Metal Mediated Synthesis

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72 Terms

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What is a Cross-Coupling reaction?

A nucleophilic substitution at an sp2 hybridised carbon by using a transition metal mediated catalyst.

  • Catalytic Ni, Fe or Co can also be used as well as Pd.

<p>A nucleophilic substitution at an sp2 hybridised carbon by using a transition metal mediated catalyst.</p><ul><li><p>Catalytic Ni, Fe or Co can also be used as well as Pd.</p></li></ul><p></p>
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How does a bromopyridine react with nBuLi?

Can react at -78oC to remove R-X.

Can react at -40oC to form a disubstituted pyridine.

<p>Can react at -78<sup>o</sup>C to remove R-X.</p><p>Can react at -40<sup>o</sup>C to form a disubstituted pyridine.</p>
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What is the halogen dance reaction?

When Li and Br are both bonded to a ring, they can swap positions.

<p>When Li and Br are both bonded to a ring, they can swap positions.</p>
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How does an alkyne react with nBuLi?

Releases n-butane gas.

<p>Releases n-butane gas.</p>
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How are Grignard reagents formed?

Reaction of R-X with Mg.

<p>Reaction of R-X with Mg.</p>
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How do you add RX to an active catalyst?

Via oxidative addition.

  • The Pd(0) is oxidised to Pd(II)

  • The valence electron count is increased from 14 to 16, and the coordination number increases from 2 to 4.

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Why are organo-chlorides not favoured reagents in cross-coupling?

The C-X bond strength decreases as group 17 descends, therefore Cl and F reagents have stronger C-X bonds.

  • The strength of the bond determines whether or not the oxidative addition step is the RDS, a stronger bond means a slower reaction.

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How does transmetallation occur?

  • The active catalyst loses a ligand, forming a vacant site.

  • The transmetallating agent (R’-M) reacts with the Pd centre, forming a Pd-R’ bond and losing a M-I byproduct.

  • The loss of MI leaves another vacant site, the ligand then coordinates to give the product.

There is no change in OS between intermediates.

The MI is a stable metal salt.

<ul><li><p>The active catalyst loses a ligand, forming a vacant site.</p></li><li><p>The transmetallating agent (R’-M) reacts with the Pd centre, forming a Pd-R’ bond and losing a M-I byproduct.</p></li><li><p>The loss of MI leaves another vacant site, the ligand then coordinates to give the product.</p></li></ul><p>There is no change in OS between intermediates.</p><p>The MI is a stable metal salt.</p><p></p>
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How is R-R lost from the active catalyst?

Via reductive elimination, the Pd(II) is reduced to Pd(0). The R-X is lost.

  • The valence electron count is reduced from 16 to 14.

  • The coordination number lowering from 4 to 2.

<p>Via reductive elimination, the Pd(II) is reduced to Pd(0). The R-X is lost.</p><ul><li><p>The valence electron count is reduced from 16 to 14.</p></li><li><p>The coordination number lowering from 4 to 2.</p></li></ul><p></p>
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What affect does trace air have on the [L2Pd] catalyst?

The O2 adds onto the Pd, oxidising it to Pd(II) and forming a 16 electron species.

  • This can further break down, reforming Pd(0).

<p>The O<sub>2</sub>&nbsp;adds onto the Pd, oxidising it to Pd(II) and forming a 16 electron species.</p><ul><li><p>This can further break down, reforming Pd(0).</p></li></ul><p></p>
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How does a precatalyst become a catalyst?

The Pd must be in the 0 O.S. and have a vacant coordination site for ligands to bind.

  • Must reduce a stable starting material to form the catalyst.

  • The catalyst may still require displacement of a neutral ligand to form a vacant site.

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What is a precatalyst?

The precatalyst is not in an active form itself, but requires an activation step to form the active catalyst.

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What is the ‘active catalyst’ in most C-C cross couplings?

Thought to be [L2Pd], where L is typically a phosphine ligand and Pd is in the 0 O.S..

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How do you reduce a precatalyst using a base?

