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Moment
The ______________ of a force is a measure of its tendency to cause a body to rotate about a specific point or axis. This is different from the tendency for a body to move, or translate, in the direction of the force.
creates angular movement!
Moment
___________= Linear force * moment arm
SI Units: (Newton.meters) or N.m
1. Linear force
oLine of action of the linear force
oPoint of application
oDirection
oAngle of application (inclination)
2. Axis
3. Some kind of distance between the linear force and axis
oDistance is the perpendicular distance between the line of the force and the axis – called moment arm
In order to create a moment we need to have 3 conditions met, what are they?
internal moment
What is a rotational force or torque provided by anatomic structures of the body (forces comes from within the body)?
Linear force, parallel
For internal moments a __________ force is occurring.
The Line of action is usually __________ to the direction of the muscle fibers
attachment, toward
For internal moment...
- Point of application is at the distal ___________ of the muscle (via the tendon) on the moving segment
- Direction moving __________ the stabilizing segment
Angle of Application (Inclination)
What is the angle between the line of action of the muscle (represented by the tendon) and the long axis of the bone onto which the tendon inserts (on the side of the joint axis.)?
In this picture is 100 degrees!
Axis
What is the
1) Instantaneous center of joint rotation (moves as joint moves)
2) Fulcrum around which angular motion occurs
3) Pivot point for angular motion
moment arm
- also called force arm, resistance arm, effort arm
What is the perpendicular distance from linear force to the axis?
moment = force
moment arm = distance from axis to linear force
_________ = force
______________ = distance from axis to linear force
MOMENT ARM
Good visual
YES. It has to be a perpendicular line to the linear force and MUST create a 90 degree angle.
- the picture demonstrates this idea
Can the moment arm line of action extended past the segment?
Segment
Moment arm
The force vector attaches on the ___________
________________ forms a 90° angle with the line of action
Blue circle = axis
Curved red arrow = angular force
Linear red arrow = linear force
General Abduction Shoulder Movement.
Blue circle = ?
Curved red arrow = ?
Linear red arrow = ?
external moment
What is a rotational force or torque provided by forces external to the body (usually ground reactive force, momentum or gravity)?
Gravity and Added resistance / free wt - are at the CoM of the segment being acted upon
NO, Added resistance / manual is at the point of contact!
What external moments have points of application that occur at the CoM?
o Gravity
o Added resistance - weights
o Added resistance - manual
Gravity
This external moment is generally vertical with direction pointing down?
in line of directed force
This picture is an example of manually added resistance, what would the line of action direction be?
Moment arm
Other names:
o Moment arm
o Resistance arm
o Effort arm
What is the line that is perpendicular (at right angle to or is at 90°) to the line of action of external force to joint axis of rotation?
opposite
- (and vice versa - internal is opposite to external)
- Ex: Lateral shoulder raises, the weight (external force is going down) and the deltoid is working to oppose this force (internal force pointing upward)
External moment direction will be ____________ to the internal moment at the same joint.
flex
(Example: Biceps are in front of joint so will flex)
If line of action of muscle is anterior to coronal axis, muscle will _______ the joint
(exception -- knee)
extend
(Example: triceps are posterior to join so will extend)
If line of action is posteriorly (behind) to the frontal axis, muscle will ________
Anterior deltoids = flex
Posterior deltoids = extend
Using this principle the anterior deltoids in front of the joint will _________ and the posterior deltoids behind the joint will __________?
abduct
If line of action of muscle passes superiorly to A/P axis, muscle will ________
adduct
If line of action of muscle passes inferiorly to sagittal or A/P axis (thick line going front/back), muscle will ________
internally or externally rotate
Subscapularis = in front of the longitudinal axis will internally rotate
Teres minor = behind the longitudinal axis will externally rotate
Location of muscle to longitudinal axis determines whether it will _________ or ___________ rotate
Red circle = axis
Red straight line = linear force
Red curved line = angular force
(The external force of the backpack pulls you back and down but the internal forces of the body pull you forward to attempt to keep you upright)
Red circle = ?
Red straight line = ?
Red curved line = ?
Red circle = axis
Red straight line = linear force
Red curved line = angular force
(External forces pulling you down toward the suitcase and internal forces trying to pull you upright)
Red circle = ?
Red straight line = ?
Red curved line = ?
B, the moment arm is greater thus the force is much greater than in picture A
In which picture will there be more force acting on the knee? A or B?
internal moment
When an external moment is acting on a joint, we usually want the body to respond by creating an opposing ________ moment
Posterior to Cervical
Anterior to Thoracic
Anterior to Knee
Anterior to Ankle
For correct posture the line of gravity is....
