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a cell is at equilibirum potential when:
delta G = 0
Nernst Equation
van’t Hoff’s equation with membrane potential taken into account
i. deltaG = RTln(S outside/S inside) + zFE
in the Nerst equation, z is equal to:
an ion’s valence
in the Nerst equation, F is equal to:
the faraday constant
in the Nernst equation, E is equal to:
membrane potential
the Nerst equation can be rearranged to solve for E, which looks like:
1. E ion = (61mV/z) x log([s]outside/[s]inside)
The equilibrium potential for potassium is -94mV. This means that:
when the inside of the cell is -94mV, it will arrest movement of potassium. deltaG=0
what else must we take into account when evaluating diffusion of a substance through a membrane?
resting membrane potential/permeability differences between ions
Goldman H K equation normalized the Nernst equation based on the permeabilities of both ions:
a. The 0.04 accounts for potassium being 25x more permeable than sodium (1/25)
b. Vm = 61log (PNa[Na]o) + (PK[K]o) / (PNa[Na]i) + (PK[K]i)
c. Vm = 61log (0.04)(145mM) + (1)(4mM) / (0.04)(15mM) + (1)(140mM)
d. Vm = -70.6mV
i. It will favor potassium because potassium is more permeable