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equilibrium
when the rate of the reactants equals the rate of the products (NOT THE CONCENTRATION)
What is used to denote that an equilibrium reaction is occurring in both directions?
double arrow
equation for the equilibrium constant for the reaction aA → ← bB
K = [B]b/[A]a
law of mass action
regardless of the initial concentrations, at equilibrium, the ratio of concentrations raised to the appropriate powers will always equal K
What does the value of K depend on?
specific chemical equations
temperature
What does the value of K not depend on?
concentration
particle size
catalyst
heterogenous equilibria
equilibria that include species of different phases
equilibrium constant expression doesn’t include solids or pure liquids
only gas and aqueous species have concentrations that can change and are included in the equilibrium constant expression
What does the value of K for a reaction give quantitative information about?
the extent of the reaction
When are forward and reverse reactions equally favored?
when the concentration of reactants and products are almost equal at equilibrium
K is about 1
When is the forward reaction favored?
when the concentration of reactants is less than the concentration of products at equilibrium
K is less than 1
When is the reverse reaction favored?
when the concentration of the reactants is more than the concentration of products at equilibrium
K is more than 1
equilibrium constant in terms of concentration (aA + bB → ← cC + dD)
Kc = [C]c[D]d/[A]a[B]b
equilibrium constant in terms of partial pressure (aA (g) + bB (g) → ← cC (g) + dD (g))
Kp = (PC)c(PD)d / (PA)a(PB)b
Kc in terms of KP
Kc = KP (1/RT)(c+d) - (a+b)
KP in terms of Kc
KP = Kc (RT)delta n
What is delta n equal to?
(c+d) - (a+b)
What is the equilibrium constant of the overall equation when 2 or more equations are added together?
it’s the product of the equilibrium constants of the individual equations
Koverall = K1 x K2
What happens to the equilibrium constant when the coefficients of a reaction are multiplied by a factor?
the equilibrium constant is raised to the power of the same factor
What does the reverse equation yield?
the inverse (reciprocal) equilibrium constant
What does a large K value represent?
equilibrium is shifted right
there are more products
What does a small K value represent?
equilibrium is shifted left
there are more reactants
When does the K not apply?
when the system is not at equilibrium
reaction quotient (Q)
can be determined using the same ratio as K, but using concentrations or partial pressures when the system is NOT at equilibrium
reaction quotient in terms of concentration
Qc = [C]c[D]d/[A]a[B]b
reaction quotient in terms of partial pressure
Qp = (PC)c(PD)d / (PA)a(PB)b
What does it mean when Q = K?
the reaction is at equilibrium
no shift
What does it mean when Q > K?
more products must be formed to achieve equilibrium
shifts left
What does is mean when Q < K?
more reactants must be formed to achieve equilibrium
shifts right
What can you use to determine the equilibrium constant?
ICE table
Le Chatelier’s Principles
if stress is applied to a system at equilibrium, the reaction will shift to relieve stress
stress
change of conditions imposed on the system (i.e change in concentration or pressure on reactants or products, change in temperature of the system)
shift
net forward reaction of reactants to form products
net reverse reaction of products to form reactants
When delta n < 0, an increase in volume
causes a shift left
When delta n < 0, a decrease in volume
causes a shift right
When delta n =0, an increase or decrease in volume
causes no change
When delta n > 0, an increase in volume
causes a shift right
When delta n > 0, a decrease in volume
causes a shift left
In endothermic reactions, how are K and T related?
directly related
In exothermic reactions, how are K and T related?
inversely related
equation that shows relationship between K and T
ln K2/K1 = deltar H/R (1/T1 - 1/T2)
Does a catalyst affect the equilibrium constant?
no, it simply lowers the activation energy of both forward and reverse reactions
equilibrium is established quicker, but position remains unchanged