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the interpretation of the slope coefficient in the model Yi=B0+B1ln(Xi)+ui is as follows
A a change in X by one unit is associated with a B1 × 100% change in Y
B a 1% change in X is associated with a B1% change in Y
C 1% change in X is associated with a change in Y of 0.01 x B1
D a change in X by one unit is associated with a B1 change in Y
C 1% change in X is associated with a change in Y of 0.01 x B1
In the regression model Yi= B0+B1Xi+B2Di+B3(Xi+Di)+ui, where X is a continuous variable and D is a binary variable, B3:
A has no meaning since (XiDi)=0 when Di=0
B has a standard error that is not normally distributed even in large samples since D is not a normally distributed variable
C indicates the differences in the slopes of the 2 regressions
D indicates the slope of the regression when Di=1
C indicates the differences in the slopes of the 2 regressions
Consider the polynomial regression model of degree Yi=B0+B1Xi+B2Xi2+…+BrXir+ui. According to the null hypothesis that the regression is linear and the alternative that is a polynomial of degree r corresponds to:
A H0:B3=0…,Br=0, vs H1: all Bj does not equal 0, j=3,…, r
B H0: Br=0 bs Br does not equal 0
C H0= Br=0 vs B1 does not equal 0
D H0=B2, B3=0…, Br=0, vs H1: atleastone Bj does not equal 0, j=2,…,r
D H0=B2, B3=0…, Br=0, vs H1: atleastone Bj does not equal 0, j=2,…,r
In the expression Pr(denyi=1/IRatioi, Black)=Φ(-2.26+2.74P/I ratioi+0.71Blacki), the effect of increain the P/I ratio from 0.3 to 0.4 for a white person:
A is 6.1 percentage points
B is 2.74 percentage points
C is 0.274 percentage points
D should not be interpreted without knowledge of R squared
A is 6.1 percentage points
Maximum likelihood estimation yields the values of the coefficients that:
A minimize the sum of squared prediction errors
B come from a probability distribution and hence have to be positive
C maximize the log likelihood function
D are typically larger than those from OLS estimators
C maximize the log likelihood function
Estimation of the IV regression model:
A requires only exact identification
B allows only one endogenous regressor, which is typically correlated with the error term
C is only possible if the number of instruments is the same as the number of regressors
D requires exact identification or over identification
D requires exact identification or over identification
In the case of the simple regression model Yi=B0+B1Xi+ui, i=1…, n when X and u are correlated, then:
A OLS and TSLS produce the same estimate
B the OLS estimator is biased in small samples only
C the OLS estimator is inconsistent
D X is exogenous
C the OLS estimator is inconsistent
The two conditions for a valid instrument are:
A corr (Zi, Xi)=0 and corr (Zi, ui)=0
B corr (Zi, Xi)=0 and corr (Zi, ui) does not equal 0
C corr (Zi, Xi) does not equal 0 and corr (Zi, ui)=0
D corr (Zi, Xi) does not equal 0 and corr (Zi, ui) does not equal 0
C corr (Zi, Xi) does not equal 0 and corr (Zi, ui)=0
Instrumental Variables regression uses instruments to
A isolate movementds in X that are uncorrelated with u
B establish the mozart effect
C increase the regression R squared
D eliminate serial correlation
A isolate movementds in X that are uncorrelated with u
The regression R squared is defined as follows:
A SSR/TSS
B SSR/n-2
C ESS/TSS
C ESS/TSS
Imagine you regressed earnings of individuals on a constant, a binary variable (Male) which takes on the value 1 for males and is 0 otherwise, and another binary variable (Female) which takes on the value 1 for females and is 0 otherwise. Because females typically earn less than males, you would expect:
A both coefficients to be the same distance from the constant, one above and the other below
B this to yield a difference in means statistic
C none of the OLS estimators to exist because there is perfect multicolinearity
D the coefficient for Male to have a positive sign, and for Female a negative sign
C none of the OLS estimators to exist because there is perfect multicolinearity
The following linear hypothesis can be tested using the F test with the exception of:
A B2=1 and B3=B4/B5
B B1+B2=1 and B3=-2B4
C B2=0
D B0=B1 and B1=0
A B2=1 and B3=B4/B5