Phyics B michaelmas: EM

0.0(0)
Studied by 0 people
call kaiCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/91

encourage image

There's no tags or description

Looks like no tags are added yet.

Last updated 2:54 PM on 3/29/26
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai

No analytics yet

Send a link to your students to track their progress

92 Terms

1
New cards

Stokes's theorem

∫F·dr = ∫∫∇×F·dS

2
New cards

Divergence Theorem

∫F·dS = ∫∫∇·F·dV

3
New cards

torque and potential energy of:

a dipole in a uniform electric field

a magnetic dipole in a uniform magnetic field

G = p × E

U = -p·E

G = m × B

U = -m·B

4
New cards

force on:

a dipole in a non-uniform electric field

a magnetic dipole in a non-uniform magnetic field

net force and torque:

electric: F = ∇[p·E]

magnetic: F = ∇ [m · B]

5
New cards

Maxwell's Equations diffrential form

∇·D = ρ_free

∇ · B = 0

∇ × E = − ∂B / ∂t

∇ × H = J_free + ∂D / ∂t

6
New cards

Maxwell's Equations integral form

∮ D · dA = Q_enc

∮ B · dA = 0

∮ E · dl = − d/dt ∫ B · dA

∮ H · dl = I_enc + d/dt ∫ D · dA

7
New cards

potential expression using Green's function, and the four conditions necessary to find G

V(r) = (1/ε₀)∫ρ(r')G(r',r) d³r'

2 BC or 1 IC, G⁻ = G⁺ , dG⁻ /dr - dG⁺ /dr

<p>V(r) = (1/ε₀)∫ρ(r')G(r',r) d³r'</p><p>2 BC or 1 IC, G⁻ = G⁺ , dG⁻ /dr - dG⁺ /dr</p>
8
New cards

stored magnetic energy

and density

1/2∫B(r)·H(r)dV

density: 1/2 B(r)·H(r)

9
New cards

Lorentz force law (full)

F = q(E + v × B)

10
New cards

E in terms of V

E = -grad(V)

11
New cards

potential due to a dipole in spherical polar coordinates (far)

V(r, θ) = p cos θ / (4πε₀ · r² )

<p>V(r, θ) = p cos θ / (4πε₀ · r² )</p>
12
New cards

electric dipole moment?

p = qa

13
New cards

couple G acting on a dipole in a uniform electric field?

G = p × E

14
New cards

potential energy of a dipole in a uniform electric field

U = -p · E

15
New cards

What is the work done dW when increasing the angle θ of a dipole in a uniform field?

dW = |G(θ)|dθ, where G(θ) is the couple acting on the dipole.

16
New cards

force using potential energy

F(r) = -∇U(r)

17
New cards

electric flux

Φ = ∫∫dS · E(r).

18
New cards

continuity equation in electrostatics (conservation of charge)

∂ρ/∂t + ∇·J = 0

19
New cards

E of a uniform sheet of charge?

E = σ/(2ε₀)

20
New cards

E of a uniform line of charge?

E(r) = λ/(2πε₀r)

21
New cards

Poisson's equation

∇²V(r) = -ρ(r)/ε₀

22
New cards

Laplace's equation and when is it applicable

∇²V(r) = 0, applicable when only the surface is charged

23
New cards

types of boundary conditions

Dirichlet: the quantity of interest is specified over a boundary (eg V_surface is given)

Neumann: normal derivative of the quantity of interest is specified over a boundary

Cauchy: mixed

24
New cards

Green's function in free space

G(r, r′) = 1/(4π | r - r′ | )

point source, infinite boundaries

25
New cards

potential between parallel plates

V = Ez

26
New cards

Dipole moment defined through polarisability (α)

p = αE0

27
New cards

voltage and surface charge of a (neutral) conducting sphere in a uniform electric field

V(r) = E₀ cos θ (s³/r² - r)

σ = 3ε₀ E₀ cos θ

E₀ is the external field.

