two adjacent p-orbitals.

88
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Why does the C=C bond have restricted rotation?

π bond prevents rotation — rotation would break overlap of p-orbitals.

89
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Balanced equation for polymerisation of chloroethene

nCH₂=CHCl → -[CH₂-CHCl]-ₙ (use displayed formula with correct side links).

90
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Problem with combustion of chloroalkene polymers

Releases toxic gases e.g. HCl which contributes to acid rain.

91
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How is HCl removed during incineration?

Sodium hydrogencarbonate (NaHCO₃) neutralises HCl, forming NaCl, CO₂ and H₂O.

92
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Give one advantage and disadvantage of incinerating polymers

Advantage: Energy production; Disadvantage: Toxic gases (HCl, CO, CO₂).

93
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Define structural isomers

Compounds with the same molecular formula but different structural formulae (i.e. different connectivity of atoms).

94
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How to test for C=C double bond

Add bromine water → decolourisation confirms presence of alkene.

95
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How do alkenes react with H₂O (steam)?

Hydration reaction → electrophilic addition → forms alcohols.

96
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Draw the intermediate in an alkene + HBr mechanism

A carbocation (C+) at the more stable site; curly arrow from Br⁻ to the C⁺.

97
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Repeat unit of an addition polymer

Two carbon atoms from the original C=C, now single bonded, each with side links to next units.

98
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Why do polymers not biodegrade easily?

Contain strong C-C and C-H bonds which are unreactive and not broken down by microbes.

99
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What does a curly arrow show in a mechanism?

Movement of a pair of electrons.

100
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Monomer used to make PTFE

Tetrafluoroethene: CF₂=CF₂