ME 240: Final Review (Hopefully)

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59 Terms

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Specifications of Metals

Strong, Ductile, High Thermal and Electrical Conductivity, Opaque, Reflective

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Specifications of Semiconductors

Covalent bonding (share electrons), depends on contaminants

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Specifications of Polymers/plastics

Covalent bonding, Soft, Ductile, low strength, low density, thermal and electrical insulators, optically translucent or transparent

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Specifications of Ceramics

Ionic bonding, brittle, glassy, elastic, non-conducting

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Electron Configuration for Carbon (6)

1s²2s²2p²

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Electron Configuration for Neon (10)

1s²2s²2p^6

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Electron Configuration for Aluminum (13)

1s²2s²2p^6 3s²3p^1

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Electron Configuration for Argon (18)

1s²2s²2p^6 3s²3p^6

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Specifications of Ionic bonding

Pos. and Neg. ions naturally attract each other, Non-directional, Pos. Valence Electrons must have Neg. Valence Electrons, Strong Resistance to mechanical force and experiences plastic deformation

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Specifications of Covalent Bonding

Equal sharing of valence electrons, directional bonds, strength of covalent bonds varies widely, backbone of polymer chains, hard and brittle.

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Specifications of Metallic Bonding

Valence electrons detach from atoms and spread, non-directional, very good conductors of electricity and heat

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Specifications of Secondary Bonding

Between Dipoles

<p>Between Dipoles</p>
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Iron has a BCC crystal structure, an atomic radius of 0.124 nm, and an atomic weight of 55.85 g/mol. Compute and compare its theoretical density with the experimental value (7.87 g/cm³)

7.90 g/cm³

<p>7.90 g/cm³</p>
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<p>Determine whether its crystal structure is FCC, BCC, or simple cubic, and then justify your<br>determination.</p>

Determine whether its crystal structure is FCC, BCC, or simple cubic, and then justify your
determination.

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List the point coordinates for all atoms associated with the FCC unit cell

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<p><span>Determine the indices for the directions shown in the following cubic unit cell</span></p>

Determine the indices for the directions shown in the following cubic unit cell

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<p><span>Determine the Miller indices for plane B only</span></p>

Determine the Miller indices for plane B only

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<p>Calculate the diffusion coefficient at 1250 C if you are given the following information</p>

Calculate the diffusion coefficient at 1250 C if you are given the following information

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<p>For a bronze alloy, the stress at which plastic deformation begins is 275 MPa (40,000 psi), and the modulus of elasticity is 115 GPa (16.7 × 106 psi).</p><p><span>(a) What is the maximum load that may be applied to a specimen with a cross-sectional area of 325 mm<sup>2</sup> (0.5 in.<sup>2</sup> ) without plastic deformation?</span></p>

For a bronze alloy, the stress at which plastic deformation begins is 275 MPa (40,000 psi), and the modulus of elasticity is 115 GPa (16.7 × 106 psi).

(a) What is the maximum load that may be applied to a specimen with a cross-sectional area of 325 mm2 (0.5 in.2 ) without plastic deformation?

89,375 N

<p>89,375 N</p>
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<p>For a bronze alloy, the stress at which plastic deformation begins is 275 MPa (40,000 psi), and the modulus of elasticity is 115 GPa (16.7 × 106 psi).</p><p>(b) If the original specimen length is 115 mm (4.5 in.), what is the maximum length to which it may be stretched without causing plastic deformation?</p>

For a bronze alloy, the stress at which plastic deformation begins is 275 MPa (40,000 psi), and the modulus of elasticity is 115 GPa (16.7 × 106 psi).

(b) If the original specimen length is 115 mm (4.5 in.), what is the maximum length to which it may be stretched without causing plastic deformation?

115.28 mm

<p>115.28 mm</p>
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<p><span>A cylindrical rod 100 mm long and having a diameter of 10.0 mm is to be deformed using a tensile load of 27,500 N. It must not experience either plastic deformation or a diameter reduction of more than 7.5 × 10-3 mm. Of the materials listed as follows, which are possible candidates? Justify your choice(s).</span></p>

A cylindrical rod 100 mm long and having a diameter of 10.0 mm is to be deformed using a tensile load of 27,500 N. It must not experience either plastic deformation or a diameter reduction of more than 7.5 × 10-3 mm. Of the materials listed as follows, which are possible candidates? Justify your choice(s).