28
New cards

What is the relationship between the radius of a conducting sphere in a uniform field and the strength of the dipole it is equivalent to?

p = 4πε₀s³E₀

29
New cards

What is the capacitance of two parallel cylindrical conductors separated by distance 2D?

C/L = πϵ0 / ln(2D/a)

30
New cards

energy required to assemble a discrete system of charges?

U_N = (1/2) Σ (q_j V_j)

31
New cards

energy stored in a capacitor and inductor

U = (1/2) CV^2

U = (1/2) LI^2

32
New cards

electric potential energy from charge density?

U = (1/2) ∫ d^3r ρ(r)V(r).

33
New cards

electric energy density

UE(r) = 1/2 D(r) · E(r).

34
New cards

force between charged parallel plates?

F = Q²/(2ϵ0A).

35
New cards

Capacitance of Coaxial Cable

C/L = πε₀ / ln(r₁/r₂)

36
New cards

electric displacement

definition

formula in linear ( P proportional to E) dielectrics

in non linear dielectrics

free charge is the source of D, and both free and bound charges are the source of E

linear: D = εε₀E

non linear: D = ε₀E + P

37
New cards

magnetic field in terms of magnetic field strength:

linear and non linear materials

non linear: B = µ0(H + M)

linear: B = µµ₀H

38
New cards

Polarization/ magnetization of a dielectric: definition and formula using χ:

dipole moment(electric/ magnetic) per unit volume

linear: P = ε₀χE , M = χ_m H

where 1 + χ = ε , 1 + χ_m = µ

39
New cards

volume and surface polarization of a dielectric

describes the effective charge:

σ = P · n^

ρ​= −∇⋅P​

40
New cards

capacitance of a capacitor filled with dielectric

C = ε₀εA/d

41
New cards

what component (parallel or perpendicular) of H, B, D, E is conserved across boundaries

D and B : perpendicular

H and E : parallel

42
New cards

electric field INSIDE a dielectric sphere in a uniform field

Ein = 3/(ε+2)E₀

derived by conservation od D across boundary + assuming Ein in unniform + that the external field is the original uniform field plus a dipole field generated by the surface polarisation

43
New cards

Force on current element due to magnetic field.

dF = Idl × B

44
New cards

Biot-Savart law

dB = (µ₀I)/(4πr²) dl × r^

45
New cards

magnetic force between two parallel wires

F = (µ₀I₁I₂)/(2πd)

46
New cards

B on the axis of a current loop

B = (µ₀Ia²)/( 2(a²+x²)^(3/2) )

47
New cards

B in the middle of a long solenoid

µ₀ N/D I

48
New cards

Magnetic dipole moment

m = I∫dS

49
New cards

Magnetic scalar potential

H(r) = −∇φm(r)

50
New cards

Magnetic scalar potential of a current loop

dφ using magnetic dipole

φ using solid angle

dφ = |dm|cosθ /4πr²

φ = IΩ/4π

where the solid angle Ω = dS·r/r³ of a sphere

51
New cards

Ampere's law

∮dl · B = µ₀I = µ₀∫dS·J

52
New cards

magnetic field for a long wire

B(r) = µ₀I/ 2πr

53
New cards

B defined with Magnetic vector potential

B(r) = ∇ × A(r)

54
New cards

Poisson equation for magnetic vector potential A

−∇²A = µ₀J

55
New cards

Ohm's law

resistance with conductivity

J = σE

R = l / Sσ

56
New cards

dipole moment and Magnetisation relationship

m= ∫ M dV

57
New cards

current density:

Magnetisation current density

Magnetisation surface current density

Ordinary (free) electrical current density

J_m = ∇ × M (quivalent currents that reproduce the correct magnetic field, no charge carrying)

J_s​=M×n^ (Appears as a current flowing along the surface)

I=∫​J⋅dS​ (actual motion of free charges)

58
New cards

magnetic field strength in a sphere in a uniform magnetic field

H_in = 3H₀/(µ + 2)

59
New cards

B_ gap in a toroidal core: how to derive it and what is the final answer

use B_gap = B_in since the perpendicular component is conserved, ampere's law on the loop, and B_gap = µ₀H_gap.

