Aromatic chemistry and amines

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19 Terms

1
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Explain why modern benzene is more thermodynamically stable than kekule structure 

Electrons delocalised in a ring,overlap of p orbital 

2
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Name the mechanism + reagents +conditions for the reaction of sulfuric+nitric acid with benzene

Electrophillic addition 

Concentrated H2SO4 and HNO3

Reflux 

3
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Explain the bonding in benzene

Each c has 3 covalent bonds

Spare electrons in p orbital overlap to form a pie cloud 

Delocalisation 

4
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Explain the shape of benzene 

Planar 

Hexagon /6 C ring 

C-C bonds equal in length 

5
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Compare the stability of benzene with that of hypothetical cyclohexa 1,3,5 triene

Enthalpy of hydrogenation of cyclohexene is =-360

Enthalpy of hydrogenation of benzene less exothermic by 152kj mol

Benzene Lower in energy so more stable

Because of delocalisation 

6
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Suggest a value for Enthalpy of hydrogenation of cyclohexa 1,3 diene

Justify 

-239 to -121

Double bonds separated by one single bond

Allows some delocalisation of p orbitals 

7
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Use Enthalpy of hydrogenation data to show that benzene is 152kj mol more stable than hypothetical compound of cyclohexa-1,3,5-triene

3(-120)-(-208)=-152

8
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State in terms of bonding why benzene is more stable than kekule (1)

Benzene ring of delocalised electrons

9
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Suggest bond lengths for

Single bond in kekule 

Double bond in kekule 

Single bond in benzene 

147

135

140

10
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Give the 2 equations for the formation of a nitronium ion

H2so4 + HNO3——> HSO4 minus + H2NO3 plus

H2NO3 plus ——→ NO2 plus + H20

11
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Give the overall equation for the formation of nitronium ion

H2so4 + HNO3—→HSO4- + NO2+ +H20

12
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What are the two types of electrophillic substitution and conditions for each?

Nitration-conc h2so4 and Hno3, warm-UNDER 55 degrees for single

Friedel craft acylation

Acyl chloride

Alcl3 catalyst

Reflux

dry ether

13
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What is the electrophille in acylation and what does this form as products

Acylium ion

Phenyl ketone and HCL

14
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What do you use to prepare aromatic amines

Equation for nitrobenzene

using tin/sn and HCL

Reducing agent

C6H5NO2+ 6H —→ C6H5NH2+ 2H20

15
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Why aq solution obtained in reduction of nitrobenzene even tho phenylamine insoluble

C6H5NH2 ionic salt

16
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Give two step synthesis of aliphatic amine

And give strengths weaknesses

Nucleophillic sub aq ethanolic KCN

Reduction of nitrile H2 Nickel

-high atom economy

-single product/pure

-low% yielf

17
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Give one step synthesis of aliphatic amine

Strengths and weaknesses

NH3 excess nucleophillic substitution

Low atom economy

Further substitution-impure product

18
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How can you ensure major product is quaternary salt

Excess haloalkane

19
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Suggest why amines with benzene ring are weaker 

Lone pair on N 

Delocalised into the ring 

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