Give the mechanism of free radical addition of HBr by filling in blanks
Step 1 Initiation: Carbon chain breaks __________ with light
step 2: The lone electron attacks ____ of HBr. The bond breaks, giving the electron to Br.
Step 3: The lone electron of Br attacks. the tertiary/primary carbon of the double bond. The double bond donates an electron to _______.
Step 4: The lone electron of the carbon chain attacks _____ of HBr. The bond of HBr breaks, giving an electron to ____. This produces a carbon chain with a ____ and _____, and a ___ ion with a _____.