Pericyclic Reactions

0.0(0)
learnLearn
examPractice Test
spaced repetitionSpaced Repetition
heart puzzleMatch
flashcardsFlashcards
Card Sorting

1/29

encourage image

There's no tags or description

Looks like no tags are added yet.

Study Analytics
Name
Mastery
Learn
Test
Matching
Spaced

No study sessions yet.

30 Terms

1
New cards

How does your very generalized Diels-Alder reaction look like?

knowt flashcard image
2
New cards

For a Diels-Alder (DA) reaction, what moiety do we need attached to the diene and what moiety do we need attached to the dienophile? Why for both cases?

  • The diene must have electron-donating groups because it raises the energy of the molecular orbitals, specifically the HOMO, because of its increasing repulsion via donation of electrons.

  • The dienophile should have electron-withdrawing groups because it lowers the energy of the molecular orbitals, specifically the LUMO, because its decreasing repulsion via withdrawal of electrons.

  • This raising of MOs from diene and lowering of MOs from dienophile provide better energy overlap and efficient bonding.

3
New cards

What should you remember, regioselectively, in regards to bonding in DA?

The delta positive of the dienophile and delta negative of the diene or full positive of the dienophile and full negative of the diene have to match.

4
New cards

What should you remember, stereochemically, without an Evans aux., in regards to bonding in DA?

Endo is always preferred over exo.

5
New cards

When there is an “outer” R on C1 of butadiene, what’s the Krel if R was CH3, or C(CH3)3, with R as H as a reference point for Krel, where Krel = 1? What explains these relative values?

  • If R was CH3, K would be 4.2 because of electron-donation.

  • If R was a t-butyl group, K would be 0.05 because of steric hinderance, i.e. less trajectories to attack.

6
New cards

When there is an “inner” R on C1 of butadiene, what’s the Krel if R was CH3, with R as H as a reference point for Krel, where Krel = 1? What explains this relative values?

If R = Me, then K would 1E-3 because of allylic strain that forces the butadiene to go cis instead of trans. If it goes trans, then the reaction can’t proceed because we need cis conformation.

7
New cards

When there is an R on C2 of butadiene, what’s the Krel if R was t-butyl, with R as H as a reference point for Krel, where Krel = 1? What explains this relative values?

If R was t-Butyl, then K would be 27 because of electron donation.

8
New cards

How do Lewis acids assist in the catalysis of DA reactions?

You would form a full positive charge on the dienophile, which lowers the energy of the LUMO for efficient bonding. Also makes the positively-charged resonance structure more pronounced as a call for bonding at its electrophilic carbon.

Generally, uncatalyzed results in 70% yield at 200ÂșC for 6 weeks, while catalyzed results in 95% yield at -78ÂșC for 10 seconds.

9
New cards

What are some useful DA products for synthetic utility?

  • Danishefsky and Rawal’s product.

  • “Walsh’s product.”

  • “Sorensen’s product.”

  • “Davis’ product.”

  • Ketene equivalent product.

  • Ethene equivalent product.

  • Acetylene equivalent product.

  • Wittig product.

10
New cards

How do you synthesize Danishefsky and Rawal’s product?

knowt flashcard image
11
New cards

How do you synthesize Walsh’s product?

knowt flashcard image
12
New cards

How do you synthesize Sorensen’s product?

knowt flashcard image
13
New cards

How do you synthesize Davis’ product?

knowt flashcard image
14
New cards

How do you synthesize the ketene equivalent product?

knowt flashcard image
15
New cards

How do you synthesize the ethene equivalent product?

knowt flashcard image
16
New cards

How do you synthesize the acetylene equivalent product?

knowt flashcard image
17
New cards

How do you synthesize the Wittig product?

knowt flashcard image
18
New cards

How do you ensure stereochemistry of DA products?

Use Evans aux. and Lewis acids on the dienophile. The Lewis acids will activate the dienophile and make the whole dienophile as planar as possible to understand diene attack, a la re/si model, increasing endo selectivity further as well due to the cyclic lock, and endo 1 vs. endo 1 selectivity.

19
New cards

If you wanted to attach to molecules together like lego pieces, how would you proceed?

knowt flashcard image
20
New cards

What are the five discussed 3,3-sigmatropic rearrangements in lecture?

  • Cope.

  • Oxy-cope.

  • Anionic oxy-cope.

  • Claisen.

  • Claisen of allyl phenyl ethers.

21
New cards

How does the cope rearrangement work?

knowt flashcard image
22
New cards

How does the oxy-cope rearrangement work?

knowt flashcard image
23
New cards

How does the anionic oxy-cope rearrangement work?

knowt flashcard image
24
New cards

How does the cope and oxy-cope rearrangement explain the super-efficiency of the anionic oxy-cope rearrangement?

  • Cope rearrangement: Synthetically useless - same product as reactant. Uses a lot of energy 300ÂșC. In equilibrium too.

  • Oxy-cope rearrangement: Still not the best synthetically. Does give you keto product via taut with no full return to alcohol. In equilibrium regardless. Still needs energy - 175ÂșC.

  • Anionic oxy-cope rearrangement. The best synthetically here. The creation of the intermediate with a resonance-stabilized enolate is downhill in energy and more stable than the starting material, compared to the “downhill” in energy with the oxy-cope where there is no stabilization. Anionic is so stable to the point that it wouldn't be in equilibrium or want to return to non-resonance-stabilized-enolate form. Can taut. into keto once treated with proton source.

<ul><li><p>Cope rearrangement: Synthetically useless - same product as reactant. Uses a lot of energy 300ÂșC. In equilibrium too.</p></li><li><p>Oxy-cope rearrangement: Still not the best synthetically. Does give you keto product via taut with no full return to alcohol.&nbsp;In equilibrium regardless. Still needs energy - 175ÂșC.</p></li><li><p>Anionic oxy-cope rearrangement. The best synthetically here. The creation of the intermediate with a resonance-stabilized enolate is downhill in energy and more stable than the starting material, compared to the “downhill” in energy with the oxy-cope where there is no stabilization. Anionic is so stable to the point that it wouldn't be in equilibrium or want to return to non-resonance-stabilized-enolate form. Can taut. into keto once treated with proton source.</p></li></ul><p></p>
25
New cards

How does the Claisen rearrangement work?

knowt flashcard image
26
New cards

How does the Claisen of allyl phenyl ethers rearrangement work?

knowt flashcard image
27
New cards

How does cheletropic elimination work?

knowt flashcard image
28
New cards

Why is the cheletropic elimination of SO2 beneficial for Diels-Alder reactions?

The generation of the cis diene is slower than Diels-Alder reactions, allowing Diels-Alder to occur with such dienes produced.

29
New cards

Does the reaction for rearrangement of phenyl ethers favour the enol form over the keto form? If so, why?

Phenol prefers enol form over keto form because of aromaticity.

30
New cards

What are the Woodward-Hoffman rules? What explains these rules?

  • 4n / ∆ / con

  • 4n+2 / ∆ / dis

  • 4n+2 / hv / con

  • 4n / hv / dis

Electrocyclic reactions occur at the highest occupied MO. Using heat, the HOMO is used as the orbitals in rotations. Using light, the electron is excited to the LUMO, which is now the SOMO (singly-occupied molecular orbital), and our new highest MO is the SOMO for orbital rotations.