<p></p>
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<p><span>A cylindrical 1040 steel rod having a minimum tensile strength of 865 MPa (125,000 psi), a ductility of at least 10%EL, and a final diameter of 6.0 mm (0.25 in.) is desired. Some 7.94 mm (0.313 in.) diameter 1040 steel stock, which has been cold worked 20% is available. Describe the procedure you would follow to obtain this material. Assume that 1040 steel experiences cracking at 40%CW.</span></p>

A cylindrical 1040 steel rod having a minimum tensile strength of 865 MPa (125,000 psi), a ductility of at least 10%EL, and a final diameter of 6.0 mm (0.25 in.) is desired. Some 7.94 mm (0.313 in.) diameter 1040 steel stock, which has been cold worked 20% is available. Describe the procedure you would follow to obtain this material. Assume that 1040 steel experiences cracking at 40%CW.

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<p>Consider an 18-8 Mo stainless steel component (Figure 8.35) that is exposed to a temperature of 500°C (773 K). What is the maximum allowable stress level for a rupture lifetime of </p><p>a) 5 years</p>

Consider an 18-8 Mo stainless steel component (Figure 8.35) that is exposed to a temperature of 500°C (773 K). What is the maximum allowable stress level for a rupture lifetime of

a) 5 years

260 MPa

<p>260 MPa</p>
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<p>Consider an 19-8 Mo stainless steel component that is exposed to a temperature of 773K. What is the maximum allowable stress level for a rupture lifetime of</p><p>b) 20 years </p>

Consider an 19-8 Mo stainless steel component that is exposed to a temperature of 773K. What is the maximum allowable stress level for a rupture lifetime of

b) 20 years

225 MPa

<p>225 MPa</p>
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Explain Ductility

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Explain Toughness

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Explain Hardness

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Explain True Stress and Strain

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Explain three Strategies for strengthening

Strengthening by grain size reduction, Solid-Solution, Strain hardening

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Explain Ductile to Brittle Transition Temperature

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Explain three stages of creep

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<p>Consider 2.5 kg of austenite containing 0.65 wt% C, cooled to below 727°C (1341°F).</p><p>(a) What is the proeutectoid phase?</p>

Consider 2.5 kg of austenite containing 0.65 wt% C, cooled to below 727°C (1341°F).

(a) What is the proeutectoid phase?

Ferrite

<p>Ferrite</p>
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<p>Consider 2.5 kg of austenite containing 0.65 wt% C, cooled to below 727°C (1341°F).</p><p>(b) How many kilograms each of total ferrite and cementite form?</p>

Consider 2.5 kg of austenite containing 0.65 wt% C, cooled to below 727°C (1341°F).

(b) How many kilograms each of total ferrite and cementite form?

2.27 kg of Ferrite, 0.23 kg of total cementite

<p>2.27 kg of Ferrite, 0.23 kg of total cementite</p>
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<p>Consider 2.5 kg of austenite containing 0.65 wt% C, cooled to below 727°C (1341°F).</p><p>(c) How many kilograms each of pearlite and the proeutectoid phase form?</p>

Consider 2.5 kg of austenite containing 0.65 wt% C, cooled to below 727°C (1341°F).

(c) How many kilograms each of pearlite and the proeutectoid phase form?

2.12 kg of pearlite, 0.38 kg of proeutectoid ferrite

<p>2.12 kg of pearlite, 0.38 kg of proeutectoid ferrite</p>
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<p><span>A copper-nickel alloy of composition 70 wt% Ni-30 wt% Cu is slowly heated from a temperature of 1300°C (2370°F).</span></p><p><span>At what temperature does the first liquid phase form?</span></p>

A copper-nickel alloy of composition 70 wt% Ni-30 wt% Cu is slowly heated from a temperature of 1300°C (2370°F).

At what temperature does the first liquid phase form?

About 1345 C

<p>About 1345 C</p>
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<p><span>A copper-nickel alloy of composition 70 wt% Ni-30 wt% Cu is slowly heated from a temperature of 1300°C (2370°F).</span></p><p><span>What is the composition of the first liquid phase?</span></p>

A copper-nickel alloy of composition 70 wt% Ni-30 wt% Cu is slowly heated from a temperature of 1300°C (2370°F).