The base (e.g. Et3N) is added to the stable starting material.

  • A ligand is replaced by the base.

  • A H on the base is added onto the Pd, the base is then lost (Beta-hydride elimination).

  • The base attacks a Cl ligand and the H ligand, removing it and forming HCl.

  • The catalyst Pd(0) is formed.

<p>The base (e.g. Et<sub>3</sub>N) is added to the stable starting material.</p><ul><li><p>A ligand is replaced by the base.</p></li><li><p>A H on the base is added onto the Pd, the base is then lost (Beta-hydride elimination).</p></li><li><p>The base attacks a Cl ligand and the H ligand, removing it and forming HCl.</p></li><li><p>The catalyst Pd(0) is formed.</p></li></ul><p></p>
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How do you reduce a precatalyst using organometallics?

The organometallic (e.g. RMgX) is added to the stable SM. 2 molecules of RMgX are required per SM.

  • The R group substitutes with the Cl ligands on the SM.

  • The two R groups are then eliminated, removing a R-R molecule.

  • The catalyst Pd(0) is formed.

<p>The organometallic (e.g. RMgX) is added to the stable SM. 2 molecules of RMgX are required per SM.</p><ul><li><p>The R group substitutes with the Cl ligands on the SM.</p></li><li><p>The two R groups are then eliminated, removing a R-R molecule.</p></li><li><p>The catalyst Pd(0) is formed.</p></li></ul><p></p>
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What determines which part of the catalyst activation is slowest?

Kinetics:

  • Bond strengths.

  • Nucleophilicity of organometallic reagents.

  • Lattice energy of metal salts.

  • Rate of cis-trans isomerism.

  • Nature of the ligands.

  • Unwanted side reactions.

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When is XPhos used as a ligand and why?

XPhos (PCy3) must be used for catalysts when R-X contains a Cl.

  • The C-Cl bond is too strong, XPhos activates the C-Cl bond allowing the catalyst to react with it.

  • There is a Cipso-Pd interaction that activates the C-Cl bond.

<p>XPhos (PCy<sub>3</sub>) must be used for catalysts when R-X contains a Cl.</p><ul><li><p>The C-Cl bond is too strong, XPhos activates the C-Cl bond allowing the catalyst to react with it.</p></li><li><p>There is a C<sub>ipso</sub>-Pd interaction that activates the C-Cl bond.</p></li></ul><p></p>
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<p>What occurs in a general catalytic cycle for Pd catalysed C-C couplings?</p>

What occurs in a general catalytic cycle for Pd catalysed C-C couplings?

  1. The precatalyst is reduced to form the active catalyst.

  2. R-X is added, oxidative addition occurs to form a 4 coordinate Pd complex.

  3. Side reactions may occur when oxidative addition is fast, forming R-H or R-R.

  4. Transmetallation occurs, R’-M is added and reacts with the Pd complex, forming a metal salt (MX). This forms a Pd complex with the R and R’ ligands.

  5. Reductive elimination occurs, removing the R-R’ product.

The active catalyst can undergo ligand dissociation to form a Pd(PPh3) complex, which can also act as the active catalyst.

<ol><li><p>The precatalyst is reduced to form the active catalyst.</p></li><li><p>R-X is added, oxidative addition occurs to form a 4 coordinate Pd complex.</p></li><li><p>Side reactions may occur when oxidative addition is fast, forming R-H or R-R.</p></li><li><p>Transmetallation occurs, R’-M is added and reacts with the Pd complex, forming a metal salt (MX). This forms a Pd complex with the R and R’ ligands.</p></li><li><p>Reductive elimination occurs, removing&nbsp;the R-R’ product.</p></li></ol><p>The active catalyst can undergo ligand dissociation to form a Pd(PPh3) complex, which can also act as the active catalyst.</p><p></p>
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During the Pd catalysed C-C coupling, when is oxidative addition fast?

When X= Br, I, OTf or OTs: K1 is fast.

When X= Cl, F: K2 is slow, therefore a special phosphine (that is electron rich or sterically hindered) must be used.

