Calculus BC inverse trig identities

π/2 - x, x ∈ [0, π]

arctan(cot(x))

π/2 - x, x ∈ [0, π]

arcsin(cos(x))

π/2 - x, x ∈ [0, π/2]

arcsec(csc(x))

√(1 - x²)

sin(arccos(x))

√(1 - x²)

cos(arcsin(x))

x / √(1 - x²)

sin(arctan(x))

1 / √(1 - x²)

cos(arctan(x))

x / √(1 - x²)

tan(arcsin(x))

√(1 - x²) / x

tan(arccos(x))

π/2

arcsin(x) + arccos(x)

π/2

arctan(x) + arccot(x)

π/2

arcsec(x) + arccsc(x)