1/11
Looks like no tags are added yet.
Name | Mastery | Learn | Test | Matching | Spaced | Call with Kai |
|---|
No analytics yet
Send a link to your students to track their progress
Dynamic equilibrium
Reversible reaction where rates of forward and reverse reactions are equal
Kc and Kp Exothermic
Heat is a product
Increase temperature
shift LEFT (remove heat)
Kc/Kp decreases
Decrease temperature - favours exothermic side
shift RIGHT
Kc/Kp increases
Kc and Kp Endothermic
Heat is a reactant
Increase temperature - favours endothermic side
Shift RIGHT
Kc/Kp increases
Decrease temperature
Shift LEFT
Kc/Kp decreases
Kc
Equilibrium constant terms of concentration in solutions
Kp
Equilibrium constant terms of partial gas pressure
Calculating Kc
aA + bB = cC +dD
Kc = [C]c[D]d / [A]a[B]b
Calculating Kp
Kp = (pC)c(pD)d / (pA)a(pB)b
Calculating partial pressure
pp = mole fraction x total pressure
Magnitude of Kc Kp
K>1 Products favoured (higher conc products at equilibrium)
K<1 Reactants favoured (higher conc reactants at equilibrium)
K=1 Mixture of both
Large k→ lies to right
Small K → lies to left
K tells you..
Position of equilibrium
Explain why powers included in calculations
Powers correspond to stoichiometric coefficients
Reflects ration in which substances react and formed
How does weak acid and its sodium salt maintain pH
RCOOH = RCOO- + H+
RCOONa = RCOO- + Na+
H+ removed by salt A- + H+ →HA
OH- removed by acid OH- + HA → A- + H2O