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Dynamic Equilibrium
When the rate of forwards reactions equals the rate of backwards reactions. The concentration of each substance remains constant (not necessarily the same).
-only occurs in closed systems
How to calculate equilibrium constant
Kc = the concentration of products/ concentration of reactants
What happens to equilibrium when temperature increases?
-equilibrium shifts in endothermic direction to oppose increase in temperature
-Kc will decrease
What happens to equilibrium when temperature decreases?
-equilibrium shifts in exothermic direction to oppose decrease in temperature
-Kc will increase
Kc>>1
-equilibrium lies well over to the right
-many more products than reactants
Kc<1
-equilibrium lies slightly to the left
-more reactants than products
Kc=1
equilibrium is in the middle
What happens to Kc when there is a change in concentration?
Nothing. Kc is unaffected.
What happens to the equilibrium when pressure is increased?
The equilibrium shifts to the side with the fewest number of gas particles to reduce the pressure.
What happens to the equilibrium when pressure is decreased?
The equilibrium shifts to the side with the most gas particles to increase the pressure
Electrolysis
The breaking down of a substance using electricity.
What must the electrolyte be in electrolysis?
an ionic compound that is molten or in an aqueous solution
Anode
+ positive electrode
+ negative ions (anions) are attracted to the anode and give up electrons
Cathode
-negative electrode
-positive ions (cations) are attracted to the cathode and receive electrons
What are electrodes made of?
Inert and conductive materials e.g. platinum or graphite
What is the product at the cathode if the electrolyte is a group 1 or 2 metal or aluminium?
Hydrogen
2H2O(l) + 2e- -> 2OH-(aq) + H2 (g)
What is the product at the anode if the electrolyte contains a halide?
Halogen
2Cl- (aq) -> Cl2 (g) + 2e-
What is the product at the cathode in the electrolysis of metal that's not a group 1 or 2 metal or aluminium?
Metal
Cu2+(aq) + 2e- -> Cu(s)
What is the product at the anode if the electrolyte contains a sulfate or nitrate?
Oxygen
2H2O(l) -> O2(g) + 4H+(aq) + 4e-
What is the product at the cathode if the electrolyte is an acid?
Hydrogen
2H+(aq) + 2e- -> H2(g)
What is the product at the anode if the electrolyte contains a hydroxide?
4OH-(aq) -> O2(g) + 2H2O(l) + 4e-
Electrolysis in the purification of metals (eg. Copper) at the ANODE
-made from impure copper
-copper loses 2 electrons
- Cu(s) -> Cu2+(aq) + 2e-
-the anode wears away and becomes lighter
Electrolysis in the purification of metals (eg. Copper) at the CATHODE
-made from pure copper
-copper ions added to the solution from the anode gain electrons at the cathode to become copper again, this 'plates' the cathode
- Cu2+(aq) + 2e- -> Cu(s)
-the cathode will become heavier
Brine
-high concentration solution of salts
-found in sea water (made when mineral rocks dissolve in water)
-some halogens like chlorine can be extracted through the electrolysis of brine
Chlorine extracted from the electrolysis of brine, anode
Cl- ions from the salt make Cl2 gas
2Cl-(aq) -> Cl2(g) + 2e-
Chlorine extracted from the electrolysis of brine, cathode
H+ ions from the water make H2 gas
2H+(aq) + 2e- -> H2(g)
Chlorine extracted from the electrolysis of brine, solution
Sodium ions (Na+) are more reactive than hydrogen so remain in the solution. They react with hydroxide ions (OH- from the water) to make sodium hydroxide (NaOH)
Why must the sodium chloride solutions in the electrolysis of brine be concentrated?
If the solution is dilute the chloride ions don't release their electrons, instead OH- ions lose their electrons and water and oxygen are produced instead
4OH-(aq) + 2H2O(l) + O2 + 4e-
Extraction of bromine
-uses a more reactive halogen to extract it from its brine
-chlorine is more reactive than bromine
-bromine is produced which is condensed and purified into a liquid
2Br-(aq) + Cl2(g) -> Br2(g) + 2Cl-(aq)
Extraction of iodine
-uses a more reactive halogen to extract it from its brine
-chlorine is more reactive than iodine
-iodine is produced which is condensed and purified into a grey solid
2I-(aq) + Cl2(g) -> I2(aq) + 2Cl-(aq)
OIL RIG
Oxidation is Loss of Electrons, Reduction is a Gain of Electrons
Redox reaction
Involves reduction and oxidation
Reducing agents
Lose electrons and are oxidise themselves
Oxidising agents
Gain electrons and are reduced themselves
Oxidation number of every uncombined element
Always 0
e.g. Cl2, Fe, O2
Oxidation number of an ion
Always the charge on the ion
e.g. Cl- = -1
Oxidation number of groups 1, 2 and 3
Group 1 always = 1
Group 2 always = 2
Group 3 always = 3
e.g. in KCl, K = +1
Oxidation state of hydrogen
Always +1 except in hydroxides where it's -1
Oxidation number of oxygen
Always -2 (except it's -1 in peroxides and +2 in OF2)
What happens to the oxidation number in reduction?
It decreases
What happens to the oxidation number in oxidation?
It increases
Ammonium
NH4+
Hydrogen Carbonate
HCO3-
Manganate (VII)
MnO4 -
Nitrate (V)
NO3-
Sulfide
S²⁻
What must be balanced in redox reactions?