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What effect does Pd agglomeration have on the catalytic cycle?

The agglomerate Pd reacts with the R-X similarly to the normal Pd catalyst, forming the R’-R product.

<p>The agglomerate Pd reacts with the R-X similarly to the normal Pd catalyst, forming the R’-R product.</p>
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What are Pd black particles?

Inactive agglomerated Pd particles that lead to catalyst deactivation.

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How do you remove Pd black?

Can react with:

  • R-SH: leading to breakdown of 8000ppm Pd particles to 100ppm particles.

  • Zn, EDTA: leads to breakdown of 100 ppm Pd particles to 5 ppm.

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What is Kumada cross-coupling?

An Ar-X reacts with a Grignard reagent in the presence of a catalyst (Pd, Ni, Fe) to form a new C-C bond.

<p>An Ar-X reacts with a Grignard reagent in the presence of a catalyst (Pd, Ni, Fe) to form a new C-C bond.</p>
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What is a problem with Kumada coupling?

The Grignard reagent required has low functional group compatability, it is likely to act as a nucleophile and attack sensitive FGs, such as ketones and esters.

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How is Fe used as a catalyst for Kumada CC?

FeCl3 is used as the precatalyst.

  • The R-MgBr reagent reacts with the precatalyst and forms Fe nanoparticles. These act as the active catalyst.

<p>FeCl<sub>3</sub> is used as the precatalyst. </p><ul><li><p>The R-MgBr reagent reacts with the precatalyst and forms Fe nanoparticles. These act as the active catalyst.</p></li></ul><p></p>
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How can Pd/Fe nanoparticles be useful as catalysts?

They are magnetic. 

  • Helps with recovery of catalyst (use a magnet to remove).

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What is the original Negishi CC?

Negishi proposed that less electropositive metals (Al or Zr) can be used as transmetallating reagents rather than Mg or Li.

  • The Schwartz reagent (Cp2ZrHCl) is added to an alkyne in the presence of dry THF, forming an alkene. 

  •  R-X is then added, Pd or Ni catalyst is used.

<p>Negishi proposed that less electropositive metals (Al or Zr) can be used as transmetallating reagents rather than Mg or Li.</p><ul><li><p>The Schwartz reagent (Cp<sub>2</sub>ZrHCl) is added to an alkyne in the presence of dry THF, forming an alkene.&nbsp;</p></li><li><p>&nbsp;R-X is then added, Pd or Ni catalyst is used.</p></li></ul><p></p>
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What effect does the catalyst choice (Pd or Ni) have on the products of Negishi CC?

If the R-X added contains a double bond:

  • Using a Ni catalyst yields 95% trans-trans and 5% trans-cis.

  • Using Pd yields over 99% trans-trans.

<p>If the R-X added contains a double bond:</p><ul><li><p>Using a Ni catalyst yields 95% trans-trans and 5% trans-cis.</p></li><li><p>Using Pd yields over 99% trans-trans.</p></li></ul><p></p>
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How does the addition of ZnCl2 affect Negishi CC?

The addition of ZnCl2 increases the reactivity of the transmetallating agent in situ.

  • The ZnCl2 reacts with the organometallic RZrCp2Cl to produce an alkenylzinc species (RZnCl).

  • This then reacts with the R=X.

<p>The addition of ZnCl<sub>2</sub>&nbsp;increases the reactivity of the transmetallating agent in situ.</p><ul><li><p>The ZnCl<sub>2</sub>&nbsp;reacts with the organometallic RZrCp<sub>2</sub>Cl to produce an alkenylzinc species (RZnCl).</p></li><li><p>This then reacts with the R=X.</p></li></ul><p></p>
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How do you recycle the Schwartz reagent in Negishi CC?

Using LiAlH4 after modifying with ZnCl2.

<p>Using LiAlH4 after modifying with ZnCl2.</p>
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What is Stille CC?

An R-X compound is reacted with a R’-SnBu3 compound in the presence of a Pd(0) catalyst, forming the R-R’ and X-SnBu3 products.

