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What is a linear transformation?
Let V and W be vector spaces over the same field (always R unless otherwise specified). A function T : V → W is called a linear transformation iff:
T(u + v) = T(u) + T(v) for all vectors u, v in V
T(λv) = λT(v) for all vectors v in V and all scalars λ
Equivalently, T : V → W is called a linear transformation iff:
T(u + λv) = T(u) + λT(v) for all vectors u, v in V and all scalars λ
V is allowed to equal W
What is the zero transformation?
O(v) = 0
What is the identity transformation?
Iv(v) = v
What are some properties of linear transformations T : V → W?
T(0v) = 0w
T(-v) = -T(v) for all v in V
T(λ1v1 + … + λkvk) = λ1T(v1) + … + λkT(vk) for all vectors v1, …, vk in V and scalars λ1, …, λk
If V is n-dimensional with a basis B = {b1, …, bn} and there are 2 linear transformations T1 : V → W and T2 : V → W such that T1(bi) = T2(bi) for i = 1, 2, …, n then,…
T1 = T2. Moreover, for any vectors w1, …, wn in W, there exists a unique linear transformation T : V → W such that T(bi) = Wi for all i = 1, 2, …, n
What is a composition?
Let T : U → V and S : V → W be linear transformations. Then the composition S ∘ T : U → W is the function (S ∘ T)(u) = S(T(u)) for all u in U
Prove this theorem: ‘Let T : U → V and S : V → W be linear transformations. Then the composition S ∘ T : U → W is a linear transformation.’
Take u1, u2 in U and scalar λ
(S ∘ T)(λu) = S(T(λu))
= S(λT(u))
= λS(T(u)) because S is a linear transformation
= λ(S ∘ T)(u)
So both criteria are satisfied, therefore S ∘ T is a linear transformation
What is the image?
Let T : V → W be a linear transformation. Then the image of T is the set of all possible outputs in W:
im(T) = {T(v) ∈ W : v ∈ V}
What is the kernel?
The kernel of T is the set of everything in V that gets mapped to 0w:
ker(T) = {v ∈ V : T(v) = 0w}
Prove this theorem: ‘Let T : V → W be a linear transformation. Then im(T) \< W and ker(T) \< V’
Take w1, w2 ∈ im(T)
Take scalar λ
We want w1 + λw2 ∈ im(T)
We know there exists v1, v2 ∈ V such that T(v1) = w1 and T(v2) = w2
Consider T(v1 + λv2) = T(v1) + λT(v2) = w1 + λw2
Since v1 + λv2 ∈ V, we’ve found a preimage of w1 + λw2 under T
Therefore, w1 + λw2 ∈ im(T)
Take v1, v2 ∈ ker(T) and scalar λ
We have T(v1 + λv2) = T(v1) + λT(v2) = 0 + 0λ = 0
Therefore v1 + λv2 ∈ ker(T)
Im(T) and ker(T) are both non-empty since T(0v) = 0w so 0w ∈ im(T), 0v ∈ ker(T)
What is the rank-nullity theorem?
Let T : V → W be a linear transformation. Then, dim(im(T)) + dim(ker(T)) = dim(V) (dim(im(T)) = rank of T, dim(ker(T)) = nullity of T)