CHARGE as well as atoms
Iodine-sodium thiosulfate titration
-used to find concentration of oxidising agent
-add excess potassium iodide solution to KIO3
IO3-(aq) + 5I-(aq) + 6H+(aq) -> 3H20(l) + 3I2(aq)
-titrate sodium thiosulfate into KIO3 solution until it turns a pale yellow colour
-add starch, it turns dark blue, makes it easier to see colour change
I2(aq) + 2S2O3 2-(aq) -> S4O6 2-(aq) + 2I-(aq)
-use titration to find concentration of IO3-
How to get more accurate results in a titration
-rinse burette
-wash conical flask between repeats
-read from the bottom of the meniscus
-record results to 2d.p
-repeat until concordant results
-use freshly made solutions
Fluorine state at room temperature
yellow gas
Chlorine state at room temperature
pale green gas
Bromine state at room temperature
brown, volatile liquid
Iodine state at room temperature
silver solid
Uses of chlorine
-sterilise drinking water
-swimming pools
-bleach
-making paper
Use of fluorine
toothpaste
use of bromine
fire-retardant materials
use of iodine
disinfectant
What happens to electronegativity down group 7?
It DECREASES because the atoms get larger in size which means there is a larger distance between the positive nucleus and bonding electrons and there is more shielding
What happens to charge density down group 7?
it decreases
What happens to boiling point down group 7?
it INCREASES because instantaneous dipole-induced dipole bonds increase due to the increasing size and relative mass of the atoms
solubility of chlorine in hexane
organic layer- Pale green (more vivid)
polar layer - pale green
solubility of bromine in hexane
organic layer- red
polar layer - red/brown
solubility of iodine in hexane
organic- violet
polar - brown
How to test for chloride
Add dilute nitric acid, then silver nitrate
WHITE precipitate forms
Ag+(aq) + Cl-(aq) -> AgCl(s)
How to test for bromine
Add dilute nitric acid, then silver nitrate
CREAM precipitate forms
Ag+(aq) + Br-(aq) -> AgBr(s)
How to test for iodine
Add dilute nitric acid, then silver nitrate
YELLOW precipitate forms
Ag+(aq) + I-(aq) -> AgI(s)
How to test for fluorine
Add dilute nitric acid, then silver nitrate
no precipitate forms
silver chloride in ammonia
dissolves to give a colourless solution
silver bromide in ammonia
precipitate is almost unchanged using dilute ammonia solution, but dissolves in concentrated ammonia solution to give a colourless solution
silver iodide in ammonia
precipitate is insoluble in ammonia solution of any concentration
Preparing hydrogen chloride
NaCl(s) + H2SO4(aq) -> NaHSO4(aq) + HCl(g)
white fumes produced
Preparing hydrogen bromide
- NaBr(s) + H2O4(aq) -> NaHSO4(aq) + HBr(g)
- bromine ions produced are strong enough to reduce sulfuric acid to sulfur dioxide
- 2H+(aq) + 2Br-(aq) + H2SO4(aq) -> SO2(g) + Br2(l) + 2H2O(l)
-gas produced will be a mixture of hydrogen bromide, sulfur dioxide and bromine vapour (because exothermic)
-if phosphoric acid is used no reduction takes place and pure HBr is formed
Preparing hydrogen iodide
- NaI(s) + H2SO4(aq) -> NaHSO4(aq) + HI(g)
- iodine ions produced are even stronger reducing agents than in hydrogen bromide. They reduce sulfuric acid to hydrogen sulfate gas
- 8H+(aq) + 8I- + H2SO4(aq) -> H2S(g) + 4I2(s) + 4H2O(l)
- if phosphoric acid is used no reduction takes place and pure hydrogen iodide is formed
What happens to the thermal stability down group 7?
it DECREASES because bond strength between hydrogen and halogen decreases down the group
What happens to hydrogen fluoride when it's heated?
it's not broken down into its elements
What happens to hydrogen chloride when it's heated?
it's not broken down into its elements
What happens to hydrogen bromide when it's strongly heated?
it forms some brown bromine gas
2HBr(g) -> H2(g) + Br2(g)
What happens if a red hot needle is plunged into hydrogen iodide?
large amounts of purple gaseous iodine are formed
2HI(g) -> H2(g) + I2(g)
Acidity of hydrogen halides
HCl, HBr, and HI form stronger acids than HF, in solution, because they dissociate into their ions
e.g HCl(aq) -> H+(aq) + Cl-(aq)
or H20(l) + HCl(aq) -> H3O+(aq) + Cl-(aq)
What happens to strength of halide ions as reducing agents down the group?
-it INCREASES
-because as you go down the group the ionic radius increases
-so distance between nucleus and outer electrons gets larger, more shielding and weaker attractive forces
-the outer electron is lost more readily
Hydrogen fluoride and sulfuric acid
no reaction
Hydrogen chloride and sulfuric acid
no reaction
Hydrogen bromide and sulfuric acid
makes sulfur dioxide, SO2
Hydrogen iodide and sulfuric acid
makes hydrogen sulfide, H2S
Reactions of hydrogen halides and ammonia
make salts
e.g. NH3(g) + HCl(g) -> NH4Cl(s)
form white misty fumes
Chlorine risks
-toxic and corrosive
-oxidising agent so must be kept away from flames
Chlorine transportation
Transported and stored under pressure as a liquid in a small container
What is atom economy?
Mass of desired product/mass of all products x 100
How efficient a reaction is
100%= sustainable, less waste, less by-products so saves time and money