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Velocity
• Average velocity = displacement / time (m/sec)
- Vector quantity
Baseball, reaction time of a hitter needed to hit a pitch of 90 mph from 60.5 feet (the ball is released 2.5 feet in front of mound)
- Calculate time
0.44 seconds
Application: GPS/LPS - Player Load Monitoring
Uses combo of inertial measurement units (accelerometers, magnetometer, gyroscopes) & satellites to triangulate athlete's position - 10 Hz
• Running/cycling distance, velocity/speed, acceleration, deceleration, jumps, COD, impact
Load Monitoring
Internal (RPE, HR, BP, HRV, biochem markers)
Vs.
External (key performance indicators [KPI])
- Tracking software daily, weekly, monthly, yearly
Internal Load Monitoring
RPE, HR, BP, HRV, biochem markers
External Load Monitoring
key performance indicators (KPI)
Acceleration
rate of change of velocity
- Object accelerates when it speeds up, slows down, starts, stops, & changes direction
- Instantaneous versus average acceleration
Acceleration equation
a=vf-vi/t
Vf
final velocity
Vi
initial velocity
t
time
Is Acceleration directional?
No, only + or -
- Instantaneous versus average acceleration
Explain Pelvic Acceleration with a progression that increases with difficulty
The more difficult the progression, the greater the pelvic ACC
Projectile Examples
Human body and objects
Uniform Acceleration: Projectiles
- constant net external force acting on an object with vertical motion being constant
- an object that has no external forces acting on it other than gravity
- Vertical motion is a constant: g = -9.81 m/s^2
Law of Inertia
horizontal velocity component is constant
Vertical Velocity
will change from + at release, to 0 peak, and - upon return
Vpeak
0 m/s
Horizontal Acceleration
0 m/s^2
Vertical Acceleration
-9.81 m/s^2
Projectile Calculations
Vertical position
Vertical velocity
Horizontal velocity
Horizontal position
Vertical & horizontal displacement
Flight time
Vf = Vi + gΔt
Solve for projectile’s final velocity
- a = Vf – Vi / Δt will also be = g
- Vf – Vi = g Δt
1st Law of Uniformly Accelerated Motion
A projectile's final velocity is related to its Initial velocity & constant acceleration
Vf^2 = Vi^2 + 2gΔy
If vertical displacement is known
3rd Law of Uniformly Accelerated Motion
A projectile's final velocity is related to its acceleration & displacement
Vf = (g)(Δt)
or
Vf^2 = 2g(Δy)
If an object is free falling (Vi = 0m/s)
Vi^2 = 2g(Δy)
if an object is thrown up (Vf = 0 m/s)
2nd Law of Uniformly Accelerated Motion
A projectile's final position is related to its initial velocity & acceleration
yf = yi + (vi)iΔt - (1/2)g(Δt^2)
solving for vertical position
yf = ½(g)(Δt)^2
Free falling objects (yi, vi = 0)
ΔY = (Vr ∙ sinƟ)^2 / 2g
if the projectile is released at an angle instead of directly upward
Tup = resultant v (sinθ)= / g
Solve for flight time when resultant velocity & angle are known
Total flight time = 2(timeup)
Tup = Tdown : landing & release heights :
SQRT(2gx + (vsinθ)^2 / g^2)
When landing & release ht differ
Vh x Δt
horizontal displacement
xi + Vh(Δt)
horizontal position
Range
total horizontal displacement of a projectile
v^2 x sin2Ɵ / g
range on a flat ground
v^2 ∙ sinƟ ∙ cosƟ ∙ + x ∙ SQRT((Vy^2) + 2gh) / g
Range when projectile is released from elevated height (h)
Optimal angle if release height = landing
45°
Optimal angle if landing height is lower than release
less than 45°
Optimal angle if landing height is higher than release
greater than 45°
Max vertical height
closer to 90°
When is a 45° angle optimal
if there is an equal need for vertical and horizontal velocity
What affects optimal angle?
angle affected by Vv and Vh at release
Projection Speed of Implement decreases if:
projection angle increase
What's more critical, projection speed or angle?
projection angle
Optimal angle of shotput
26-42°
Average angle of shotput
37°
Optimal angle of Javelin
about 32-36°
Optimal Angle of Long Jump
18-27 degrees
- take off angle decreases as velocity increases
Discus (Opt, Avg, Deviation)
Opt Angle: 35-40°
Average: 35°
2° deviation = decrease 0.2m in distance
5° deviation = decrease 1.26m in distance
High Jump optimal angle
approached from a 40-48° angle
Soccer Throw-in
Optimal Angle: 30°
- Distance of throw may increase by a few meters by using fast backspin, but ball must be launched at a slightly lower release angle
Baseball Swing
35°
- Ball arrives 10° downward trajectory
- Hitter Swings at 25°
Golf Drive
Depends on many factors such as club head velocity, ball velocity, spin rate, loft angle, backspin, drag & lift force
- Avg PGA TOUR player = launch angle of 11.2° &spin rate of 2,685 rpm
- Contact time < 0.5 ms, swing speeds > 120mph, forces > 5 kNmph, forces > 5 kN
- Loft Angle
Loft Angle
angle clubface makes with the vertical when club head impacts ball
Projection of Accuracy
Balance between projection angle, velocity, release & landing height, distance from target, &barriers
•Small projection angle = ↑ horizontal component & ↓ flight time
•Large projection angle = ↓ horizontal component & ↑ flight time
Small Projection Angle
↑ horizontal component & ↓ flight time
Large Projection Angle
↓ horizontal component & ↑ flight time
Optimal Angle for a jump shot
52 degrees
- (ranges from 49-55 degrees)
- angle may increase closer to rim
How to convert mph to ft/s and vise versa
1 mph = 1.47 ft/s
1 ft/s = 0.68 mph