B_gap = µ₀NI / l

60
New cards

Faraday's law of magnetic induction

ε = − d/dt ∫ dS · B(r) = − dΦ/dt

61
New cards

self inductance

L = Φ/I

62
New cards

Self-inductance of long solenoid

n²LSµ₀

63
New cards

Self-inductance of coaxial cylinders: formula or how to derive it

µ0L/ 2π ln(b/a)

derive by constructing a surface from the center to the edge and finding the flux through it

64
New cards

Self-inductance of a pair of wires: formula or how to derive it

µ0l/π ln (2D/a )

2D is the distance between the wires

derive by constructing a rectangular loop between the centers.

65
New cards

how are sparks across switches created

V_gap​=L dI/dt​

where V is a voltage across the switch. When the switch is opened dI/dt​ goes to very large (negative) numbers and the voltage across the switch grows. Derived by applaying faraday's law to a current loop.

66
New cards

Mutual inductance

M = M21 = Φ2/I1 = M12 = Φ1/I2

67
New cards

total energy stored using mutual and self inductance

U = 1/2 I₁² L₁ + 1/2 I₂² L₂ +1/2 I₁ I₂ M

68
New cards

coupling coefficient

M = k(L₁ L₂)½

69
New cards

ideal transformer coupling coefficient and voltage ratio

k=1

V2/V1 = N2/N1

70
New cards

Load impedance ratio across a transformer: full expression/ how to derive it

Z₁ = [ jωL₁Z₂(N₁/N₂)² ]/ [ jωL₁+ Z₂(N₁/N₂)² ]

same as jωL₁ in parallel with Z₂(N₁/N₂)²

typically: Z₁ ≈ Z₂(N₁/N₂)²

derived by M = (L₁ L₂)½ combined with the expressions for V1 and V2 from faraday's law and complex representation.

Z1 is the equivalent input impedance seen by the source​

71
New cards

Magnetic energy of discrete circuits

U = 1/2 sum Φ_i I_i

72
New cards

speed of light (in terms of free space permeability/permittivity)

c = 1/ √(ε₀µ₀)

<p>c = 1/ √(ε₀µ₀)</p>
73
New cards

refractive index

n=c/v = √(εµ)

(in non magnetic materials: √ε )

74
New cards

k in terms of wavelength and frequency

k = 2π/λ = ω/c

75
New cards

impedance of free space

in terms of permeability and permittivity

numerical value

in term of electric and magnetic field componenets

Z₀ = √(µ₀/ε₀) = Ex / Hy = 377Ω

76
New cards

relationship between Ex and By in free space wave propagating in the z direction

Ex = cBy

77
New cards

relationship between H₀ and E₀ in plane waves using k

H₀ = 1/Z₀ k^ × E₀

k^ is the unit vector pointing in the direction of propagation

78
New cards

Poynting vector:

formula

what does it signify

imaginary and real component sugnificance

N(r) = E(r) × H(r)

The magnitude of N gives the power flow per unit area, and the direction of N gives the direction in which the power is flowing. Can be complex if H and E are out of phase

real: instantaneous power flow per unit area at a given point

imaginary: time-averaged power flow per unit area at a point

79
New cards

Radiation pressure and how to derive it

R = N/c

Consider now the radiation incident normally on area A of a surface in time dt, In terms of the Poynting vector N. Find energy density. Dividing by the volume per photon the energy density is related to the radiation momentum density g by U = |g|c. radiation pressure is the rate of change of momentum per unit area.