<p>An R-X compound is reacted with a R’-SnBu<sub>3</sub> compound in the presence of a Pd(0) catalyst, forming the R-R’ and X-SnBu<sub>3</sub> products.</p>
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What are the advantages of Stille coupling?

  • Has near complete FG tolerance.

  • The organostannanes and organohalides are air and moisture stable.

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What is a problem with Stille CC?

The R-SnBu3 reagent is toxic.

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How does the ‘fluoride effect’ increase the speed of Stille CC?

The fluoride ions activate the organotin reagent, forming a tin-fluoride species (which is more reactive).

  • CuI can also be used, forming a R-Cu intermediate which allows more efficient exchange of R onto the Pd catalyst.

<p>The fluoride ions activate the organotin reagent, forming a tin-fluoride species (which is more reactive).</p><ul><li><p>CuI can also be used, forming a R-Cu intermediate which allows more efficient exchange of R onto the Pd catalyst.</p></li></ul><p></p>
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What is Suzuki-Miyaura CC?

An Ar-X compound and an ArB(OH)2 compound are reacted in the presence of a Pd catalyst, a base, 2M Na2CO3, and in a 1:1 THF/H2O mixture.

<p>An Ar-X compound and an ArB(OH)<sub>2</sub> compound are reacted in the presence of a Pd catalyst, a base, 2M Na<sub>2</sub>CO<sub>3</sub>, and in a 1:1 THF/H2O mixture.</p>
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How does Suzuki-Miyaura CC occur?

The Ar-X reagent bonds to the Pd catalyst via oxidative addition.

The Pd complex undergoes ligand exchange with a OH- (from the base), forming the Pd-OH and losing a halide.

This goes on to react with the boronic acid, forming the Pd(Ar)2 complex.

The product is lost via reductive elimination.

<p>The Ar-X reagent bonds to the Pd catalyst via oxidative addition.</p><p>The Pd complex undergoes ligand exchange with a OH- (from the base), forming the Pd-OH and losing a halide.</p><p>This goes on to react with the boronic acid, forming the Pd(Ar)2 complex.</p><p>The product is lost via reductive elimination.</p><p></p>
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What mechanistic effect does the formation of a Pd-OH species have in Suzuki-Miyaura CC?

The formation of the Pd-OH allows efficient reaction of the catalyst with Ph-B(OH)2, forming a Pd-Ph bond and a B(OH)3 compound.

<p>The formation of the Pd-OH allows efficient reaction of the catalyst with Ph-B(OH)<sub>2</sub>, forming a Pd-Ph bond and a B(OH)<sub>3</sub>&nbsp;compound.</p>
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What effect does [OH] have on Suzuki-Miyaura CC?

Increasing [OH] increases rate until the point at which OH inhibits the reductive elimination step.

  • If [OH-] becomes too high, the reductive elimination step is inhibited as stable anionic Pd-OH- complexes are formed, which have a high electron denisty.

  • The reduction of Pd becomes harder, therefore reductive elimination is inhibited.

<p>Increasing [OH] increases rate until the point at which OH inhibits the reductive elimination step.</p><ul><li><p>If [OH-] becomes too high, the reductive elimination step is inhibited as stable anionic Pd-OH- complexes are formed, which have a high electron denisty.</p></li><li><p>The reduction of Pd becomes harder, therefore reductive elimination is inhibited.</p></li></ul><p></p>
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<p>What is the chemoselectivity when bromine and iodine are both on the phenyl ring?</p>

What is the chemoselectivity when bromine and iodine are both on the phenyl ring?

The C-I bond is selectively broken as this is the weaker C-X bond compared to C-Br.

<p>The C-I bond is selectively broken as this is the weaker C-X bond compared to C-Br.</p>
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<p>What is the chemoselectivity when there are 2 halogens on a N-substituted ring?</p>

What is the chemoselectivity when there are 2 halogens on a N-substituted ring?

The C-Br located next to the N atom is weaker than the other C-Br, therefore this bond is selectively attacked, forming the major product.

