Combined Gas Laws and Properties of Gases

0.0(0)
studied byStudied by 0 people
0.0(0)
full-widthCall Kai
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
GameKnowt Play
Card Sorting

1/40

flashcard set

Earn XP

Description and Tags

A set of 41 flashcards covering key concepts and formulas related to gas laws, properties of gases, and colligative properties.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

41 Terms

1
New cards

Combined Gas Law

P1V1/T1 = P2V2/T2, relates pressure, volume, and temperature for a fixed amount of gas.

2
New cards

Molar Volume at STP

22.4 L/mol for an ideal gas.

3
New cards

STP Definition

Standard Temperature and Pressure: 1 atm and 273 K.

4
New cards

Ideal Gas Law

PV = nRT; R = 0.0821 L·atm·mol^-1·K^-1.

5
New cards

Effect of doubled P and T

Volume (V) remains unchanged.

6
New cards

Variable 'n' in PV = nRT

Number of moles of gas.

7
New cards

Effect of halving V on P

Pressure (P) doubles if temperature (T) and moles (n) are constant (Boyle's Law).

8
New cards

Effect of doubled T on V

Volume (V) doubles if pressure (P) and moles (n) are constant (Charles' Law).

9
New cards

Average Kinetic Energy and Temperature

Directly proportional to absolute temperature (Kelvin).

10
New cards

Elastic Collision Definition

A collision with no net loss of kinetic energy.

11
New cards

Heat Equation

q = m·c·ΔT; where m is mass (g), c is specific heat (J/g·°C), and ΔT is temperature change.

12
New cards

Heat of Fusion Formula

q = m·Hf; calculates heat required to melt or freeze a substance.

13
New cards

Heat of Vaporization Formula

q = m·Hv; calculates heat required to boil or condense a substance.

14
New cards

Gas Density Formula

D = PM/RT; relates density to pressure, molar mass, gas constant, and temperature.

15
New cards

Effect of Increasing T on P at Constant Volume

Increases pressure (P); directly proportional.

16
New cards

Definition of % (w/v)

grams of solute per 100 mL of solution × 100%.

17
New cards

Definition of % (w/w)

grams of solute per 100 g of solution × 100%.

18
New cards

Definition of % (v/v)

mL of solute per 100 mL of solution × 100%.

19
New cards

Molarity Definition

M = moles of solute / liters of solution.

20
New cards

Dilution Equation

M1V1 = M2V2; relates concentrations and volumes before and after dilution.

21
New cards

Temperature Effect on Solubility of Solids

Solubility increases with temperature.

22
New cards

Temperature Effect on Solubility of Gases

Solubility decreases with temperature.

23
New cards

Henry's Law

Higher pressure increases gas solubility in liquids.

24
New cards

Electrolyte Definition

A substance that forms ions in water; e.g., NaCl.

25
New cards

Strong vs Weak Electrolyte

Strong electrolytes dissociate nearly completely; weak electrolytes only partially dissociate.

26
New cards

Direction of Osmosis

Solvent moves from lower solute concentration to higher solute concentration.

27
New cards

Osmolarity (Osm) Definition

Osm = (number of ions, n) × molarity M.

28
New cards

Osmotic Pressure Formula

π = n·M·R·T; relates osmotic pressure to number of moles, molarity, gas constant, and temperature.

29
New cards

Hypertonic vs Hypotonic vs Isotonic

Hypertonic: higher solute concentration; Hypotonic: lower solute concentration; Isotonic: equal solute concentrations.

30
New cards

Boiling Point Elevation Formula (Water)

ΔTb = n·Kb·M; Kb = 0.52 °C·kg·mol^-1.

31
New cards

Freezing Point Depression Formula (Water)

ΔTf = n·Kf·M; Kf = 1.86 °C·kg·mol^-1.

32
New cards

Liters Occupied by 2.00 mol of Ideal Gas at STP

44.8 L.

33
New cards

Liters of H2O Formed from 10.0 L H2

10.0 L H2O produced from reaction with O2.

34
New cards

Using PV = nRT to Solve for n (Moles)

n = PV / RT.

35
New cards

Moles from Molarity and Volume

n = M·V; where M is molarity and V is volume in liters.

36
New cards

Van't Hoff Factor for NaCl in Colligative Properties

n = 2; NaCl dissociates into two ions.

37
New cards

Heat (q) for 50.0 g Water

q = m·c·ΔT; results in 5230 J.

38
New cards

Grams of CO2 in 11.2 L at STP

22.0 g of CO2.

39
New cards

Heat (q) for 50.0 g Water with Temperature Change

q = 523 J; results in 5230 J.

40
New cards

Boiling Point Elevation for 0.50 M NaCl (n=2)

ΔTb = 0.52 °C.

41
New cards

Freezing Point Depression for 0.50 M NaCl (n=2)

ΔTf = 1.86 °C.