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Entropy
measure of the energy lost to molecular disorder or randomness in a sample
units: J per Kelvin
+ value means system increaded in entropy
- value indicates that the entropy of the system decreased
Third Law of Thermodynamics
entropy of a perfect crystal at 0K is zero
microstates
invisible possible sections
More spread out particles
higher disorder/entropy
Gases have the highest what
entropy
products have more moles
entropy increase, thetaS is positive
Higher Temp
Greater KE, greater Entropy
Entropy increases
Decomposotion reaction
Increase in temp
Dissociation of ions or dissolution of a solute to form a solution
Endothermic phase changes
increase in the number of moles of gas
Gas expansion(decreasing p, increasing V)
Entropy decreases
Composition reaction
decrease in temp
precipitation or formation of a solid from aqueous solutions(aq → s)
exothermic phase changes
decrease in the number of moles of gas
Gas compression
Second Law of thermodynamics
Entropy of the universe increases in for a spontaneous process and remains unchanged when a system is at equilibrium
Equation for Entropy of a reaction
theta S = sum of thetaS (pdts) - sum of thetaS (rcts)
At equalibrium
theta S = 0
spontaneous process
theta S > 0
Gibbs free energy(G)
energy available in a system that can be used to do work
-G = favorable
Reactions that take place
thermodynamically favorable or spontaneous
Kinetic Control
favorable reaction that are very slow, look at the kinetics of the reaction to determine the rate of reaction
Enthalpy
energy required or released in a chemial process
exothermic = favorable ( negative H)
endo= unfavorable(Positive H)
Favorable G (non temp dependant)
-H and +S
Unfavorable G (non temp dependent)
+H and -S
temperature dependant favorable G
-H and -H
+ at high temp
-at low temp
+S and +S
+ at low temp
-at high Temp
G = thetaH - T thetaS
equation
if entropy is unfavorable at high temps
it determines
if enthalpy is unfavorable at low temps
it determines
theta G(reaction) = sum of thetaG(pdts) - sum of thetaG(reactants)
standard G of formation of reaction
What happens when a reaction is unfavorable what can you do
force it by supplying sufficent energy
light and electrical energy
or to Couple it into a reaction that is thermodynamically favorable
coupled system
the negative G from the thermodynamically favorable reaction provides the energy needed by the unfavorable reaction and drives the unfavorable reaction to proceed
G = -nFE
gibbs free energy equation
intermediates
in pdts and then in reactants in another step
oxidation-reduction reaction
electrons are transfered from one species to another
can be measured by an electrochemical cell
simple/Galvanic cell
two half cells
electrodes
solids(gas systems) that are placed into each of the solutions
cathode
reduction occurs because it attracts the cations from the salt bridge and the other solution
red-cat
Au3+ + 3e- →Au(s)
mass increases
the one with the higher reduction potential should stay as reduced and the other oxidized so flip
anode
attracts anions from the salt bridge and the solution
an-ox
Ag(s) →Ag+ + e-
mass decreases
FAT CAT
from anode to cathode
E cell equation
Ecell = Ereduced(anode) - Eoxidation(cathode)
positive Ecell
favorable
Galvanic or voltaic cells
-Ecell
unfavorable - requires external source
Electrolytic cell
magnitude of voltage doesn’t change when..
multiply one or more of the reactions in order to balance
1 volt
1 joule/columbs
reached equilibrium
zero for cell potential
Nernst Equation
shows the relationship between the cell potentials at non-standard states and standard states
Q
pdts/reactants
E - E(standard) - (RT/nF)lnQ
nernst equation
always use the ions when molarity for finding Q
Q
tells us which way the equation shifts
reaction quotient
current
defined as the amounts of charge transferred over time
(I) is measured in amperes
1 ampere = 1 coulomb/second
Faradays constant F
way to relate coulombs to moles of electrons
current equation
I = q/t
Q>1
“Too manhy products”
E cell will be less than Standard Ecell
Products are favored so more products are formed
Q<1
Ecell will be greater than standrad Ecell
reactants are favored so less products are formed
if Q=K
at equilibrium