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acceleration
change in velocity, either in its magnitude or in its direction, or both
UCM direction of velocity…
changes constantly, so there is always an associated acceleration even though the mag of the velocity might be constant
sideways acceleration in a car
holding wheel steady during a turn and move at a constant speed
Centripetal Acceleration
points directly toward the center of rotation (the center of the circular path)
Centripetal
toward the center or center seeking
Triangle formed by…
by the velocity vectors and the one formed by the radii r and Δs are similar
Triangles ABC and PQR
isosceles triangles (two equal sides)
Two equal sides of the velocity vector triangle are
the speeds v1=v2=v
Ac formula
V²/r and rw²
Centripetal Acceleration is greater at
at high speeds and in sharp curves (smaller radius), a sharp corner has a small radius, so that ac is greater for tighter turns
Centrifuge
rotating device used to separate specimens of different densities
High centripetal acceleration significantly decreases…
the time it takes for separation to occur, and makes separation possible with small samples
Applications of Centrifuges
science and medicine- single cell suspensions (bacteria, viruses, and blood cells from a liquid medium) and macromolecules- DNA and protein from a solution
Centrifuges are often rated in terms of their
centripetal acceleration relative to acceleration due to gravity (g)
Maximum centripetal acceleration
of several hundred thousand g is possible in a vacuum.
Human centrifuges (extremely large centrifuges)
have been used to test the tolerance of astronauts to the effects of accelerations larger than that of Earth’s gravity.
Net external force is needed to cause
any acceleration (N2L), so it is needed to cause a centripetal acceleration
Any force or combination of forces
can cause a centripetal or radical acceleration
Centripetal force
Any net force causing uniform circular motion, direction is toward center of curvature, same direction as the direction of centripetal acceleration
Fc=mac
magnitude of centripetal force
acceleration ac from ac=v2r;ac=rω2, we get two expressions for the centripetal force Fc in terms of mass, velocity, angular velocity, and radius of curvature:
Fc=mv²/r; Fc=mrω²
Centripetal force Fc is always perpendicular
to the path and pointing to the center of curvature, because ac is perpendicular to the velocity and pointing to the center of curvature
r=mv²/Fc.
implies that for a given mass and velocity, a large centripetal force causes a small radius of curvature—that is, a tight curv
banked curves
where the slope of the road helps you negotiate the curve, the greater the angle θ, the faster you can take the curve
ideally banked curves
the angle θ is such that you can negotiate the curve at a certain speed without the aid of friction between the tires and the road
ideal banking
the net external force equals the horizontal centripetal force in the absence of friction.
The components of the normal force N in the horizontal and vertical directions must equal
the centripetal force and the weight of the car, respectively
If the angle θ is ideal for the speed and radius, then
the net external force will equal the necessary centripetal force
weight of car and normal force of road must add to give a net external force
that is horizontal toward the center of curvature and has magnitude mv²/t, crucial force and horizontal- must use vertical and horizontal axes
Because the car does not leave the surface of the road, the net vertical force must be zero,
meaning that the vertical components of the two external forces must be equal in magnitude and opposite in direction
A large θ will be obtained
for a large v and a small r, roads must be steeply banked for high speeds and sharp curves
Note that θ does not depend
on the mass of the vehicle
Friction helps, because it allows you to take the curve at
greater or lower speed than if the curve is frictionless