  • In some situations, if Pd nanoparticles or Pd3 clusters are used the minor product can be formed.

<p>The C-Br located next to the N atom is weaker than the other C-Br, therefore this bond is selectively attacked, forming the major product.</p><ul><li><p>In some situations, if Pd nanoparticles or Pd<sub>3</sub>&nbsp;clusters are used the minor product can be formed.</p></li></ul><p></p>
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What is Sonogashira cross-coupling?

The reaction of an R-M with a R’-X in the presence of a Pd catalyst and amine base.

  • CuI can be added to aid Pd activation and affects the reactivity of the acetylene hydrogen.

  • The R’-H is usually an alkyne.

  • The organometallic reagent is produced in situ.

<p>The reaction of an R-M with a R’-X in the presence of a Pd catalyst and amine base.</p><ul><li><p>CuI can be added to aid Pd activation and affects the reactivity of the acetylene hydrogen.</p></li><li><p>The R’-H is usually an alkyne.</p></li><li><p>The organometallic reagent is produced in situ.</p></li></ul><p></p>
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How does CuI aid Pd activation is Sonogashira CC?

The CuI reacts with the alkyne double bond, forming a C-Cu bond and removing HI.

<p>The CuI reacts with the alkyne double bond, forming a C-Cu bond and removing HI.</p>
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What is the Heck reaction?

An R-X is reacted with an alkene/alkyne in the presence of a Pd catalyst and a base, forming a R=R.

  • B-hydride elimination occurs.

  • R-X must not contain and alkyl-aryl group as this would lead to unwanted byproducts

<p>An R-X is reacted with an alkene/alkyne in the presence of a Pd catalyst and a base, forming a R=R.</p><ul><li><p>B-hydride elimination occurs.</p></li><li><p>R-X must not contain and alkyl-aryl group as this would lead to unwanted byproducts</p></li></ul><p></p>
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How do you make CCs more atom efficient?

Reactions where neither component is pre-activated are most atom efficient.

<p>Reactions where neither component is pre-activated are most atom efficient.</p>
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What is ‘direct arylation’?

An Ar-H reacts with an Ar-X in one step to form an Ar-Ar product.

  • This involves only one substrate being pre-activated.

  • The Ar-H is activated using a Pd catalyst, CuI and DMF, Cs2CO3 at 140oC.

<p>An Ar-H reacts with an Ar-X in one step to form an Ar-Ar product.</p><ul><li><p>This involves only one substrate being pre-activated.</p></li><li><p>The Ar-H is activated using a Pd catalyst, CuI and DMF, Cs<sub>2</sub>CO<sub>3</sub>&nbsp;at 140<sup>o</sup>C.</p></li></ul><p></p>
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What is Oxidative Aromatic Cross-Coupling and how do you make it selective?

The reaction of Ar-H and Ar’-H in which neither component is pre-activated. They are reacted in the presence of a Pd(II) catalyst and an oxidant.

  • If the oxidant is AgOAc, the Ar adds onto the C2 position. If the oxidant is Cu(OAc)2 the Ar adds onto the C3.

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How does Oxidative Aromatic CC occur?

  • The Pd(OAc)2 catalyst reacts with the Ar-H to form the reactive species PhPdOAc and removes a molecule of AcOH.

  • The reactive species reacts with the Ar-H bond via concerted metalation deprotonation.

  • Reductive elimination occurs to form the product.

<ul><li><p>The Pd(OAc)<sub>2</sub> catalyst reacts with the Ar-H to form the reactive species PhPdOAc and removes a molecule of AcOH.</p></li><li><p>The reactive species reacts with the Ar-H bond via concerted metalation deprotonation.</p></li><li><p>Reductive elimination occurs to form the product.</p></li></ul><p></p>
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What is a Buchwald-Hartwig amination?

Ar-X reacts with R-NH2 in the presence of a Pd catalyst, PtBu3 and a base (NaOtBu).

  • The [R-NH]- Na+ acts like a R-M species.

