Math Geo sequence + Log Question bank

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28 Terms

1
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1.) 3
2.) 1
3.) 2log 2( 3) +3
4.) 2
5.) 3

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2
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1.) x=1/4
2.) x=8
3.) x=2

4.) no valid solutions

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3
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1.) 2a+1/b
2.) 2ln3/ln5

4a ln(15) = (a+2) ln 81

solve for a

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4
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4.1.)

X-Intercept: (1,0)

Pass Point: (e,1)

Vertical Asymptote: x=0

Range: (-inf, +inf)
Domain: (0, +inf)


2.) 2(ln -2(x+(1/2)-2)-1)

3.) Vertical stretch by 2
Reflect over x axis
Translate (-3, -1)

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5
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f(x)
Domain: (-inf, +inf)
Range: (-2, +inf)
Horizontal Asymptote: y = -2
f-1(x)
Domain:(-2, +inf)
Range: (-inf, +inf)
Vertical Asymptote: x = -2
X intercept: (8,0)
Y intercept: (0, -0.6989)

<p>f(x)<br>Domain: (-inf, +inf)<br>Range: (-2, +inf)<br>Horizontal Asymptote: y = -2<br>f-1(x)<br>Domain:(-2, +inf)<br>Range: (-inf, +inf)<br>Vertical Asymptote: x = -2 <br>X intercept: (8,0)<br>Y intercept: (0, -0.6989)<br></p><p></p>
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6
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f(x)=log sqrt2 (-x+2)

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7
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1.)k = 500
2.) 10^6

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8
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I = 10.2

<p>I = 10.2 </p>
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9
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1.) R(200A0) = log(200A0/A0) = log(200) = 2.301
2.) Find (A1/A2)
6.8-5.8
10^0.9

3.)

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10
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11
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k = 2

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12
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13
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i) a1: -1 CD: 2
ii) a1: 3/2 CD:-3/2

<p>i) a1: -1 CD: 2<br>ii) a1: 3/2 CD:-3/2</p>
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14
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an = 11-3(n-1)
an = log p (b) + (log p (a))²

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15
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i) First term: -2 CD:(1/2)
ii) First term: =-2/3 CD:(-1/2)

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16
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an = a1 * r^(n-1)
i) an = 2 × 2^(n-1)
ii) an = -2 × (1/2)^(n-1)

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17
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1.) 4+8+16+32+64+128
2.)

3.) -13116

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18
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1.) 5 sigma n=1 1/5 × (1/2)^(n-1)
2.) 8 sigma n=1 4 * -3^(n-1)

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19
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7 Terms

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20
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11th term 2187

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21
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First Convert the Annual interest and Annual pay time to months
Time - r: 7 × 12 = 84
Interest per month - n: 0.00225

Use the Loan Amortization Formula
Then solve for the monthly payment amount M

<p>First Convert the Annual interest and Annual pay time to months<br>Time - r: 7 × 12 = 84 <br>Interest per month - n: 0.00225</p><p>Use the <strong>Loan Amortization Formula</strong><br>Then solve for the monthly payment amount M</p>
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22
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First Year: $476.72
Total Pay: $3167.86

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23
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1.) First one CD: 5
2.) Last one CD: ½

3.) 1/64

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24
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25
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Use Infinite series function
Solve for R algebra substitution

<p>Use Infinite series function<br>Solve for R algebra substitution </p>
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26
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1) Explain it in plain words
2) Use the finite sequence formula
-First term a = 4*(0.8)
-Common ratio = (0.8)
-Don’t forget to add 2 meters
To find the total distance travelled in terms of n
3) Use infinite series

<p>1) Explain it in plain words <br>2) Use the finite sequence formula<br>    -First term a = 4*(0.8)<br>    -Common ratio = (0.8)<br>    -Don’t forget to add 2 meters<br>    To find the total distance travelled in terms of n<br>3) Use infinite series</p>
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27
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1i) r = (an)/(an-1)
Thus r = 4/(k-4) and r = (k+2)/4
(k+2)/4 = 4/(k-4)
ii) Cross multiply and solve for k
4 × 4 =(k-4)(k+2)
Simplify and rearrange to get
k^2−2k−24=0


2i)Use quadratic formula to solve for k
k = 6 k = -4
ii) Find all possible values of r

Substitute k into the r = equations from before

r = -0.5 and r = 2


<p>1i) r = (an)/(an-1)<br>     Thus r = 4/(k-4) and r = (k+2)/4<br>      (k+2)/4 = 4/(k-4)<br>ii) Cross multiply and solve for k<br>      4 × 4 =(k-4)(k+2)<br>    Simplify and rearrange to get<br>      <span><em>k^</em>2−2<em>k</em>−24=0</span></p><p><br><span>2i)Use quadratic formula to solve for k</span><br><span>      k = 6    k = -4</span><br>ii) Find all possible values of r</p><p>   Substitute k into the r = equations from before</p><p>   r = -0.5 and r = 2 </p><p><br></p>
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28
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Finite Series Formula Sn = (a1(1-r^n))/(1-r)
Infinite Series Formula Sn = a1/(1-r)
-1 < r < 1

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