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Sn1 rate depends on…
Carbocation stability when the leaving group leaves
Sn1 rate equation
Rate = k[thing with leaving group]
Sn1 preferred degree/hinderance
3º
3º Alkyl halides probably mean…
Sn1 reaction
Sn1 nucleophile strength
weak nucleophiles, but not that important
Sn1 preferred solvent
polar protic to steal the leaving group and stabilize the charge of the carbocation and and the LG.
they also surround the nucleophile, making it weaker
The solvent has an H bonded with O,N,S like H2O
Sn1 to help stabilize the carbocation and the LG, and make the nucleophile weaker
Sn1 steps
leaving group leaves, carbocation formed
(hydride / methyl shift)
weak nucleophile attacks frontside or backside’
result: 50:50 racemic mixture of enantiomers
Sn1 sterochemistry
Raceism
raceist mixture was formed
Sn1 sterochemistry
Sn2 rate depends on
how much steric hinderance there is and nucleophile strength
Sn2 rate equation
Rate = k[thing with the leaving group][nucleophile-].
Sn2 preferred degrees/hinderance
1º less protection from getting backside attacked
1º alkyl halide is probably
Sn2
Sn2 preferred nucleophile strength
strong nucleophile so it can give backside attacks
strong nucleophile present like Cl-
probably Sn2 unless there is a polar protic solvent, which weakens the nucleophilicity of the Cl
Sn2 preferred solvent
polar aprotic to dissolve the reactants but not solvate the nucleophile, enhancing its reactivity.
Polar aprotic solvent like DMF, DMSO, acetone, acetonitrile, oxygen in a pentagon, etc
probably Sn2 so the nucleophile is still free to give backside attacks
Sn2 preferred nucleophile size
small nucleophile so it can slip in and give backside attacks
Sn2 steps
Strong Nucleophile attacks the substrate from the opposite side of the leaving group
(Transition state forms, resulting in inversion of configuration.
Leaving group kicked out
Sn2 stereochemistry
inversion R→S, S→R
there is inversion or stereochemistry and only 1 entantiomer
Sn2 reaction because backshots