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Redox
Oxidation is loss of electrons
Reduction is gain of electrons
When this happens at once, this is redox (OIL RIG)
Oxidising agent
Accepts electrons and undergoes reduction
Reducing agent
Donates electrons and undergoes oxidation
Oxidation numbers
Oxidation
Increase of oxidation numbers
Reduction
Decrease of oxidation number
E.G. Na + 1/2 Cl2 ---> NaCl2
Sodium is oxidised because oxidation number increases from 0 to +1
Chlorine is reduced because oxidation number decreases from 0 to -1
Redox reactions
Metal acid reactions are redox
Metal atoms lose electrons and are oxidised
Hydrogen ions gain electrons and are reduced
Any species whose oxidation number does not change is a spectator ion
Not part of ionic equation
Rules of oxidation numbers
Un-combined elements have an oxidation number of 0
Atoms in molecules bonded to identical atoms (diatomic molecules) have oxidation number of 0
Monatomic ion's ON is same as its charge (Fe3+ has ON of +3)
In molecular ion, sum of ON is equal to overall charge
Neutral compounds have ON sum of 0
Combined oxygen has ON of -2 except in peroxides where its -1
In OF2 its +2
Combined hydrogen usually has an ON of +1 except in metal hydrides where its -1
Oxidation number of compound containing 2 non-metals is given to more electronegative element
Roman numerals
Roman numerals are used after element's name to specify its oxidation number
Iron (II) has ON of +2
Iron (III) has ON of +3
-ate compunds
Ions ending in -ate are made up of oxygen and another element
Element bonding to oxygen has variable oxidation number
Roman numerals are used after compound's name to differentiate between these numbers
Reduction in acidic conditions
Check oxi/red element is balanced on both sides
Add H20 to balance out any oxygen in compound
Add H+ to balance out any hydrogen in H20
Use electrons to balance the charge
Reduction in alkaline conditions
Check element is balanced
Add 2x OH- needed to balance oxygens in compound
Add H2O to balance OH-
Use e- to balance the charge
Combining half equations
Scale up and multiply half equations to ensure e- are equal
Cancel out anything that appears on both sides (water, H+, OH- and e-)
Subtracting half equations
Scale up half equation so moles of element is equal
Subtract half equation from redox
Place same number of e- from half equation on the opposite side
Simplify if needed
Disproportionation
When single element is both oxidised and reduced
e.g. in Cl2 + 2OH- ----> ClO- + Cl- + H2O
Cl is both oxidised (increase in ON)
Cl is both reduced (decrease in ON)