Stoichiometry and Molar Mass Calculations in Chemistry

0.0(0)
studied byStudied by 0 people
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/36

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

37 Terms

1
New cards

Mole Amounts of Pure Substances

4.003 g Helium Gas, 63.55 g Copper Wire, 200.59 g Liquid Mercury, 12.01 g Carbon Powder, 32.06 g Solid Sulfur

<p>4.003 g Helium Gas, 63.55 g Copper Wire, 200.59 g Liquid Mercury, 12.01 g Carbon Powder, 32.06 g Solid Sulfur</p>
2
New cards

Molar Mass

Calculation for the Molar Masses of Compounds

3
New cards

Molar Mass of Sodium Chloride

MNaCl: (1 x 22.99 g/mol) + (1 x 35.45 g/mol) = 58.44 g/mol

4
New cards

Molar Mass of Glucose

MC6H12O6: (6 x 12.01 g/mol) + (12 x 1.01 g/mol) + (6 x 16.00 g/mol) = 180.18 g/mol

5
New cards

Molar Mass of Calcium Phosphate

MCa3(PO4)2: (3 x 40.08 g/mol) + (2 x 30.97 g/mol) + (8 x 16.00 g/mol) = 310.18 g/mol

6
New cards

Formula Mass

Mass of a single molecule (for molecular compounds) or a single formula unit (for ionic compounds)

<p>Mass of a single molecule (for molecular compounds) or a single formula unit (for ionic compounds)</p>
7
New cards

Terminology: Formula Mass

Applies to ionic compounds

8
New cards

Terminology: Molecular Mass

Applies to molecular compounds

9
New cards

Formula Mass Units

Expressed in atomic mass units (amu)

10
New cards

Atomic Mass Examples

H (1.01 amu), O (15.9994 amu), C (12.0107 amu)

11
New cards

Percent Composition Calculation

Calculate the Percent Composition of Methane (CH4): Sum = 74.83 % + 25.17 % = 100 %

12
New cards

Percent Composition for Binary Compounds

The % composition of 1st element is first found, then subtract from 100 to find the % composition of the 2nd element.

13
New cards

Percent Composition for Compounds with 3 Elements

Find the % compositions of 2 of the 3 elements, then subtract their sum from 100 to find the % composition of the 3rd element.

14
New cards

Percent Composition of Glucose

Calculate the percent composition of glucose, C6H12O6

15
New cards

Percent Composition of Iron(III) Carbonate

Calculate the percent composition of iron(III) carbonate, Fe2(CO3)3

16
New cards

Empirical Formulas

The empirical formula of a compound can be determined from knowing the percent compositions of all the element types present in the compound.

17
New cards

Empirical Formula

The simplest whole number ratio of elements in a compound.

18
New cards

Molecular Formula

The formula that shows the actual number of each type of atom in a molecule of a compound.

19
New cards

Stoichiometry

The quantitative relationship between the reactants and products in a balanced chemical equation.

<p>The quantitative relationship between the reactants and products in a balanced chemical equation.</p>
20
New cards

Limiting Reactant

The reactant that is completely consumed first in a chemical reaction.

21
New cards

Excess Reactant

The reactant(s) that is/are leftover unreacted once the limiting reactant has been completely consumed.

22
New cards

Theoretical Yield

The maximum amount of product possible in a chemical reaction from given amounts of reactants.

23
New cards

Actual Yield

The amount of product obtained from a chemical reaction, which is often less than the theoretical yield.

24
New cards

Percent Yield

Quantitative measure of the efficiency and success of a chemical reaction.

25
New cards

Steps for Determining Empirical Formulas

1. Assume 100 g of the compound. 2. Equate the % composition of each element type to mass (g). 3. For each element type, convert g to mol. 4. Divide each converted mole value to the smallest mole value in the set. 5. If there are common decimals or fractions present, convert the number to an improper fraction, then multiply all values by the least common integer.

26
New cards

Finding the Molecular Formula

The molecular formula can be determined by knowing the empirical formula and the molecular mass of the compound, then calculating the ratio of the compound's molecular mass to its empirical mass.

27
New cards

Sample Calculation for Benzene

Benzene is composed of 92.24 % C and 7.76 % H by mass. Calculate its empirical formula.

28
New cards

Sample Calculation for Ascorbic Acid

Ascorbic acid is composed of 40.92 % C, 4.58 % H, and 54.50 % O by mass. The molecular mass of ascorbic acid is 176.14 amu. Calculate its molecular formula.

29
New cards

Balanced Chemical Equation

A chemical equation where the number of atoms for each element is the same on both sides of the equation.

30
New cards

Haber-Bosch Process

A method for producing ammonia, NH3, from nitrogen and hydrogen.

31
New cards

Combustion of Butane

The chemical reaction of butane, C4H10, with oxygen to produce carbon dioxide and water.

32
New cards

Common Decimals in Empirical Formulas

Common decimals or fractions present include 0.25 (1/4), 0.33 (1/3), 0.5 (1/2), 0.67 (2/3), 0.75 (3/4).

33
New cards

Stoichiometric Calculation

A type of calculation that involves chemical formulas and chemical equations.

34
New cards

Chemical Reaction

A process that leads to the transformation of one set of chemical substances to another.

35
New cards

Empirical Mass

The mass of the empirical formula of a compound.

36
New cards

Molecular Mass

The mass of a molecule, calculated as the sum of the atomic masses of its constituent atoms.

37
New cards

Subscript in Empirical Formula

The number that indicates the number of atoms of each element in the empirical formula.