11. Crystal Field Stabilisation - Other Geometries

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Which orbitals are destabilised for a tetrahedral complex? How does this affect the orbital layouts for crystal stabilisation?

  • Orbital environments in a tetrahedral are called e and t2

  • They are in fact swapped around and the two e orbitals are now lower energy and the three t2 orbitals are now higher energy.

  • This is because with tetrahedral symmetry, the dxy, dyz and dxz orbitals are destabilised as they point towards the point charges

  • dx2-y2 and dz2 are stabilised this time and are the lower energy orbitals

<ul><li><p>Orbital environments in a tetrahedral are called e and t2</p></li><li><p>They are in fact swapped around and the two e orbitals are now lower energy and the three t2 orbitals are now higher energy. </p></li><li><p>This is because with tetrahedral symmetry, the dxy, dyz and dxz orbitals are destabilised as they point towards the point charges </p></li><li><p>dx<sup>2</sup>-y<sup>2</sup> and dz<sup>2</sup> are stabilised this time and are the lower energy orbitals </p></li></ul><p></p>
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How does the field splitting in a Td system differ from Oh? What does this suggest about Td spin?

  • The field splitting symmetry is smaller in a Td system compared to Oh symmetry as there are only four ligands interacting with M.

  • Low spin configurations are rarely observed due tot his and if a strong field ligand is present, the square planar geometry will be favoured.

  • Δt = 4/9Δo

  • The smaller field splitting also implies that tetrahedral metal ions are always high spin

<ul><li><p>The field splitting symmetry is smaller in a Td system compared to Oh symmetry as there are only four ligands interacting with M. </p></li><li><p>Low spin configurations are rarely observed due tot his and if a strong field ligand is present, the square planar geometry will be favoured. </p></li><li><p><span>Δt = 4/9Δo </span></p></li><li><p><span>The smaller field splitting also implies that tetrahedral metal ions are always high spin </span></p></li></ul><p></p>
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What is the crystal field splitting diagram for a square planar complex? Why does this occur? What electron orbital is this favoured for?

  • d8 ions favour square planar geometry with a strong field

  • square planar is like removing the axial ligands from an octahedral (distortion along z-axis)

  • so all orbitals with a z component has its energy lowered as the repulsions between electrons and the metal ion and ligand decrease .

  • So it makes a row of two orbitals, with two stacked on top, with the dx2-y2 orbital with a large energy gap

<ul><li><p>d<sup>8</sup> ions favour square planar geometry with a strong field </p></li><li><p>square planar is like removing the axial ligands from an octahedral (distortion along z-axis) </p></li><li><p>so all orbitals with a z component has its energy lowered as the repulsions between electrons and the metal ion and ligand decrease .</p></li><li><p>So it makes a row of two orbitals, with two stacked on top, with the dx<sup>2</sup>-y<sup>2</sup> orbital with a large energy gap </p></li></ul><p></p>
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What magnetic property do d8 complexes have?

  • As all electrons spins are paired, the compound is diamagnetic

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What does the crystal field splitting look like for a linear complex?

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