<p>Ar-X reacts with R-NH<sub>2</sub>&nbsp;in the presence of a Pd catalyst, P<sup>t</sup>Bu<sub>3</sub> and a base (NaO<sup>t</sup>Bu).</p><ul><li><p>The [R-NH]<sup>-</sup>&nbsp;Na<sup>+</sup> acts like a R-M species.</p></li></ul><p></p>
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Is there a need for a metal catalyst in SNAr reactions?

Not necessary as in many cases NGP or partial charges allow the reaction to occur without catalysts.

<p>Not necessary as in many cases NGP or partial charges allow the reaction to occur without catalysts.</p>
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What is the mechanism for alkene metathesis?

  • A Ru complex loses a ligand, forming a 14 electron adduct.

  • An alkene is added, which coordinates to the Ru centre.

  • Heat is added, allowing a [2+2] cycloaddition to form a metallocycle intermediate.

  • An alkene is then lost, forming the 2 new alkenes.

<ul><li><p>A Ru complex loses a ligand, forming a 14 electron adduct.</p></li><li><p>An alkene is added, which coordinates to the Ru centre.</p></li><li><p>Heat is added, allowing a [2+2] cycloaddition to form a metallocycle intermediate.</p></li><li><p>An alkene is then lost, forming the 2 new alkenes.</p></li></ul><p></p>
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How does Ring-closing metathesis occur using Schrock catalyst?

Two ends of a ketone diene molecule react with one another in the presence of a Schrock catalyst. Toluene is used as a solvent at 23-25oC and the reaction takes 3 hours.

  • Ethene gas is released.

  • When R=H, there is a 0% yield.

  • When R=CH3, there is a 95% yield.

<p>Two ends of a ketone diene molecule react with one another in the presence of a Schrock catalyst. Toluene is used as a solvent at 23-25<sup>o</sup>C and the reaction takes 3 hours.</p><ul><li><p>Ethene gas is released.</p></li><li><p>When R=H, there is a 0% yield.</p></li><li><p>When R=CH<sub>3</sub>, there is a 95% yield.</p></li></ul><p></p>
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What is the Thorpe-Ingold effect?

Steric constraints increase cyclisation.

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How does Ring-closing metathesis occur using Grubbs 2nd Gen catalyst?

A 1,6-diene reacts with itself in the presence of 1 mol% of Grubbs II in the presence of CH2Cl2 at 25-38oC.

  • Ethene gas forms and bubbles out.

<p>A 1,6-diene reacts with itself in the presence of 1 mol% of Grubbs II in the presence of CH<sub>2</sub>Cl<sub>2</sub>&nbsp;at 25-38<sup>o</sup>C.</p><ul><li><p>Ethene gas forms and bubbles out.</p></li></ul><p></p>
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What is macrocyclisation?

A long chain diene reacts with itself via RCM to form a large ring molecule,

  • Forms a 1:2 mixture of E:Z

<p>A long chain diene reacts with itself via RCM to form a large ring molecule,</p><ul><li><p>Forms a 1:2 mixture of E:Z</p></li></ul><p></p>
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What factors can affect the macrocyclisation reaction?

  • Reactant concentration- typically 0.001-0.005 moldm-3.

  • Remote substituents (substituents away from reaction site)- OR substituents can increase reaction rates and may change stereoselectivity, whereas OH can inhibit and poison the catalyst.

  • Interaction that increase rigidity of the substrate- reduces entropic cost of cyclisation.

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What is cross metathesis?

A reaction in which two alkene react with one another to form a new alkene.

  • Grubbs I or II can be used, however this changes the ratio of E:Z formed.

  • The reaction can be selective or non-selective, the use of the G II  catalyst allows equilibration to the thermodynamically stable E isomer.

<p>A reaction in which two alkene react with one another to form a new alkene.</p><ul><li><p>Grubbs I or II can be used, however this changes the ratio of E:Z formed.</p></li><li><p>The reaction can be selective or non-selective, the use of the G II&nbsp; catalyst allows equilibration to the thermodynamically stable E isomer.</p></li></ul><p></p>
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How do you prevent homodimerisation in cross-metathesis and why?