What is the composition of the first liquid phase?

59 wt% Ni

<p>59 wt% Ni</p>
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<p><span>A copper-nickel alloy of composition 70 wt% Ni-30 wt% Cu is slowly heated from a temperature of 1300°C (2370°F).</span></p><p><span>At what temperature does complete melting of the alloy occur?</span></p>

A copper-nickel alloy of composition 70 wt% Ni-30 wt% Cu is slowly heated from a temperature of 1300°C (2370°F).

At what temperature does complete melting of the alloy occur?

about 1380 C

<p>about 1380 C</p>
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<p>A copper-nickel alloy of composition 70 wt% Ni-30 wt% Cu is slowly heated from a temperature of 1300°C (2370°F).</p><p><span>What is the composition of the last solid remaining prior to complete melting?</span></p>

A copper-nickel alloy of composition 70 wt% Ni-30 wt% Cu is slowly heated from a temperature of 1300°C (2370°F).

What is the composition of the last solid remaining prior to complete melting?

about 79 wt% NI

<p>about 79 wt% NI</p>
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<p>For a 40 wt% Sn-60 wt% Pb alloy at 150 C, find the phases that are present</p>

For a 40 wt% Sn-60 wt% Pb alloy at 150 C, find the phases that are present

Pb & Sn

<p>Pb &amp; Sn</p>
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<p>For a 40 wt% Sn-60 wt% Pb alloy at 150 C, find the compositions of each existing phase</p>

For a 40 wt% Sn-60 wt% Pb alloy at 150 C, find the compositions of each existing phase

Alpha - 11 wt% Sn

Beta - 98 wt% Sn

<p>Alpha - 11 wt% Sn</p><p>Beta - 98 wt% Sn</p>
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<p>For a 40 wt% Sn-60 wt% Pb alloy at 150 C, find the relative (%) amount of each phase</p>

For a 40 wt% Sn-60 wt% Pb alloy at 150 C, find the relative (%) amount of each phase

Alpha - 0.66 wt% Sn

Beta - 0.33 wt% Sn

<p>Alpha - 0.66 wt% Sn</p><p>Beta - 0.33 wt% Sn</p>
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What are the three main components of whiteware ceramic such as porcelain?

Quartz, Clay, Flux

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Describe the role of Quartz in forming and firing procedures

Quartz acts as a filler material

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Describe the role of Clay in forming and firing procedures

Clay facilitates the forming operation and maintains shape of the piece.

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Describe the role of Flux in forming and firing procedures

Flux facilitates the formation of glass having a relatively low melting temperature.

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Name 3 glass forming fabrications methods

Pressing, Blowing, Fiber Drawing

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Explain the Pressing glass forming method

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Explain the Blowing glass forming method

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Explain the Fiber Drawing glass forming method

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<p>Draw the specific volume changes with temperature in crystalline materials versus amorphous glasses and explain with words the characteristics of each one </p>

Draw the specific volume changes with temperature in crystalline materials versus amorphous glasses and explain with words the characteristics of each one

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Explain the steps in the particulate forming fabrication method for ceramics

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What are the advantages of using ceramics for heat engine?

Run at higher temperature, Excellent Wear & Corrosion resistance, Low Frictional Losses, Ability to operate without a cooling system, low density

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What are the disadvantages of using ceramics for heat engine?

Brittle, Easy to have voids-weaken the engine, Difficult to machine

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Name 2 examples candidates for ceramics for heat engines

Si3N4, SiC, & ZrO2

<p>Si3N4, SiC, &amp; ZrO2</p>
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Draw the stress-strain graph for brittle, plastic, and elastomer polymers

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Explain fiber-reinforced Polymers

Fibers are very strong in tension, provide significant strength improvement to the composite

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Provide examples of fiber-reinforced polymers and properties

Fiber-glass - continuous glass filaments in a polymer mix

Glass Fibers: strength and stiffness

Polymer matrix: holds fibers in place, protects fiber surfaces, transfers load to fibers

<p>Fiber-glass - continuous glass filaments in a polymer mix</p><p>Glass Fibers: strength and stiffness</p><p>Polymer matrix: holds fibers in place, protects fiber surfaces, transfers load to fibers</p>
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term image

L = 1254 nm

r = 15.4 nm

<p>L = 1254 nm</p><p>r = 15.4 nm</p>
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