____________ to Cervical Vertebrae
_________ to Thoracic
___________ to Knee
____________ to Ankle
summated
Vectors can be ________________ so force composition allows for the addition of the force vectors representing two or more forces into a single resultant force
(A + B = C) but with vectors
1) Normal or typical motion
2) Poor movement patterns/poor motor control motion
When multiple internal and/or externals forces are acting at the same time composition can determine if the resultant action is: (2)
Co-linear (same line)
Co-linear or NOT co-linear?
NOT co-linear
Co-linear or NOT co-linear?
Linear system
A _________ system can be thought of as a tug of war
Parrallelogram
Opposite sides are parallel but not 90 degree angles
:), the more forces the harder it gets
This picture shows how the creation of a parallelogram can be used to find effect of non-linear forces.
Move vector down and create a polygon
Another way to find non-linear forces effect is to create a polygon (chain).
:)
- Order doesn't matter
Another example of polygon (chain) creation with 3 vectors.
:)
4 common errors when adding vectors are....
1. Magnitude not maintained
2. Direction not maintained
3. Tail-to-tip not followed
4. Resultant not correctly drawn tail-to-tip or to end of completed chain
combined
Why is vector addition important?
- To determine action of ___________ forces
:)
Example of combined forces of rotator cuff.
Is an action that has all combined forces of the deltoid working!
Anterior, posterior, and middle deltoid.
Why is manual muscle test (MMT) full deltoid muscle in shoulder abduction?
Combined forces of upper and lower pec major.
How does pectoralis major adduct?
Down to the left
Which way would the resultant be oriented?
:)
How you would draw the resultant.
The resultant, or combined, effect of these forces is directed toward the trochlear groove of the femur as a joint compression force (CF).
What would the resultant force be in this image?
perpendicular
The two component forces are _______________ to each other with the resultant in between
point of application
All 3 parts (the 2 components and the resultant) have the same point of _______________
parallel, perpendicular
One component will act __________ to lever, the other will act ______________ to the lever
Resultant force
Direction of vectors depends on direction of _________
rectangle
When lines drawn connecting tips of 2 components, a ___________ will result
oParallel component
oTangential component
oRadial component
oFx
Component Parallel to Lever has many different names.
oPerpendicular component
oNormal component
oTransverse component
oFy
Component Perpendicular to Lever has many different names.
tangential
Parallel component to the lever or segment on which it is acting will be the ____________ component with a primary function of compression or distraction
RED LINE
normal
Perpendicular component to the lever or segment on which it is acting will be the _________ component with a primary function of providing rotary movement
GREEN LINE
1) angular
2) compression in A-B, distractive force in D
3) stabilizing
The normal force, (Fy in the drawings) actually contributes to the joint _______ motion
Tangential force (Fx) creating ________ force on the joint in A – B; and a ___________ force in D
Tangential component can act as a _________ force for the joint
opposite
Tangential
Normal force acts on segment to try to produce motion _________ to that of the muscle forces (Fy)
________ may be compressive or distractive (Fx)
DO NOT
they cause compression or distraction
Tangential components do or do not cause rotation?
QLf - internal force (Quads)
FxQLf - parallel component (trying to flex knee)
FyQLf - perpendicular component (trying to extend knee)
GLf - gravity
QLf - ?
FxQLf - ?
FyQLf - ?
GLf - ?
In the picture on the left
- Clinician working harder on left
- Pt. working harder on the left (NEED much more force to resist knee extension is external force is further away, will have a much longer moment arm)
You want to resist or test knee extension. Which of the hand placements in the graphic would make it 'easier' on you?
BOTH, down more to first rotate the wheel and the push it forward.
So, is the PT pushing the wheelchair forward or downward? If both, in which direction is she pushing more?
COS
_______ is related to the adjacent side of the right triangle (typically associated with the Cartesian system x-component, although not always)
SIN
______ is related to the opposite side of the right triangle (typically associated with the Cartesian system y-component, although not always)
TAN
____ is the association between the opposite and adjacent sides
sine = opposite/hypotenuse
cosine = adjacent/hypotenuse
tangent = opposite/adjacent
SOH, CAH, TOA
•cos θ = Fx/QLf (adjacent/hypotenuse)
•sin θ = Fy/QLf (opposite/hypotenuse)
•tan θ = Fy/Fx (opposite/adjacent)
Typically used when the angle is known and one side magnitude is known:
•θ = cos-1( Fx/QLf) [adjacent/hypotenuse]
•θ = sin-1( Fy/ QLf) [opposite/hypotenuse]
•θ = tan-1(Fy/Fx) [opposite/adjacent]
When just finding the angle: