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sec(x) =
1 / cos(x)
cosec(x) =
1 / sin(x)
cot(x) =
1 / tan(x) or cos(x) / sin(x)
sin and cos equation?
sin²(x) + cos²(x) = 1
how to derive sin²(x) + cos²(x) = 1
right angled triangle, hypotenuse 1. one length sin(x) other cos(x) .
using Pythagoras, sin²(x) + cos²(x) = 1
tan and sec equation?
tan²(x) + 1 = sec²(x)
derive tan and sec equation
divide sin²(x) + cos²(x) = 1 by cos²(x)
you get tan²(x) + 1 = sec²(x)
cot and cosec equation/
1 + cot²(x) = cosec²(x)
derive cot and cosec equation
divide sin²(x) + cos²(x) = 1 by sin²(x)
you get, 1+ cot²(x) = cosec²(x)