Session 1b: Electronic Principles and Capacitors

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10 Terms

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Capacitors

Are passive elements designed to store energy (charge) within its electric field

Used extensively in electronics, communications (tuning radio receivers), computers (dynamic memory elements), and power systems

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What does Capacitors Consist of ?

•of two conducting plates separated by an insulator or dielectric

oThe two plates may be aluminium foil, while the dielectric may be air, ceramic, paper, or mica

<p><span>•of two conducting plates separated by an insulator or dielectric</span></p><p><span style="font-family: &quot;Courier New&quot;;">o</span><span>The two plates may be aluminium foil, while the dielectric may be air, ceramic, paper, or mica</span></p>
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<p><span>Capacitors: Charge and Capacitance</span></p>

Capacitors: Charge and Capacitance

When a voltage source is connected to the capacitor, the source deposits a positive charge +q on one plate, and a negative charge -q on the second plate

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Capacitance

The ratio of charge on one plate of a capacitor to the voltage difference between the two plates

C=Q/V , and V=Q/C

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<p><span>Parallel plate capacitor: </span><span style="font-family: &quot;Cambria Math&quot;;">C=εA/d</span></p>

Parallel plate capacitor: C=εA/d

̶C is capacitance measured in Farads (F)

̶A is surface area (m^2)

̶d is distance between the conductors

̶ε is the permittivity constant of the dielectric material

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Typical capacitor values are in…

microfarad (μF), and picofarad (pF)

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Value should be chosen based on…

on the applications (decoupling, filtering, etc.) and tolerances needed

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Capacitors calculated in parallel. What is the Calculation?

C_T=C_1+C_2+C_3+…C_n

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<p><span>Capacitors calculated in series. What is the Calculation?</span></p>

Capacitors calculated in series. What is the Calculation?

1/C_T =1/C_1 +1/C_2 +1/C_3 +…1/C_n

OR 

C_Total=1/(1/C1+1/C2+1/C3+…1/Cn)

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•First, calculate the capacitance in series

o1/CT=1/(1×10^(-6) )+1/(5×10^(-6) )=1.2×10^6

̶CT_Series=1/(1.2×10^6 )=8.33×10^(-7)

̶CT_Series=0.833×10^(-6)

̶〖CT〗_Series=0.833 μF

•Next, calculate the capacitance in parallel

CT_Parallel=0.833 μF+8 μF

CT_Parallel=8.833 μF