Having steric bulk in one alkene can help favour the cross-metathesis over the homodimerisation.

  • Using a protecting group can help increase bulk and prevent homodimerisation.

  • Homodimerisation causes a lower yield.

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What is a Pauson-Khand reaction?

A formal [2+2] cycloaddition of an alkyne, alkene and CO. This can occur catalytically (intramolecularly) or stoichiometrically (intermolecularly).

<p>A formal [2+2] cycloaddition of an alkyne, alkene and CO. This can occur catalytically (intramolecularly) or stoichiometrically (intermolecularly).</p>
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What is Intramolecular PK?

Requires Co2(CO)8, THF and rt-60oC temp.

The enyne reacts with itself to form the product.

<p>Requires Co<sub>2</sub>(CO)<sub>8</sub>, THF and rt-60<sup>o</sup>C temp.</p><p>The enyne reacts with itself to form the product.</p>
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What is intermolecular PK?

Occurs via the reaction of an alkene and an alkyne from separate molecules in the presence of CO and a metal (usually Co2(CO)8).

  • This is a stereospecific reaction.

  • Requires THF and rt-60oC

<p>Occurs via the reaction of an alkene and an alkyne from separate molecules in the presence of CO and a metal (usually Co<sub>2</sub>(CO)<sub>8</sub>).</p><ul><li><p>This is a stereospecific reaction.</p></li><li><p>Requires THF and rt-60<sup>o</sup>C</p></li></ul><p></p>
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What are the limitations of intermolecular PK?

  • Co2(CO)8 is toxic and difficult to handle- complexes can be affected by air and water as Co-H species can form.

  • Intermolecular reactions are more difficult and side reactions can occur,

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What is the Co2(CO)8 intermediate formed in PK?

Binds to the alkyne.

Forms an sp3 hybridised carbon.

<p>Binds to the alkyne.</p><p>Forms an sp<sup>3</sup> hybridised carbon.</p>
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How do substituents effect intermolecular PK reactions?

  • Monosubstituted terminal acetylenes will give products where the substituent is in the alpha-position of the enone. Regiochemistry is dominated by steric effects.

  • For disubstituted acetylenes, EDG tend to prefer the alpha-position, whereas EWG tend to prefer the beta position. Regiochemistry is dominated by electronic effects.

<ul><li><p>Monosubstituted terminal acetylenes will give products where the substituent is in the alpha-position of the enone. Regiochemistry is dominated by steric effects.</p></li><li><p>For disubstituted acetylenes, EDG tend to prefer the alpha-position, whereas EWG tend to prefer the beta position. Regiochemistry is dominated by electronic effects.</p></li></ul><p></p>
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How are DMSO and TMANO used in PK reactions?

They can displace the CO ligand in the formation of the inital alkynyl-cobalt(0) complex.

Can also assist in alkene insertion (CO loss may be neccessary).

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What is a con of classical cross couplings?

They require substrate activation.

Aggregation of Pd can be a problem, therefore choice of ligand is important.

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What is a con of C-H bond activation reactions?

They are often better than classical cross couplings, but often require additives (such as special ligands, base, etc.)

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What is a con of cross-metathesis?

Selectivity can be an issue (such as homodimerisation vs. cross-dimerisation).

High catalyst loadings are often required, and the choice of catalyst is important.

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What conditions are used for metathesis?

Mild conditions (ambient temp).

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Which CC reactions require inert conditions, dry solvents and rt?

Kumada

Negishi

Stille

Sonogashira

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Which CC reactions require a base?

Suzuki

Direct Arylation

Sonogashira (dry NEt3)

  • Heat reactions to 60oC in THF or CH3CN.

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What FGs do Grignard/organolithium reagents react with?

They will react with aldehydes, ketones, esters and deprotonate acidic groups.

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How does organolithium reagents react with R-Br, CuI and ZnCl2?

Reactions often require inert conditions and require dry solvents.

<p>Reactions often require inert conditions and require dry solvents.</p>