synthesis reactions - midterm 2

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Last updated 9:56 PM on 2/26/25
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27 Terms

1
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alkoxide + methyl/primary alkyl halides

ethers

  • sn2 rxn

    • the william ether synthesis rxn

2
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alcohol + NaH

epoxide

  • hydroxide cannot be used because it won’t make enough product which would give a mix of both hydroxide ions and alkoxide

3
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dehydration

the elimination rxn of alcohols

  • solvent: H2SO4 or TsOH

  • alkene will be made

  • good for secondary + tertiary alcohols = E1

  • carbocation rearrangements can occur

  • highly substituted alkene is favored

4
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alcohol → alkyl halides using H-X

  • best for methyl, primary, and tertiary substrates

  • tertiary = Sn1

  • methyl + primary = Sn2

  • stereochemistry: 100% inversion

5
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alcohol → alkyl halides other methods

  • solvents: PBr3 + pyrimidine

  • solvents: SOCl2 + pyrimidine

  • next round of solvents: NaX

  • first solvent (PBr3 or SOCl2) will attach to oxygen on alcohol → pyrimidine will deprotonate and leaving group from first will do backside attack + take off oxygen

  • pyrimidine prevents buildup of HBr or HCl so that racemization and carbocation rearrangements do not occur

  • only for methyl, primary, or secondary alcohols bc mechanism is only Sn2 + 100% inversion occurs

6
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alcohols → sulfonate esters

  • addition → elimination

  • alcohol is added to sulfonyl chlorides (ex: TsCl) → pyrimidine deprotonates oxygen to create tosylate

  • retention of configuration

  • nucleophiles can then attack tosylates + do an Sn2 reaction bc sulfate anion is a good LG → inversion will occur bc

7
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alcohols → sulfonate esters → alkyl halides

  • solvents: TsCl, pyrimidine → NaX

  • first step creates tosylate

  • second step creates alkyl halide as Sn2 occurs → inversion

8
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substitution of ethers

  • solvents: hot HI or HBr

  • Sn1 = LG gives a secondary or tertiary carbocation

  • Sn2 = carbocation won’t form if LG makes it unstable

9
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acid-catalyzed ring opening of epoxides

  • solvents: acid catalyst + H2O/alcohols

  • nucleophile will attack most substituted side and give one regiosiomer

  • backside attack will occur once hydroxyl group is made

10
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nucleophilic ring opening of epoxides

  • solvents: alkoxides/strong bases

  • strong nucleophile will attack least substituted side

11
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alternative to dehydration of primary alcohols

  • use: PBr3, pyrimidine; SOCl2, pyrimidine; TosCl, pyrimidine; HBr → make alkyl halide and make hydroxyl group into a good LG

  • then use a very hindered base to promote E2

12
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addition of hydrogen halides to alkenes

  • use HCl, HBr, or HI

  • hydrogen attaches to one carbon (RDS), and halide attaches to the other and breaks pi bond

  • major product: hydrogen is attached to least substituted and halide attached to most substituted and has most stable carbocation → that way a primary carbocation does not form

    • markovnikov’s product is major

  • need to watch for carbocation rearrangements

  • stereochemistry: if reactant was achiral and product becomes chiral, racemic mixture will occur

    • syn and anti addition occur

13
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hydration = water + alkene

  • solvents: strong acid + water

  • alcohol will form

  • reverse reaction of dehydration

  • regioselectivity: markovikov’s product is major → one with the most stable carbocation

  • alkenes that make tertiary carbocation are favored

  • hydrogen goes to the least substituted side and hydroxyl goes to most substituted side

14
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vicinal dihalides - halogenation

  • alkene + Br2/Cl2

  • only anti addition

  • racemix mixture

  • halides will be on opposite sides

15
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bromohydrin

  • bromonium ion (from halogenation) + water

  • all reactants in the rxn: Br2 + H2O

  • one bromine on one side and a hydroxyl group on the other

  • water attacks most substituted side

16
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hydroboration of alkenes

  • solvents: BH3, THF

    • then: H2O2, -OH (either NaOH or H2O)

  • regioselectivity: BH3 is bulky, so will be on least substituted side + hydrogen will go on most substituted side

    • syn addition will occur (anti mark. product)

    • can be favorable since rearrangements won’t occur

  • OH group will replace B which will be the oxidation step

17
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acetylide ion

  • a terminal alkyne that has been deprotonated by a strong base

  • solvents: NaNH2, NH3 (l)

  • a good nucleophile that can react with primary or methyl halides

    • can get internal alkynes

    • another option to get from epoxide → alcohol (breaks open the epoxide ring)

  • DO NOT USE FOR SECONDARY BC E2 WILL OCCUR AND WE WANT SN2 REACTION

18
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preparation of alkynes

  • double elimination

    • vicinal/geminal dihalides + -NH2 (ex: NaNH2)

    • will go from alkane → alkene → alkyne

  • if making a terminal alkyne, need to have three steps (alkene → terminal alkyne)

    • Br2, 3 eq. -NH2, + H3O+/H2O

19
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addition of H-X to alkynes

  • solvents: H-X, CCl4 (carbon tetrachloride is just a solvent)

  • 1 eq. of H-X = alkene

  • 2 eq. of H-X = alkane

    • will create a geminal dihalide

  • a resonance structure can be made

20
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hydration of alkynes

  • solvents: H2O, H2SO4, HgSO4 (only add this if its a terminal alkyne bc it needs an extra catalyst)

  • an enol will be produced in middle of rxn (alkene and an alcohol)

  • tautomerization will occur once an enol is formed

    • alkyne → enol

    • enol + resonance structures → ketone

    • ketone + enols are tautomers

    • ketones will automatically form with acid + base present

  • markonikov’s rule applies → terminal and alkynes will produce ketones

  • regioselectivity: hydrogen is added to least substituted side

  • unsymmetrical alkynes will give a mixture of products (C=O can be on either side)

21
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bromine/chlorine + alkyne

  • solvents: Br2/Cl2, CCl4

  • 1 eq. = trans alkene

  • 2 eq. = tetra alkane

22
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hydroboration of alkynes

  • solvents: BH3, THF

    • use 9-BBN or (sia)2B-H if unsymmetrical or terminal alkynes

  • base catalyzed tautomerization will occur → need to use -OH and H2O2

    • terminal alkynes = aldehydes → anti-markonikov

    • internal alkynes = ketones

23
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catalytic hydrogenation

  • solvents: H2 + catalyst (Pd will be used on exams)

  • stereoselective: syn addition

  • only works for carbonyls (ketones and aldehydes)

24
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hydrogenation of other double bonds

  • solvents: LiAlH4

25
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full hydrogenation of alkynes (reduction)

  • solvents: H2, Pd

    • 2 equiv. needed for full with catalyst

26
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partial hydrogenation of alkynes

  • for syn addition: use H2 + Lindlar’s catalyst

  • for anti addition: use Na + NH3(l)

27
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use of LiAlH4

  • SN2 reactions will occur

    • reagent will attack at least substituted side for epoxides

  • solvents: LiAl4 + H2O

  • good for unhindered primary and methyl substrates

    • good for epoxides → another method to use to get an alcohol from epxoides

    • can work for alkyl halides

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