Define a conservative vector field in terms of line integrals around closed paths.
For a vector field **A** to be conservative, the line integrals ∮ **A**.dl must be zero for all closed paths
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Define a conservative vector field in terms of the curl of a vector field.
for a vector field to be conservative the curl of the field is 0 everywhere.
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Given that the line integral of ∇F around any closed path is zero (∮∇F .dl = 0) , explain why a conservative field must have zero curl everywhere. (hint :∇x(∇F) = 0)
∮ **A**.dl = 0 for a conservative field, and ∮∇F .dl = 0 for all closed paths. therefore if A is conservative A = ∇F. using the ‘hint’ and **∇** x **A** = 0 is conservative.
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what does ∇x(∇F) equal?
0
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if ∇x**A** = -xk and ∮**A** .dl = -1/3 is the field conservative?
no as the curl and the closed path integral of the field does not equal 0.
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what is the conversion for **x** into **cylindrical** polar coordinates?
x = ρcosΦ
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what is the conversion for **y** into **cylindrical** polar coordinates?
x = ρsinΦ
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what is the conversion for **z** into **cylindrical** polar coordinates?
z = z
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what is the **line integral** equation for **cylindrical polar** coordinates?
Explain why your results for divergence and curl mean (they = 0) that the Laplace equation is satisfied for this flow far away from the source and sink. (There is no need to consider what happens very close to the source / sink.)
As the curl of the field is 0 we can write the vector field as the gradient of a scaler field. As the divergence also equals zero we can rewrite it as laplances equation
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Explain why the flow outside the boundary B is identical to that which would be obtained if B became a solid boundary.
If boundary B were a solid boundary laplances equation would still be satisfied and the boundary conditions would remain the same. Therefore we obtain the same answer.
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What are stagnation points?
Stagnation points are when v = 0
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Write down two boundary conditions for the electrostatic potential for this configura- tion of charges. \[hint: conductor is an equipotential\]
* As V→ 0 r → infinity * Potential diverges on the line charge