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Math 152 Exam 2 Concepts
Math 152 Exam 2 Concepts
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1
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How would you solve a definite improper integral with bounds from negative infinity to positive infinity?
Split them up into an integral from negative infinity to 0 and 0 to infinity and then add them together
2
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If you have an integral where the bounds are a to b and the function is discontinuous at 'b'...
When solving the integral you take the limit of the function approaching 'b' from the left
3
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If you have an integral where the bounds are a to b and the function is discontinuous at 'a'...
When solving the integral you take the limit of the function approaching 'a' from the right
4
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If you have an integral where the bounds are a to b and the function is discontinuous at a value in between the bounds ('c')...
When solving the integral you split the integral from 'a' to 'c' and then 'c' to 'b' and then add them together
5
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For a p-integral...
p
6
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(Comparison theorem) if bigger is convergent...
smaller is convergent
7
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(Comparison theorem) if bigger is divergent...
the comparison test fails
8
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(Comparison theorem) if smaller is divergent...
bigger is divergent
9
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(Comparison theorem) if smaller is convergent...
the comparison test fails
10
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(Sequences) if the limit as n approaches infinity exists...
the sequence converges
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(Sequences) if the limit as n approaches infinity does not exist...
the sequence diverges
12
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(Sequences) A(n) is decreasing if...
A(n) > A(n+1)
13
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(Sequences) A(n) is increasing if...
A(n) < A(n+1)
14
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As sequence is monotonic if...
it is neither increasing or decreasing
15
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If the sequence is convergent...
The sequence is bounded!
16
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What is the test for divergence?
If the limit of A(i) is not equal to zero or does not exist, the series is divergent
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How do you find A(n) given S(n)?
Use the formula A(n) = S(n) - S(n-1)
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What is the integral test?
Treating A(n) as F(n) and if the integral of F(n) converges then A(n) converges, and if the integral of F(n) diverges then A(n) diverges
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What are the requirements for the integral test?
Must be continuous, positive, and decreasing on the interval from [1, oo) or [a, oo)
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