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kph 5/18
formula for m/s (conversion)
m/s(18/5)
formula for kph (conversion)
magnitude and direction of resultant
component method (magnitude and direction of resultant)
d, v, t triangle
URM (horizontal)
Vf = Vo + at
first UAM formula
d = Vot + ½ at²
2nd UAM formula
Vf² = Vo² + 2ad
3rd UAM formula
d = (Vo + Vf)/2 x t
4th UAm
Vox = Vo cosθ (h)
Voy = Vo cosθ (v)
projectile motion horizontal and vertical axis
fma triangle
force
Fg = Gm1 m2/r²
universal law of gravitation
mass x gravity
weight (N)
ΣFx = 0, ΣFy = 0
law of inertia
a = Vf - Vo / t
law of acceleration
mew (normal force)
friction force = ??
force x displacement
f x d x cos θ
△ KE
work
positive work if same direction
negative work if displacement is opposite (there is friction)
w=0 if perpendicular
3 cases for work
½ mv²
kinetic energy formula
mass x gravity x height
potential energy
KE + PE
mechanical energy
work/time
power
mass x velocity
momentum (P)
force x time
△ momentum
impulse (J)
ΣPi = ΣPf
collision
ΣKei = ΣKef
ΣKei ≠ ΣKef
elastic and inelastic
m1v1i + m2v2i = (m1 + m2) x velocity x force
perfectly inelastic