80
New cards

Complex power

P = 1/2 I V∗

(half because of time average)

81
New cards

Snell's law

see image

<p>see image</p>
82
New cards

power Reflection coefficient in terms of

refractive index

impedance

R = ( (n₂ − n₁)/(n₂ + n₁) )²

Γ = ( (Z₂ − Z₁)/(Z₂ + Z₁) )²

83
New cards

relative permittivity in plasma using the plasma frequency and how is the plasma frequency derived

ε = 1 - ω²_p/ω²

where ω²_p = Ne²/(ε₀ m_e)

derived from:

m_e d²r/dt² = −e (E + v × B)

p = -er

N p = P = ε₀χE

84
New cards

Effective dielectric constant in conducting media

ε' = ε + iσ/ωε₀

where ε is negligable in metals where σ is large

85
New cards

skin depth in conducting media:

what is it

formula / how to derive it

relation to the wavevector

The distance into a metal at which an alternating E falls to E₀/e

δ = √(2/σωµ₀µ)

derive by: n = √(ε'µ) , where the real term in ε' can be neglected. k = ω/(c/n) = ( 1 + i )/ δ by definition.

k = ( 1 + i )/ δ

86
New cards

The effective resistance per unit length of a wire considering skin effect

R/L = 1/2πaδσ

effectively the current is assumed to flow uniformly in a thin shell of thickness δ

87
New cards

characteristic impedance of the transmission line

Z = √(L/C)

88
New cards

Voltage reflection and transmission coefficient on a transmission line

r = V2/V1 = (Zt − Z)/(Zt + Z)

t = Vt/V1 = 2Zt/(Zt + Z)

Zt is the load impedance, Z is the line impedance

89
New cards

effective Zin/Z of a transimission line terminated with an impedance Zt, and source impedance = transmittion line impedance = Z , or how to derive it

Zin / Z = (Zt cos ka + iZ sin ka)/ (Z cos ka + iZt sin ka)

derive using the formula for r, and the definition Zin = (Vi+Vr)/(Ii+Ir) at distance z=-a, sub the expression for r, expand to cos and sin

90
New cards

Quarter-wavelength line Zin formula

Zin = Z²/ Zt

91
New cards

Waveguide equation

where k²_g = ω²/c² - m²π²/a² - n²π²/b² = k²₀ -k²_c

where K_c is the cut-off frequency below which we'll get evanescent waves

92
New cards

phase velocity and group velocity in a Waveguide

v_p = ω / k_g

v_g = dω/dk

for vacuum: v_g* v_p = c^2

Explore top notes

note
Science Test
Updated 1280d ago
0.0(0)
note
Different Types of Rocks
Updated 1260d ago
0.0(0)
note
AP Human Geography
Updated 112d ago
0.0(0)
note
3.1 Intro to Culture
Updated 128d ago
0.0(0)
note
Chapter Eight: Group Processes
Updated 1140d ago
0.0(0)
note
Period 1, c.1200 to c.1450
Updated 1161d ago
0.0(0)
note
Science Test
Updated 1280d ago
0.0(0)
note
Different Types of Rocks
Updated 1260d ago
0.0(0)
note
AP Human Geography
Updated 112d ago
0.0(0)
note
3.1 Intro to Culture
Updated 128d ago
0.0(0)
note
Chapter Eight: Group Processes
Updated 1140d ago
0.0(0)
note
Period 1, c.1200 to c.1450
Updated 1161d ago
0.0(0)

Explore top flashcards

flashcards
Spanish Set 8
53
Updated 848d ago
0.0(0)
flashcards
Areas of focus - Business
28
Updated 1161d ago
0.0(0)
flashcards
Chemistry - Ions and molecules
57
Updated 409d ago
0.0(0)
flashcards
Earthquakes and Volcanoes
28
Updated 497d ago
0.0(0)
flashcards
E2: ortho practice questions
101
Updated 411d ago
0.0(0)
flashcards
Chapter 1 - Financial Literacy
35
Updated 930d ago
0.0(0)
flashcards
Spanish Set 8
53
Updated 848d ago
0.0(0)
flashcards
Areas of focus - Business
28
Updated 1161d ago
0.0(0)
flashcards
Chemistry - Ions and molecules
57
Updated 409d ago
0.0(0)
flashcards
Earthquakes and Volcanoes
28
Updated 497d ago
0.0(0)
flashcards
E2: ortho practice questions
101
Updated 411d ago
0.0(0)
flashcards
Chapter 1 - Financial Literacy
35
Updated 930d ago
0.0(0)