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Why does 4-nitrophenol have a higher boiling point than 2-nitrophenol?
Compare the bromination of benzene vs. phenol (conditions and reasoning).
both undergo electrophilic attack
bromination of phenol is tribromination and bromination of benzene monobromination
bromination of benzene requires a halogen carrier such as AlBr3 but phenol does not
How does the O−H absorption differ between ethanoic acid and ethanol in an IR spectrum?
ethanoic acid - very broad peak at 2500-3300
ethanol - broad smooth 3230-3550
key distinction is that ethanoic acid has a peak at 1700 due to presence of c=o
How does the OH bond in a carboxylic acid differ from the OH bond in an alcohol in terms of infrared spectroscopy
The OH bond in a carboxylic acid shows a distinct, extremely broad absorption in IR spectroscopy, generally occurring between
2500--3300cm-1
(often overlapping with C-H stretches), whereas an alcohol's OH bond appears as a strong, broad peak at a higher wavenumber, typically
3200-3600
What are the two-stage observations when adding butylamine dropwise, then in excess, to aqueous copper(II) sulfate?
at first a light blue precipitate is formed
when excess the precipitate redissolves to form a deep blue solution
Write the equation for the reaction of [Cu(H2O)6]2+ with dropwise butylamine (RNH2). What is the role of the amine here?
[Cu(H20)6}2+ + 2CH3CH2CH2CH2NH2 —> [Cu(H20)4(OH)2 + 2CH3CH2CH2CH2NH3+
amine acts as a base (accepts proton from water ligand)
Write the equation for the excess addition of butylamine (RNH2) to the copper(II) hydroxide precipitate. What is the role of the amine here?
[Cu(H20)6]2+ + 4CH3CH2CH2CH2NH2 —→ [Cu(CH3CH2CH2CH2NH2)4(H20)2] 2+ + 2OH- + 2H20
the amine acts as a ligand
explain why different alkanes in crude oil can be separated by fractional distillation?
Different alkanes have different boiling points based on their carbon chain length and molar mass
Why does the reactivity of primary halogenoalkanes increase from chloro- to iodoalkanes? (3 Marks)
down the group the halogen atom gets larger
distance between 2 nuclei increases so the C-X bond length increases
the C-X bond becomes weaker and requires less energy to overcome
"Compare the rates of hydrolysis of 1-chlorobutane and 2-chloro-2-methylpropane."
1-chlorobutane is primary; 2-chloro-2-methylpropane is tertiary.
Tertiary halogenoalkanes react via SN1, while primary react via SN2.
The SN1 mechanism is faster because it involves the formation of a stable tertiary carbocation.
Inductive Effect: Mention that the three alkyl groups "push" electron density toward the positive carbon, stabilizing it (the inductive effect).
difference in drawing out the mechanism for a primary and tertiary halogenoalkane?
SN1 VS SN2
sn2 - contains a transition state
sn1 - draw two steps (halogen leaving - carbocation intermediate)
How does the classification (type) of a halogenoalkane affect its rate of reaction?
Tertiary > Secondary > Primary
Tertiary halogenoalkanes react via the SN1 mechanism.
Stability: This mechanism involves a carbocation intermediate.
Inductive Effect: Tertiary carbocations are the most stable because they have three alkyl groups that donate electron density (positive inductive effect) to reduce the charge density on the carbon atom.
Describe the stages by which a catalytic converter converts polluting gases in a car exhaust system? (3 marks)
adsorption of gases to catalytic surface
weakening of bonds on catalytic surface
desorption of products from catalytic surface
What are the conditions and reactants required for the conversion of benzene to nitrobenzene?
conc. HNO3 and H2SO4 heated under reflux with 50 degrees
COnditions and reactant required for the conversion of nitrobenzene to a phenyl amine
conc HCl and Tin - heated under reflux
What two reactions can be done to nitriles?
hydrolysed and reduction
Conditions and reactant required for the hydrolysis of a nitrile
acidic hydrolysis : dilute HCl heated under reflux to form carboxylic acid and ammonium salt
alkaline hydrolysis : NaOH and h20 heated under reflux to form sodium carboxylate salt and ammonia gas
Write a full redox equation from the half equations for following the two changes combined
MnO4- —> Mn2+
C2O4 2- —> CO2
2MnO4_ + 16H+ + 5C204 2- —> 2Mn2+ + 8H20 + 10CO2