EDEXCEL GCSE MATHEMATICS

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310 Terms

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Finding the LCM of two numbers when you have the prime factors

  • List all the prime factors out

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  • If a factor appears more than once, list it that many times, e.g. 2, 2, 2, 3, 4 and 2, 2, 3, 4 would be 2, 2, 2, 3, 4

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  • Multiply these together to get the LCM

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Finding the HCF of two numbers when you have the prime factors

  • List all the prime factors that appear in both numbers

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  • Multiply these together

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Multiplying fractions

Multiply the top and bottom separately

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Dividing fractions

Turn the second fraction upside down then multiply

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Rule for terminating and recurring decimals

If the denominator has prime factors of only 2 or 5, it is a terminal decimal

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Turning a recurring decimal into a fraction

  • Name the decimal with an algebraic letter

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  • Multiply by a power of ten to get the one loop of repeated numbers past the decimal point

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  • Subtract the larger value from the single value to get an integer

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  • Rearrange

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  • Simplify

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Turning a recurring fraction into a decimal when the recurring decimal is not immediately after the decimal, e.g. r = 0.16666...

  • Name the decimal with an algebraic letter e.g. r = 0.16666...

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  • Multiply by a power of ten to get the non-repeating part out of the bracket e.g. 10r = 1.6666...

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  • Multiply to get the repeating part out of the bracket e.g. 100r = 16.6666...

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  • Take away the larger value from the smaller one (to get an integer) e.g. 100r - 10r = 90r = 15

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r = 15/90

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  • Simplify e.g. 15/90 = 1/6

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Turning a fraction into a decimal

  • Make the fraction have all nines at the bottom

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  • The number on the top is the recurring part, the number of nines is the number of recurring decimals there are

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Significant figures

The first number which isn't a zero. This is rounded.

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Rules for calculating with significant digits

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Estimating square roots

  • Find two numbers either side of the number in the root

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  • Make a sensible estimate depending on which one it is closer to

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Truncated units

When a measurement is truncated, the actual measurement can be up to a whole unit bigger but no smaller, e.g. 2.4 truncated to 1 d.p. is 2.4 ≤ x < 2.5

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Multiplying and dividing standard form

  • Convert both numbers to standard form

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  • Separate the power of ten and the other number

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  • Do each calculation separately

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Adding and subtracting standard form

  • Convert both numbers into standard form

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  • Make both powers of 10 the same in each bracket

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  • Add the two numbers and multiply by whatever power of ten; they are to the same power so this can be done

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Negative powers

1 over whatever the number to the power was, e.g.

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7⁻² = 1 / 7² = 1 / 49

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a⁻⁴ = 1 / a⁴

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If the number is a fraction, then it is swapped around, e.g.

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(3/5)⁻² = (5/3)² = 25 / 9

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Fractional powers

Something to the power of 1/2 means square root

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Something to the power of 1/3 means cube root

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Something to the power of 1/4 means fourth root, e.g.

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25^½ = √25 = 5

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Two-stage fractional powers

When there is a fraction with a numerator higher than one, spilt it into a fraction and a power and do the root first, then power, e.g.

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64^5/6 = (64^1/6)⁵ = (2)⁵ = 32

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Difference between two squares

a²-b²=(a+b)(a-b)

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Simplifying surds

Split the number in the root into a square number and the lowest other number possible, e.g.

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√250 = √(25 × 10) = 5√10

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Rationalising the denominator

This is done to get rid of a surd on the denominator. You multiply by the same fraction of the surd, but with the operation the other way round.

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Removing fractions when they (the fractions) appear on both sides of an equation

  • Multiply by the lowest common multiple of both numbers

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  • Simplify

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Quadratic formula

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Completing the square

  • Write out in the form ax²+bx+c

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  • Write out the first bracket in the form

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(x + b/2)²

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  • Multiply out the brackets and add or subtract to make the number outside the bracket match the original

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Completing the square when 'a' isn't one

  • Factorise with the 'a' value outside the brackets

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  • Write out in the form a(x+b/2)

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  • Add or subtract the remaining number

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Facts about completing the square

For a positive quadratic,

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  • The number outside the bracket is the y value of a graph

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  • The number inside the bracket is the x value multiplied by -1

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Adding and subtracting algebraic fractions

  • Make both denominators equal by multiplying the numerators by the other denominator

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  • Simplify

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Finding the nth term of quadratic sequence

  • Find the difference between the difference in each term (this can be called a second difference)

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  • Divide the second difference by two to get the coefficient of the n² term

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  • Take away the n² term from the original sequence to get a linear sequence, which can be easily worked out

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Algebra with inequalities exception

Whenever you multiply or divide by a negative number, flip the inequality sign round

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Inequalities on number lines

  • Open circles for < or >

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  • Closed circles for ≤ or ≥

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Quadratic inequalities general rule

  • If x² > a² then x > a or x < -a

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  • If x² < a² then -a < x < a

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(this is because with a square root the number can be positive or negative, and the negative would mean flipping the sign)

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Drawing quadratic inequalities

  • Factorise the equation when it equals zero to find the x intercepts

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  • Sketch the graph, paying attention to if the x² coefficient is positive or negative

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  • Solve the equation using the graph, paying attention to whether the original equation is a < or > (or a ≥ or ≤)

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  • If the equation asks for x > 0, then solve it for where the quadratic is above the x-axis. On a negative graph, this will give the results as -a < x < b, and on a positive graph it will result in x < -a and x > b

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  • If the equation asks for x < 0, then solve it for when the quadratic is below the x-axis. On a negative graph, the results will be x < -a or x > b, and on a positive graph it would be -a < x < b

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  • In the picture, the equation is x² - x - 2, as the x intercepts are -1 and 2. The answer to x² - x - 2 > 0 would be x < -1 and x > 2

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  • If the inequality has a ≤ or ≥ then the final answer has to include a ≤ or ≥ for both roots

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Showing an inequality on a graph

  • Convert the inequality into an equation

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  • Draw the graph for the equation

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  • Work out which side of the line you want and shade the region which it satisfies (it usually asks in the question)

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  • If the inequality has a < or >, then draw a dotted line

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  • If the inequality has a ≤ or ≥, then draw a solid line

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Composite functions (e.g. fg(x))

  • Always do the function close to x first, e.g. fg(x) would be f(g(x))

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Inverse functions (written as f⁻¹(x))

  • Write out the equation as x = f(y)